a)\(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)

   \(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)

   \(2AlCl_3+3Ba\left(OH\right)_2\rightarrow2Al\left(OH\right)_3\downarrow+3BaCl_2\)

   \(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)

   \(2Al+3S\underrightarrow{t^o}Al_2S_3\)

1, (1) 4Al+ 3O2--(to)---> 2Al2O3

(2) Al2O3+6HCl---> 2AlCl3+ 3H2O

(3) AlCl3+3NaOH---->Al(OH)3+ 3NaCl

(4) 2Al(OH)3---(t^o)---> Al2O3+ 3H2O

(5)2Al2O3---(t^o+ đpnc)--> 4Al+ 3O2

(6) 2Al+ 3Cl2---> 2AlCl3

2, (1)Fe+ CuSO4-->Cu+ FeSO4

(2) FeSO4+ 2NaOH--> Fe(OH)2+ Na2SO4

(3) Fe(OH)2 +2HCl---> FeCl2+ 2H2O

Bài cuối tự làm nhé!

câu 3

2Al + 3Cl2 --t--> 2AlCl3

AlCl3 + 3NaOH -> 3NaCl + Al(OH)3

2Al(OH)3 -t-> Al2O3 + H2O

Al2O3 + 3H2SO4 -> Al2(SO4)3 + 3H2O

Al2(SO4)3 + 3BaCl2 -> 3BaSO4 + 2AlCl3

2AlCl3 + 3Mg -> 2Al + 3MgCl2

\(\left(1\right)4Al+3O_2\underrightarrow{t^o}2Al_2O_3\\ \left(2\right)Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3\downarrow+3NaCl\\ 2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\\ 2Al_2O_3\underrightarrow{dpnc}4Al+3O_2\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\)

FeCl₃+3NaOH→Fe(OH)₃+3NaCl

2Fe(OH)₃→Fe₂O₃+3H₂O

Fe₂0₃+3CO→2Fe+3CO₂

Fe+H₂SO₄→FeSO₄+H₂

FeCl₃ + 3NaOH ➜ Fe(OH)₃ + 3NaCl

2Fe(OH)₃ ➜ Fe₂O₃ + 3H₂O

Fe₂O₃ + 3CO ➜ 2Fe + 3CO₂

Fe + CuSO₄ ➜ FeSO₄ + Cu

1) Al\(_2\)(SO\(_4\))\(_3\)+3BaCl\(_2\)→2AlCl\(_3\)+3BaSO\(_4\)↓

2)AlCl\(_3\)+3AgNO\(_3\)→Al(NO\(_3\))\(_3\)+3AgCl↓

3)Al(NO\(_3\))\(_3\)+3NaOH→Al(OH)\(_3\)+3NaNO\(_3\)

4)2Al(OH)\(_3\)\(\underrightarrow{to}\)Al₂O₃+3H₂O

5)2Al₂O₃\(\xrightarrow[criolit]{đpnc}\)4Al+3O₂

Chất thứ 2 trong sơ đồ phải là Al₂O₃ bạn nhé!

\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)

\(2Al_2O_3\underrightarrow{đpnc}4Al+3O_2\)

\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)

\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_{4\downarrow}\)

Bạn tham khảo nhé!

`Fe + 2HCl -> FeCl_2 + H_2`

`2Na + 2HCl -> 2NaCl + H_2`

`2Al + 6HCl -> 2AlCl_3 + 3H_2`

`2Al(OH)_3 + 3H_2SO_4 -> Al_2(SO_4)_3 + 6H_2O`

Fe + 2HCl → FeCl₂ + H₂
2Na + 2HCl → 2NaCl + H₂
2Al + 6HCl → 2AlCl₃ + 3H₂
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O

\(Fe+2HCl\rightarrow FeCl_2+H_2\)

\(2Na+2HCl\rightarrow2NaCl+H_2\)

\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)

(1) 2Na+2H2O--->2NaOH+H2

(2) 3NaOH+Al(NO3)3--->Al(OH)3+3NaNO3

(3) 2Al(OH)3--->Al2O3+3H2O

(4) 2Al2O3-đpnc---> 4Al+3O2

(5) 2Al+3H2SO4--->Al2(SO4)3+3H2

(6) Al2(SO4)3+3BaCl2--->3BaSO4+2AlCl3

(1) 2Na+2H2O->2NaOH+H2

(2) 3NaOH+AlCl3->Al(OH)3+3NaCl

(3) 2Al(OH)3->Al2O3+3H2O

(4) 2Al2O3-điện phân nóng chảy->4Al+3O2

(5) 2Al+3H2SO4->Al2(SO4)3+3H2

(6) Al2(SO4)3+3BaCl2->3BaSO4+2AlCl3

a) \(K_2O+H_2O->2KOH\)

b) \(2Fe+3Cl_2->2FeCl_3\)

c) \(2Al\left(OH\right)_3+3H_2SO_4->Al_2\left(SO_4\right)_3+6H_2O\)

d) \(4FeS_2+11O_2->2Fe_2O_3+8SO_2\)

e)\(2Al+6HCl->2AlCl_3+3H_2\)

f) \(2KClO_3->KCl+3O_2\)

g) \(4P+5O_2->2P_2O_5\)

h) \(3Fe+2O_2->Fe_3O_4\)

i) \(2Al+3CuSO_4->Al_2\left(SO_4\right)_3+3Cu\)

j) \(2K+2H_2O->2KOH+H_2\)

a) 4FeS₂+11O₂\(\overset{t^0}{\rightarrow}\)2Fe₂O₃+8SO₂

2SO₂+O₂\(\overset{V_2O_5,t^0}{\rightarrow}2SO_3\)

SO₃+H₂O\(\rightarrow\)H₂SO₄

Cu+ 2H₂SO_4đ\(\overset{t^0}{\rightarrow}\)CuSO₄+SO₂+H₂O

b)

AlCl₃+3NaOH\(\rightarrow\)Al(OH)₃+3NaCl

2Al(OH)₃\(\overset{t^0}{\rightarrow}Al_2O_3+3H_2O\)

Al₂O₃+3H₂SO₄\(\rightarrow\)Al₂(SO₄)₃+3H₂O

Al₂(SO₄)₃+3BaCl₂\(\rightarrow\)3BaSO₄+2AlCl₃

c) 4Na+O₂\(\overset{t^0}{\rightarrow}2Na_2O\)

Na₂O+H₂O\(\rightarrow\)2NaOH

2NaOH+CO₂\(\rightarrow\)Na₂CO₃+H₂O

Na₂CO₃+CO₂+H₂O\(\rightarrow\)2NaHCO₃