câu a) mình chịu (dùng kiến thức lớp 12 chắc làm đc haha)
b) gt ⇒ \(\frac{1}{6}.6^{x+2}-6^x=6^{14}-6^{13}\)
⇒ \(6^{x+1}-6^x=6^{14}-6^{13}\)
⇒ \(6^x\left(6-1\right)=6^{13}\left(6-1\right)\)
⇒ \(x=13\)
c) gt ⇒ \(\frac{1}{2}.2^{x+4}-2^x=2^{13}-2^{10}\)
⇒ \(2^{x+3}-2^x=2^{13}-2^{10}\)
⇒ \(2^x\left(2^3-1\right)=2^{10}\left(2^3-1\right)\)
⇒ \(x=10\)
d) gt ⇒ \(\frac{1}{3}.3^{x+4}-4.3^x=3^{16}-4.3^{13}\)
⇒ \(3^{x+3}-4.3^x=3^{16}-4.3^{13}\)
⇒ \(3^x\left(3^3-4\right)=3^{13}\left(3^3-4\right)\)
⇒ \(x=13\)
m.n làm giúp mình với ak
a)
\(\left(\frac{1}{2}-\frac{1}{6}\right).3^x+3^{x+1}=3^{16}+3^{13}\)
\(\frac{1}{3}.3^x+3^x.3=3^{13}.\left(3^3+1\right)\)
\(3^x.\left(\frac{1}{3}+3\right)=3^{13}.10\)
\(3^x.\frac{10}{3}=3^{13}.10\)
\(3^x=3^{13}.10:\frac{10}{3}\)
\(3^x=3^{13}.\left(10:\frac{10}{3}\right)\)
\(3^x=3^{13}.3\)
\(3^x=3^{16}\)
➩ \(x=16\)
a)
\(\left(\frac{1}{2}-\frac{1}{6}\right).3^x+3^{x+1}=3^{16}+3^{13}\)
\(\frac{1}{3}.3^x+3^x.3=3^{13}.\left(3^3+1\right)\)
\(3^x.\left(\frac{1}{3}+3\right)=3^{13}.10\)
\(3^x.\frac{10}{3}=3^{13}.10\)
\(3^x=3^{13}.10:\frac{10}{3}\)
\(3^x=3^{13}.\left(10:\frac{10}{3}\right)\)
\(3^x=3^{13}.3\)
\(3^x=3^{14}\)
➩ \(x=14\)
