-15x - 30 + 14x - 21 -50 = 0

-15x + 14x = 50 + 21 + 30

-x = 101

x = -101

=> -15x+(-30)+14x-21=50

=>(15x-14x)-(30+21)=50

x-51=50

x=-101

a,2x - 35 = 15

2x=50

x=25

Vậy x=25

b, -15(x+2) + 7(2x-3)= -50

-15x - 30 + 14x - 21 = -50

-x - 51 = -50

-x=1

x= -1

Vậy......

a) 2x+(-35)=15

2x=15-(-35)

2x=50

x=50:2

x=25

a, \(-15\left(x+2\right)+7\left(2x-3\right)=-50\\ -15x-30+14x-21=-50\\ -x-51=-50\\ -x=-50+51\\ -x=1\\ \Rightarrow x=-1\)Vậy \(x=-1\)

b, \(3\left(x+2\right)-6\left(x-5\right)=2\left(5-2x\right)\\ 3x+6-6x+30=10-4x\\ -3x+36=10-4x\\ -3x+4x=10-36\\ x=-26\)Vậy \(x=-26\)

a, $-15\left(x+2\right)+7\left(2x-3\right)=-50-15x-30+14x-21=-50-x-51=-50-x=-50+51-x=1\Rightarrow x=-1$Vậy $x=-1$

b, $3\left(x+2\right)-6\left(x-5\right)=2\left(5-2x\right)3x+6-6x+30=10-4x-3x+36=10-4x-3x+4x=10-36x=-26$Vậy $x=-26$

\(a,x+39=50\\ \Rightarrow x=11\\ b,2x-15=17\\ \Rightarrow2x=32\\ \Rightarrow x=16.\)

\(\dfrac{3}{4\left(x-5\right)}-\dfrac{15}{2\left(x-5\right)\left(x+5\right)}=\dfrac{-7}{6\left(x+5\right)}\)

\(\Leftrightarrow9\left(x+5\right)-90=-14\left(x-5\right)\)

=>9x+45-90=-14x+70

=>23x=70-45+90=115

hay x=5(loại)

\(ĐKXĐ:x\ne-1;x\ne\dfrac{1}{2}\)

Ta có : \(\dfrac{6x+5}{3x+3}=\dfrac{5-4x}{1-2x}\)

\(\Leftrightarrow\left(6x+5\right)\left(1-2x\right)=\left(5-4x\right)\left(3x+3\right)\)

\(\Leftrightarrow6x-12x^2+5-10x=15x+15-12x^2-12x\)

\(\Leftrightarrow5-4x-12x^2-15-3x+12x^2=0\)

\(\Leftrightarrow-10-7x=0\)

\(\Rightarrow x=\dfrac{-10}{7}\)

(-75) : (x + 6) = -15

x + 6 = -75 : (-15)

x + 6 = 5

x = 5 - 6

x = -1

B) -25 - 5.(x + 2) = 50

5(x + 2) = -25 - 50

5(x + 2) = -75

x + 2 = -75 : 5

x + 2 = - 15

x = -15 - 2

x = -17

D) 6.(2x - 8) - 8.(3x - 5) = -56

12x - 24 - 24x + 40 = -56

-12x + 16 = -56

-12x = -56 - 16

-12x = -72

x = (-72) : (-12)

x = 6

Lời giải:

a. 

$-75:(x+6)=-15$

$x+6=(-75):(-15)=5$

$x=5-6=-1$

b. 

$-25-5(x+2)=50$

$5(x+2)=-25-50=-75$

$x+2=-75:5=-15$

$x=-15-2=-17$

d.

$6(2x-8)-8(3x-5)=-56$

$(12x-48)-(24x-40)=-56$

$-12x-8=-56$

$-12x=-56+8=-48$

$x=(-48):(-12)=4$

(Đề ghi không rõ lắm, nên câu b có thể làm sai đề)

\(\dfrac{-75}{x+6}=-15\)

\(x+6=\dfrac{-75}{-15}=5\)

\(x=5-6=-1\)

\(-25-5x\left(x+2\right)=50\)

\(5x\left(x+2\right)=-25-50=-75\)

\(x\left(x+2\right)=x^2+2x=\dfrac{-75}{5}=-15\)

\(x^2+2x+1=-15+1=-14\)

\(\left(x+1\right)^2=-14\)

Suy ra không có nghiệm, vì không có căn bậc hai của số âm

1. => -15x-30+14x-21 = -50

=> -x-51 = -50

=> -x = -50 + 51 = 1

=> x = -1

2. = >x.(x-2) = 0

=> x=0 hoặc x-2=0

=> x=0 hoặc x=2

3. => 8x^2+28 = 100

=> 8x^2 = 100-28 = 72

=> x^2 = 72 : 8 = 9

=> x=3 hoặc x=-3

Tk mk nha

Thăn kiu pạn nhaaaaaaaa

\(1,3x-7=19\\ \Rightarrow3x=26\\ \Rightarrow x=\dfrac{26}{3}\\ 2,\left(2x+1\right)\left(x-3\right)=0\\ \Rightarrow\left[{}\begin{matrix}2x+1=0\\x-3=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=3\end{matrix}\right.\\ 3,3x+\dfrac{2}{4}+1=5x-\dfrac{1}{3}\\ \Rightarrow5x-\dfrac{1}{3}-3x-\dfrac{2}{4}-1=0\\ \Rightarrow2x-\dfrac{11}{6}=0\\ \Rightarrow2x=\dfrac{11}{6}\\ \Rightarrow x=\dfrac{11}{12}\)

\(4,\dfrac{x}{15}+\dfrac{1}{2}-\dfrac{x}{50}=\dfrac{5}{6}\\ \Rightarrow\dfrac{x}{15}-\dfrac{x}{50}=\dfrac{5}{6}-\dfrac{1}{2}\\ \Rightarrow x\left(\dfrac{1}{15}-\dfrac{1}{50}\right)=\dfrac{1}{3}\\ \Rightarrow\dfrac{7}{150}x=\dfrac{1}{3}\\ \Rightarrow x=\dfrac{50}{7}\)