a) 10/7 - 3/8 

= 59/56

b) 9/10- 7/12

= 19/60

giúp mình với

a 4/7 x 5/2 -3/8 = 10/7 - 3/8 = 59/56

b 9/10 - 7/12 =19/60

Áp dụng dãy tỉ số bằng nhau:

b.

\(\dfrac{x}{2}=\dfrac{y}{-5}=\dfrac{x-y}{2-\left(-5\right)}=\dfrac{-7}{7}=-1\)

\(\Rightarrow\left\{{}\begin{matrix}x=2.\left(-1\right)=-2\\y=-5.\left(-1\right)=5\end{matrix}\right.\)

d.

\(\dfrac{4}{x}=\dfrac{7}{y}\Rightarrow\dfrac{y}{7}=\dfrac{x}{4}=\dfrac{y-x}{7-4}=\dfrac{-12}{3}=-4\)

\(\Rightarrow\left\{{}\begin{matrix}x=4.\left(-4\right)=-16\\y=7.\left(-4\right)=-28\end{matrix}\right.\)

\(a,=7xy\left(x^2-2xy+y^2\right)=7xy\left(x-y\right)^2\\ b,=3x\left(x-y\right)-5\left(x-y\right)=\left(3x-5\right)\left(x-y\right)\\ c,=x^2+3x+4x+12=\left(x+3\right)\left(x+4\right)\)

Áp dụng tính chất của DTSBN, ta được:

\(\dfrac{x}{4}=\dfrac{y}{5}=\dfrac{z}{6}=\dfrac{x-5z}{4-5\cdot6}=\dfrac{12}{4-30}=\dfrac{-12}{26}=\dfrac{-6}{13}\)

=>x=-24/13; y=-30/13; z=-36/13

Ta có 

\(\dfrac{x}{4}=\dfrac{y}{5}=\dfrac{z}{6}\)

Áp dụng tính chất dãy tỉ số bằng nhau :

\(\dfrac{x}{4}=\dfrac{y}{5}=\dfrac{z}{6}=\dfrac{x-5z}{4-5.6}=\dfrac{12}{-26}=-\dfrac{6}{13}\\ \Rightarrow\left\{{}\begin{matrix}x=-\dfrac{6}{13}\times4=-\dfrac{24}{13}\\y=-\dfrac{6}{13}\times5=-\dfrac{30}{13}\\z=-\dfrac{6}{13}\times6=-\dfrac{36}{13}\end{matrix}\right.\)

ta có : `x/4=y/5=z/6` và `x/4=y/5=(5z)/30` và `x-5z=12`

Áp dụng t/c dãy tỉ số bằng nhau ta có :

`x/4=y/5=(5z)/30 =(x-5z)/(4-30)=12/(-26)=-6/13`

`=>x/4 =-6/13=>x=-6/13 . 4=-24/13`

`=>y/5 =-6/13=>y=-6/13 . 5= -30/13`

`=>z/6=-6/13=>z=-6/13 . 6=-36/13`

vậy ...

a.x + 2/5 = 1 - 1/6

x + 2/5 = 5/6

x= 13/30

b.3/4 - 2/5 + 5/12

=7/20 + 5/12

=23/30

a)\(x=\left(1-\dfrac{1}{6}\right)-\dfrac{2}{5}=\dfrac{5}{6}-\dfrac{2}{5}=\dfrac{13}{30}\)

b)\(=\dfrac{7}{20}+\dfrac{5}{12}=\dfrac{23}{30}\)

a.x + 2/5 = 1 - 1/6

x + 2/5 = 5/6

x= 13/30

b.3/4 - 2/5 + 5/12

=7/20 + 5/12

=23/30

(2x+1).(y2-5)=12=1.12=12.1=6.2=2.6=3.4=4.3=...(cả số âm)

Rồi bạn lập bảng

VD:

`(2x+1)(y^2-5)=12=1.12=(-1).(-12)=2.6=(-2).(-6)=3.4=(-3).(-4)`

  Vì `x;y` là số tự nhiên `=>x=1;y=3`

A

A

A

a) \(\dfrac{5}{4}+\dfrac{3}{5}=\dfrac{25}{20}+\dfrac{12}{20}=\dfrac{37}{20}\)

b) \(\dfrac{7}{8}+\dfrac{9}{24}=\dfrac{21}{24}+\dfrac{9}{24}=\dfrac{30}{24}=\dfrac{15}{12}\)

c) \(\dfrac{2}{36}+\dfrac{1}{6}+\dfrac{5}{12}=\dfrac{2}{36}+\dfrac{6}{36}+\dfrac{15}{36}=\dfrac{23}{36}\)

a) \(\dfrac{5}{4}+\dfrac{3}{5}=\dfrac{25}{20}+\dfrac{12}{20}=\dfrac{37}{20}\)

b) \(\dfrac{7}{8}+\dfrac{9}{24}=\dfrac{21}{24}+\dfrac{9}{24}=\dfrac{30}{24}=\dfrac{5}{4}\)

c) \(\dfrac{2}{36}+\dfrac{1}{6}+\dfrac{5}{12}=\dfrac{2}{36}+\dfrac{6}{36}+\dfrac{15}{36}=\dfrac{23}{36}\)

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