1 x 1! + 2 x 2 ! + 3 x 3! + ... + 13 x 13 !
Tìm số nguyên x, biết 13 ⋮ (2x + 3)
A. x ∈ {1; -1; 13; -13} B. x ∈ {1; 13}
C. x ∈ {-1; 5; -2; -8} D. x ∈ {1; 2; 5; 8}
Tìm x ∈ Z thỏa mãn; -1 < x < 2
A. x ∈ {0} B. x ∈ {-1;0;1;2} C. x ∈ {0;1} D. x ∈ {0;1;2}
Sắp xếp các số 0;-12; -4; 9; 234; -234 theo thứ tự giảm dần, chọn câu đúng?
A. 234; 0; 9; -4; -12; -234 B. -234; -4; 0; -12; 9; 234
C. -234; -12; -4; 0; 9; 234 D. 234; 9; 0; -4; -12; -234
1.(x+1)/35 + (x+3)/33 = (x+5)/33 + (x+7)/20
2. (X+1)/12+ (X+2)/13 = (X+3)/14+ (X+4)/15
3. (X-85)/15+ (X-75)/13+(X-67)/11+ (X-64)/9=10
4. (X-1)/13-(2X-13)/15=(3X-15)/27- (4X-27)/29
2: \(\Leftrightarrow\left(\dfrac{x+1}{12}-1\right)+\left(\dfrac{x+2}{13}-1\right)=\left(\dfrac{x+3}{14}-1\right)+\left(\dfrac{x+4}{15}-1\right)\)
=>x-11=0
=>x=11
3: \(\Leftrightarrow\left(\dfrac{x-85}{15}-1\right)+\left(\dfrac{x-74}{13}-2\right)+\left(\dfrac{x-67}{11}-3\right)+\left(\dfrac{x-64}{9}-4\right)=0\)
=>x-100=0
=>x=100
tìm x
a, 11/13 -( 5/42 - x) = - (15/28 - 11/13)
b, x +1/3 = 2/5-(-1/3)
c, 2/3 x +5/7 =3/10
d, 3/7-x = 1/4 - (-3/5)
e, -21/13 x + 1/3 = -2/3
11/13-(5/42-x)=(15/28-11/13)
11/13-(5/42-x)=-37/182
(5/42-x)=11/13+37/182
(5/42-x)=191/182
x=5/42-191/182
x=-254/273
vậy x=-254/273
bạn ấn vào chữ M nằm ngang ở dưới câu hỏi khi bạn trả lời là sẽ ấn được phân số nhé
còn gửi câu trả lời cũng tương tự
\(b,x+\frac{1}{3}=\frac{2}{5}-\left(-\frac{1}{3}\right)\)
\(< =>x+\frac{1}{3}=\frac{2}{5}+\frac{1}{3}\)
\(< =>x=\frac{1}{3}-\frac{1}{3}+\frac{2}{5}=\frac{2}{5}\)
\(c,\frac{2}{3}x+\frac{5}{7}=\frac{3}{10}\)
\(< =>\frac{2}{3}x=\frac{3}{10}-\frac{5}{7}=-\frac{29}{70}\)
\(< =>x=\frac{-29}{70}:\frac{2}{3}=-\frac{7}{140}\)
\(d,\frac{3}{7}-x=\frac{1}{4}-\left(-\frac{3}{5}\right)\)
\(< =>\frac{3}{7}-\frac{1}{4}-\frac{3}{5}=x\)
\(< =>x=-\frac{59}{140}\)
\(e,-\frac{21}{12}x+\frac{1}{3}=-\frac{2}{3}\)
\(< =>-\frac{21}{12}x=-\frac{2}{3}-\frac{1}{3}=-1\)
\(< =>x=\frac{12}{21}\)
tính nhanh : 3/5 x 7/9 + 11/9 x 3/5 - 3/10
14/13 : 1/2 + 3/13 x 2 - 2 x 7/13
sao ko quan tâm
Tìm số nguyên x ,nếu biết
a, \((\dfrac {1}{2}-\dfrac {1}{6}).3^x+3^{x+1}= 3^{16}+3^{13}\)
b, \((\dfrac {1}{2}-\dfrac {1}{3}).6^{x+2}-6^x = 6^{14}-6^{13}\)
c, \((\dfrac {1}{3}+\dfrac {1}{6}).2^{x+4}-2^x=2^{13}-2^{10}\)
d, \((\dfrac {1}{2}-\dfrac {1}{6}.3^{x+4} - 4.3^x =3^{16}-4.3^{13}\)
câu a) mình chịu (dùng kiến thức lớp 12 chắc làm đc haha)
b) gt ⇒ \(\frac{1}{6}.6^{x+2}-6^x=6^{14}-6^{13}\)
⇒ \(6^{x+1}-6^x=6^{14}-6^{13}\)
⇒ \(6^x\left(6-1\right)=6^{13}\left(6-1\right)\)
⇒ \(x=13\)
c) gt ⇒ \(\frac{1}{2}.2^{x+4}-2^x=2^{13}-2^{10}\)
⇒ \(2^{x+3}-2^x=2^{13}-2^{10}\)
⇒ \(2^x\left(2^3-1\right)=2^{10}\left(2^3-1\right)\)
⇒ \(x=10\)
d) gt ⇒ \(\frac{1}{3}.3^{x+4}-4.3^x=3^{16}-4.3^{13}\)
⇒ \(3^{x+3}-4.3^x=3^{16}-4.3^{13}\)
⇒ \(3^x\left(3^3-4\right)=3^{13}\left(3^3-4\right)\)
⇒ \(x=13\)
m.n làm giúp mình với ak
1. -2/9 x 15/17 + -2/9 x 2/17
2. -5/3 x 6/5 + -7/9 x 3/10
3. 15/20 x 7/5 + -9/7 x -6/4
4.-25/13 x 5/19 + -25/13 x 14/19
5 -7/13 x 13/5 + -9/7 x 5/3
`1, -2/9 xx 15/17 + (-2/9) xx 2/17`
`= -2/9 xx (15/17 + 2/17)`
`= -2/9 xx 17/17`
`=-2/9xx1`
`=-2/9`
__
`-5/3 xx 6/5 + (-7/9) xx 3/10`
`= -30/15 + (-21/90)`
`= -2 + (-7/30)`
`=-60/30 +(-7/30)`
`=-67/30`
__
`15/20 xx 7/5 + (-9/7) xx (-6/4)`
`=3/4 xx7/5 + (-9/7) xx(-6/4)`
`= 21/20 + 54/28`
`= 21/20 + 27/14`
`=417/140`
__
`-25/13 xx 5/19 + (-25/13) xx 14/19`
`=-25/13 xx (5/19 +14/19)`
`=-25/13 xx 19/19`
`= -25/13 xx 1`
`=-25/13`
__
`-7/13 xx 13/5 + (-9/7) xx 5/3`
`=-7/5 +(-15/7)`
`=-124/35`
1,Tìm x biết:
0,4:x=x:0,9
13/1/3:1/1/3=26:(2.x-1)
0,2:1/1/5=2/3:(6.x+7)
37-x/x+13=3/7
Bài 1: So sánh
1314-1313 với 1315-1314
Bài 2: Tìm x
3x+3x+1-3x+2+3x+3= 594
Bài 1:
ta có 1314<1315
1313<1314
=> dấu cân điền là"<"(1314 -1313 <1315-1314)
còn bài 2 thì sao bạn
Tính bằng cách thuận tiên nhất:
1):(3/4 x 5/97 + 1/9 x 13/47) x (1/5 - 7/25 x 5/7)
2): 8/17 x 4/15 + 8/17 x 22/15 - 8/15 x 9/17
3): 2021/2 x 1/3 + 4042/4 x 1/5 + 6063/3 x 22/15
4); 4/7 x 2/13 + 8/13 :7/4 + 4/7 : 13/2 + 4/7 x 1/13
5): 2022 x 2021 - 1/ 2021 + 2022 x 2020
6): 18 x 123 + 9 x 4567 x 2 + 3 x 5310 x 6 / (2 + 4 + 6 + 8 + ...+20 + 22) + 48
7): A= 2021 x 2021 x 202020 - 2020 x 2020 x 20212021 / 2020 x 20192019
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)