a: \(\dfrac{20}{30}=\dfrac{2}{3}\)

\(\dfrac{30}{45}=\dfrac{2}{3}\)

Do đó: \(\dfrac{20}{30}=\dfrac{30}{45}\)

b: \(\dfrac{-25}{35}=\dfrac{-5}{7}\)

\(\dfrac{-55}{77}=\dfrac{-5}{7}\)

Do đó: \(-\dfrac{25}{35}=-\dfrac{55}{77}\)

a,20/30=2/3

30/45=2/3

->20/30=30/45

b -25/35=-5/7

-55/77=-5/7

-> -25/35=-55/77

a) Phân số tối giản đều bằng 2/3

b) Phân số tối giản đều bằng -5/7

\(a,\dfrac{20}{30}=\dfrac{30}{45}v\text{ì}20.45=30.30=900\\ b,\dfrac{-25}{35}=\dfrac{-55}{77}v\text{ì}:\left(-25\right).77=35.\left(-55\right)=-1925\)

\(\dfrac{1}{5} = \dfrac{{1.3}}{{5.3}} = \dfrac{3}{{15}}\); 

\(\dfrac{{ - 10}}{{55}} = \dfrac{{ - 10:5}}{{55:5}} = \dfrac{{ - 2}}{{11}}\)

Vậy các cặp phân số bằng nhau là: \(\dfrac{1}{5} = \dfrac{3}{{15}}; \dfrac{{ - 10}}{{55}} = \dfrac{{ - 2}}{{11}}\)

a) Ta có:

\(\dfrac{36}{84}=\dfrac{3}{7}\) ; \(\dfrac{42}{98}=\dfrac{3}{7}\)

\(\Rightarrow\dfrac{36}{84}=\dfrac{42}{98}\left(=\dfrac{3}{7}\right)\)

b) Ta có :

\(\dfrac{123}{237}=\dfrac{41}{79}\) ; \(\dfrac{123123}{237237}=\dfrac{41}{79}\)

\(\Rightarrow\dfrac{123}{237}=\dfrac{123123}{237237}\)

a) Ta rút gọn phân số:

\(\dfrac{36}{84}\)=\(\dfrac{36:12}{84:12}\)=\(\dfrac{3}{7}\)

\(\dfrac{42}{98}\)=\(\dfrac{42:14}{98:14}\)=\(\dfrac{3}{7}\)

Vì \(\dfrac{3}{7}\)=\(\dfrac{3}{7}\) nên \(\dfrac{36}{84}\)=\(\dfrac{42}{98}\)

Ta có \(\left\{{}\begin{matrix}\left(3-2x\right)\left(3y-2x\right)\\\left(2x-3y\right)\left(2x-3\right)\end{matrix}\right.\left\{{}\begin{matrix}9y-6x-6xy+4x^2\\4x^2-6y-6xy+9y\end{matrix}\right.\\ =>\dfrac{3-2x}{2x-3y}=\dfrac{2x-3}{3y-2x}\)

\(\dfrac{20}{30}=\dfrac{20:10}{30:10}=\dfrac{2}{3}\)

\(\dfrac{30}{45}=\dfrac{30:15}{45:15}=\dfrac{2}{3}\)

Ta thấy\(\dfrac{2}{3}=\dfrac{2}{3}\Rightarrow\dfrac{20}{30}=\dfrac{30}{45}\)

Bài 5:

\(\dfrac{3}{4}=\dfrac{x}{20}=\dfrac{21}{y}\)

=>\(\left\{{}\begin{matrix}\dfrac{x}{20}=\dfrac{3}{4}\\\dfrac{21}{y}=\dfrac{3}{4}\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x=20\cdot\dfrac{3}{4}=15\\y=21\cdot\dfrac{4}{3}=7\cdot4=28\end{matrix}\right.\)

Bài 4:

a: \(\dfrac{3}{5}=\dfrac{3\cdot9}{5\cdot9}=\dfrac{27}{45}\)

b: Đề sai rồi bạn

Bài 3:

a: \(21\cdot21=441\)

\(49\cdot9=441\)

=>\(21\cdot21=49\cdot9\)

=>\(\dfrac{21}{9}=\dfrac{49}{21}\)

b: \(\dfrac{-24}{34}=\dfrac{-24:2}{34:2}=\dfrac{-12}{17}\)

\(\dfrac{-60}{85}=\dfrac{-60:5}{85:5}=\dfrac{-12}{17}\)

Do đó: \(\dfrac{-24}{34}=\dfrac{-60}{85}\)

Bài 2:

\(15cm=\dfrac{3}{20}m\)

\(40mm=\left(\dfrac{40}{1000}\right)m=\dfrac{1}{25}m\)

Bài 1:

a: \(\left(-17\right):8=\dfrac{-17}{8}\)

b: \(\left(-8\right):\left(-9\right)=\dfrac{-8}{-9}\)

Bài 2:

a: -2*(-27)=54

6*9=54

=>Hai phân số này bằng nhau

b: -1/-5=1/5=5/25<>4/25

Bài 3:

a: =>16/x=-4/5

=>x=-20

b: =>(x+7)/15=-2/3

=>x+7=-10

=>x=-17

a) \(\dfrac{-2}{9}\) và \(\dfrac{6}{-27}\)

\(\dfrac{6}{-27}=\dfrac{6:\left(-3\right)}{\left(-27\right):\left(-3\right)}=\dfrac{-2}{9}\)

Vậy \(\dfrac{-2}{9}=\dfrac{6}{-27}\)

b) \(\dfrac{-1}{-5}\) và \(\dfrac{4}{25}\)

\(\dfrac{-1}{-5}=\dfrac{\left(-1\right).\left(-5\right)}{\left(-5\right).\left(-5\right)}=\dfrac{5}{25}\)

Do \(5\ne4\Rightarrow\dfrac{5}{25}\ne\dfrac{4}{25}\)

Vậy \(\dfrac{-1}{-5}\ne\dfrac{4}{25}\)

Bài 3

a) \(\dfrac{-28}{35}=\dfrac{16}{x}\)

\(x=\dfrac{35.16}{-28}\)

\(x=-20\)

b) \(\dfrac{x+7}{15}=\dfrac{-24}{36}\)

\(\left(x+7\right).36=15.\left(-24\right)\)

\(36x+252=-360\)

\(36x=-360-252\)

\(36x=-612\)

\(x=\dfrac{-612}{36}\)

\(x=-17\)

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