a, \(-15\left(x+2\right)+7\left(2x-3\right)=-50\\ -15x-30+14x-21=-50\\ -x-51=-50\\ -x=-50+51\\ -x=1\\ \Rightarrow x=-1\)Vậy \(x=-1\)
b, \(3\left(x+2\right)-6\left(x-5\right)=2\left(5-2x\right)\\ 3x+6-6x+30=10-4x\\ -3x+36=10-4x\\ -3x+4x=10-36\\ x=-26\)Vậy \(x=-26\)
a, −15(x+2)+7(2x−3)=−50−15x−30+14x−21=−50−x−51=−50−x=−50+51−x=1⇒x=−1Vậy x=−1
b, 3(x+2)−6(x−5)=2(5−2x)3x+6−6x+30=10−4x−3x+36=10−4x−3x+4x=10−36x=−26Vậy