a)\(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)

   \(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)

   \(2AlCl_3+3Ba\left(OH\right)_2\rightarrow2Al\left(OH\right)_3\downarrow+3BaCl_2\)

   \(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)

   \(2Al+3S\underrightarrow{t^o}Al_2S_3\)

1) Al\(_2\)(SO\(_4\))\(_3\)+3BaCl\(_2\)→2AlCl\(_3\)+3BaSO\(_4\)↓

2)AlCl\(_3\)+3AgNO\(_3\)→Al(NO\(_3\))\(_3\)+3AgCl↓

3)Al(NO\(_3\))\(_3\)+3NaOH→Al(OH)\(_3\)+3NaNO\(_3\)

4)2Al(OH)\(_3\)\(\underrightarrow{to}\)Al₂O₃+3H₂O

5)2Al₂O₃\(\xrightarrow[criolit]{đpnc}\)4Al+3O₂

(1) 2Al(OH)3--^to--->Al2O3+3H2O

(2) 2Al2O3---dpnc-->4Al+3O2

(3) 2Al+6H2SO4--^to-->Al2(SO4)3+6H2O+3SO2

(4) Al2(SO4)3+3BaCl2---->2AlCl3+3BaSO4

1, (1) 4Al+ 3O2--(to)---> 2Al2O3

(2) Al2O3+6HCl---> 2AlCl3+ 3H2O

(3) AlCl3+3NaOH---->Al(OH)3+ 3NaCl

(4) 2Al(OH)3---(t^o)---> Al2O3+ 3H2O

(5)2Al2O3---(t^o+ đpnc)--> 4Al+ 3O2

(6) 2Al+ 3Cl2---> 2AlCl3

2, (1)Fe+ CuSO4-->Cu+ FeSO4

(2) FeSO4+ 2NaOH--> Fe(OH)2+ Na2SO4

(3) Fe(OH)2 +2HCl---> FeCl2+ 2H2O

Bài cuối tự làm nhé!

câu 3

2Al + 3Cl2 --t--> 2AlCl3

AlCl3 + 3NaOH -> 3NaCl + Al(OH)3

2Al(OH)3 -t-> Al2O3 + H2O

Al2O3 + 3H2SO4 -> Al2(SO4)3 + 3H2O

Al2(SO4)3 + 3BaCl2 -> 3BaSO4 + 2AlCl3

2AlCl3 + 3Mg -> 2Al + 3MgCl2

\(\left(1\right)4Al+3O_2\underrightarrow{t^o}2Al_2O_3\\ \left(2\right)Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3\downarrow+3NaCl\\ 2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\\ 2Al_2O_3\underrightarrow{dpnc}4Al+3O_2\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\)

`Fe + 2HCl -> FeCl_2 + H_2`

`2Na + 2HCl -> 2NaCl + H_2`

`2Al + 6HCl -> 2AlCl_3 + 3H_2`

`2Al(OH)_3 + 3H_2SO_4 -> Al_2(SO_4)_3 + 6H_2O`

Fe + 2HCl → FeCl₂ + H₂
2Na + 2HCl → 2NaCl + H₂
2Al + 6HCl → 2AlCl₃ + 3H₂
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O

\(Fe+2HCl\rightarrow FeCl_2+H_2\)

\(2Na+2HCl\rightarrow2NaCl+H_2\)

\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)

2Al + 6H₂SO₄ → Al₂(SO₄)₃ + 3SO₂ + 6H₂O

CaCO₃ \(\underrightarrow{to}\) CaO + CO₂

2Al(OH)₃ \(\underrightarrow{to}\) Al₂O₃ + 3H₂O

3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 2NO + 4H₂O

4P + 5O₂ \(\underrightarrow{to}\) 2P₂O₅

2Al(OH)₃ + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O

2AlCl₃ + 3Ba(OH)₂ → 3BaCl₂ + 2Al(OH)₃

2Na₃PO₄ + 3CaCl₂ → 6NaCl + Ca₃(PO₄)₂

Bạn viết sai một số công thức, lần sau chú ý hơn nhé!

Cân bằng các phương trình hoa học sau:
$\mathrm{2A}l+\; 6\mathrm{H2}S{O}_4->A{l}_2{\left(S{O}_4\right)}_3+\; 3S{O}_2+\; 6H_{2}O$

$CaC{O}_3->Ca{O}_2+C{O}_2$

$\mathrm{2A}\mathrm{l(}O{\mathrm{H)}}_3->A{l}_2{O}_3+\; 3H_{2}O$

$\mathrm{3C}u+\; 8HN{O}_3->\; 3Cu{\left(N{O}_3\right)}_2+\; 2NO+\; 4H_{2}O$

$\mathrm{4P}+\; 5O_2->\; 2P_2{O}_5$

$\mathrm{2A}\mathrm{l(}O{\mathrm{H)}}_3+\; 3H_{2}S{O}_4->A{l}_2{\left(S{O}_4\right)}_3+\; 6H_{2}O$

$\mathrm{2A}lC{l}_3+\; 3BaO{H}_2->\; 3AlO{H}_3+\; 2BaC{l}_2$

$\mathrm{2N}{a}_{3}P{O}_4+\mathrm{C3}aC{l}_2->\; 6NaCl+C{a}_3{\left(P{O}_4\right)}_2$

\(\text{Al2O3+6HCl->2AlCl3+3H2O}\)

\(\text{AlCl3+3AgNO3->3AgCl+Al(NO3)3}\)

\(\text{Al(NO3)3+3NaOH->Al(OH)3+3NaNO3}\)

\(\text{Al(OH)3+NaOH->NaAlO2+2H2O}\)

Al2O3+6HCl---->2AlCl3+3H2O

AlCl3+3AgNO3----->Al(NO3)3+3AgCl

Al(NO3)3+3NaOH---->3NaNO3+Al(OH)3

Al(OH)3+NaOH---->NaAlO2+2H2O

Nhầm @@

\(Al\left(NO_3\right)_3\)

a) \(K_2O+H_2O->2KOH\)

b) \(2Fe+3Cl_2->2FeCl_3\)

c) \(2Al\left(OH\right)_3+3H_2SO_4->Al_2\left(SO_4\right)_3+6H_2O\)

d) \(4FeS_2+11O_2->2Fe_2O_3+8SO_2\)

e)\(2Al+6HCl->2AlCl_3+3H_2\)

f) \(2KClO_3->KCl+3O_2\)

g) \(4P+5O_2->2P_2O_5\)

h) \(3Fe+2O_2->Fe_3O_4\)

i) \(2Al+3CuSO_4->Al_2\left(SO_4\right)_3+3Cu\)

j) \(2K+2H_2O->2KOH+H_2\)

$\rm u)S + 2HNO_3 \rightarrow H_2SO_4 + 2NO \uparrow$

$\rm v)3Ba(NO_3)_2 + Al_2(SO_4)_3 \rightarrow 3BaSO_4 \downarrow + 2Al(NO_3)_3$
$\rm w)3Ba(OH)_2 + P_2O_5 \rightarrow Ba_3(PO_4)_3 \downarrow + 3H_2O$
$\rm x)2Fe_2O_3 + 3C \xrightarrow{t^o} 4Fe + 3CO_2 \uparrow$