a:
ĐKXĐ: x<>6
\(\dfrac{x-6}{-1,5}=\dfrac{-6}{x-6}\)
=>\(\left(x-6\right)^2=\left(-1,5\right)\cdot\left(-6\right)=9\)
=>\(\left[{}\begin{matrix}x-6=3\\x-6=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=9\left(nhận\right)\\x=3\left(nhận\right)\end{matrix}\right.\)
b: \(\dfrac{1\dfrac{2}{3}}{x-4}=\dfrac{5\dfrac{1}{6}}{x+1}\)
=>\(\dfrac{\dfrac{5}{3}}{x-4}=\dfrac{\dfrac{31}{6}}{x+1}\)
=>\(\dfrac{5}{3}\left(x+1\right)=\dfrac{31}{6}\left(x-4\right)\)
=>\(10\left(x+1\right)=31\left(x-4\right)\)
=>31x-124=10x+10
=>21x=134
=>\(x=\dfrac{134}{21}\)(nhận)
Đề yêu cầu làm gì với tỉ lệ thức đó em?