a)

b) 4,5 : 0,3 = 2,25 : ( 0,1.x) => 0,1.x =

c)

d)

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a: (2x-3/2)(|x|-5)=0

=>2x-3/2=0 hoặc |x|-5=0

=>x=3/4 hoặc |x|=5

=>\(x\in\left\{\dfrac{3}{4};5;-5\right\}\)

b: x-8x^4=0

=>x(1-8x^3)=0

=>x=0 hoặc 1-8x^3=0

=>x=1/2 hoặc x=0

c: x^2-(4x+x^2)-5=0

=>x^2-4x-x^2-5=0

=>-4x-5=0

=>x=-5/4

a)\(3,8:\left(2x\right)=\dfrac{1}{4}:2\dfrac{2}{3}\)

\(2x=3,8:\dfrac{3}{32}\)

\(x=\dfrac{608}{15}:2\)

\(x=\dfrac{304}{15}\)

b)\(\left(0,25x\right):3=\dfrac{5}{6}:0,125\)

\(0,25x=\dfrac{20}{3}\times3\)

\(x=20:0,25\)

\(x=80\)

c) \(0,01:2,5=\left(0,75\times x\right):0,75\)

\(0,004=0,75\times x:0,75\)

\(0,004=x\times0,75:0,75\)

\(0,004=x\times1\)

\(0,004=x\)

\(\Rightarrow x=0,004\)

d)\(1\dfrac{1}{3}:0,8=\dfrac{2}{3}:\left(0,1x\right)\)

\(\dfrac{5}{3}=\dfrac{2}{3}:0,1\times x\)

\(\dfrac{5}{3}=\dfrac{20}{3}\times x\)

\(\Rightarrow x=\dfrac{20}{3}:\dfrac{5}{3}\)

\(x=4\)

a) \(x=20\dfrac{4}{15}.\)

b) \(x=80\)

c) \(x=0,004\)

d) \(x=4.\)

a: 

ĐKXĐ: x<>6

\(\dfrac{x-6}{-1,5}=\dfrac{-6}{x-6}\)

=>\(\left(x-6\right)^2=\left(-1,5\right)\cdot\left(-6\right)=9\)

=>\(\left[{}\begin{matrix}x-6=3\\x-6=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=9\left(nhận\right)\\x=3\left(nhận\right)\end{matrix}\right.\)

b: \(\dfrac{1\dfrac{2}{3}}{x-4}=\dfrac{5\dfrac{1}{6}}{x+1}\)

=>\(\dfrac{\dfrac{5}{3}}{x-4}=\dfrac{\dfrac{31}{6}}{x+1}\)

=>\(\dfrac{5}{3}\left(x+1\right)=\dfrac{31}{6}\left(x-4\right)\)

=>\(10\left(x+1\right)=31\left(x-4\right)\)

=>31x-124=10x+10

=>21x=134

=>\(x=\dfrac{134}{21}\)(nhận)

Đề yêu cầu làm gì với tỉ lệ thức đó em?

a) x : ( -2,14) = (-3,12) :1,2

x : ( -2,14) = -2,6

x = -2,6 x ( -2,14)

x = 5,564

Vậy x = 5,564

b)\(2\dfrac{2}{3}\) : x = \(2\dfrac{1}{12}\) : ( -0,06)

\(2\dfrac{2}{3}\) : x = \(-\dfrac{625}{18}\)

x = \(2\dfrac{2}{3}\) : \(-\dfrac{625}{18}\)

x =

a)x : (-2,14) = (-3,12) : 1,2

x : (-2,14) = -2,6

x = (-2,6) * (-2,14)

x = 5,564

b)8/3 : x = 25/12 : (-0,06)

8/3 : x = -625/18

x = 8/3 : -625/18

x = -48/625 = -0,0768

Đó là đáp án của em ạ , mong thầy duyệt.

`a,ĐKXĐ:x-4 ne 0,2x+2 ne 0`

`<=>x ne 4,x me -1`

`b,ĐKXĐ:4x^2-25 ne 0`

`<=>(2x-5)(2x+5) ne 0`

`<=>x ne +-5/2`

`c,ĐKXĐ:8x^3+27 ne 0`

`<=>8x^3 ne -27`

`<=>2x ne -3`

`<=>x ne -3/2`

`d,2x+2 ne 0,4y^2-9 ne 0`

`<=>2x ne -2,(2y-3)(2y+3) ne 0`

`<=>x ne -1,y ne +-3/2`

b) ĐKXĐ: \(x\notin\left\{\dfrac{5}{2};-\dfrac{5}{2}\right\}\)

c) ĐKXĐ: \(x\ne-\dfrac{3}{2}\)

d) ĐKXĐ: \(\left\{{}\begin{matrix}x\ne-1\\y\notin\left\{\dfrac{3}{2};-\dfrac{3}{2}\right\}\end{matrix}\right.\)

a: 10:15=14:21

=>10/14=15/21; 15/10=21/14; 14/10=21/15

b: 2/3:1/4=2/3x4=8/3

16/9:16/24=16/9x24/16=8/3

Do đó: \(\dfrac{\dfrac{2}{3}}{\dfrac{1}{4}}=\dfrac{\dfrac{16}{9}}{\dfrac{16}{24}}\)

Suy ra: \(\dfrac{\dfrac{2}{3}}{\dfrac{16}{9}}=\dfrac{\dfrac{1}{4}}{\dfrac{16}{24}};\dfrac{\dfrac{1}{4}}{\dfrac{2}{3}}=\dfrac{\dfrac{16}{24}}{\dfrac{16}{9}};\dfrac{\dfrac{16}{9}}{\dfrac{2}{3}}=\dfrac{\dfrac{16}{24}}{\dfrac{1}{4}}\)

\(\begin{array}{l}a)\dfrac{x}{6} = \dfrac{{ - 3}}{4}\\x = \dfrac{{( - 3).6}}{4}\\x = \dfrac{{ - 9}}{2}\end{array}\)

Vậy \(x = \dfrac{{ - 9}}{2}\)

\(\begin{array}{l}b)\dfrac{5}{x} = \dfrac{{15}}{{ - 20}}\\x = \dfrac{{5.( - 20)}}{{15}}\\x = \dfrac{{ - 20}}{3}\end{array}\)

Vậy \(x = \dfrac{{ - 20}}{3}\)