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Minh Lệ
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Hà Quang Minh
1 tháng 12 2023 lúc 1:20

a) 11 000 x 9 

Nhẩm: 11 nghìn x 9 = 99 nghìn 

            11 000 x 9 = 99 000

b) 21 000 x 3

Nhẩm: 21 000 x 3 = 63 nghìn 

            21 000 x 3 = 63 000

c) 15 000 x 6 

Nhẩm: 15 nghìn × 6 = 90 nghìn 

            15 000 × 6 = 90 000

Phương Hà Hoàng
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⭐Hannie⭐
8 tháng 2 2023 lúc 13:30

`5`

`a, -7/21 +(1+1/3)`

`=-7/21 + ( 3/3 + 1/3)`

`=-7/21+ 4/3`

`=-7/21+ 28/21`

`= 21/21`

`=1`

`b, 2/15 + ( 5/9 + (-6)/9)`

`= 2/15 + (-1/9)`

`= 1/45`

`c, (9-1/5+3/12) +(-3/4)`

`= ( 45/5-1/5 + 3/12)+(-3/4)`

`= ( 44/5 + 3/12)+(-3/4)`

`= 9,05 +(-0,75)`

`=8,3`

`6`

`x+7/8 =13/12`

`=>x= 13/12 -7/8`

`=>x=5/24`

`-------`

`-(-6)/12 -x=9/48`

`=> 6/12 -x=9/48`

`=>x= 6/12-9/48`

`=>x=5/16`

`---------`

`x+4/6 =5/25 -(-7)/15`

`=>x+4/6 =1/5 + 7/15`

`=> x+ 4/6=10/15`

`=>x=10/15 -4/6`

`=>x=0`

`----------`

`x+4/5 = 6/20 -(-7)/3`

`=>x+4/5 = 6/20 +7/3`

`=>x+4/5 = 79/30`

`=>x=79/30 -4/5`

`=>x= 79/30-24/30`

`=>x= 55/30`

`=>x= 11/6`

Vanh Nek
8 tháng 2 2023 lúc 13:32

\(5)\)

\(A=\dfrac{-7}{21}+\left(1+\dfrac{1}{3}\right)\)

\(A=\dfrac{-7}{21}+\dfrac{4}{3}\)

\(A=\dfrac{-7}{21}+\dfrac{28}{21}\)

\(A=1\)

\(--------------\)

\(B=\dfrac{2}{15}+\left(\dfrac{5}{9}+\dfrac{-6}{9}\right)\)

\(B=\dfrac{2}{15}+\dfrac{-1}{9}\)

\(B=\dfrac{18}{135}+\dfrac{-15}{135}\)

\(B=\dfrac{1}{45}\)

\(------------\)

\(C=9-\dfrac{1}{5}+\dfrac{3}{12}+\dfrac{-3}{4}\)

\(C=\dfrac{44}{5}+\dfrac{3}{12}+\dfrac{-3}{4}\)

\(C=\dfrac{528}{60}+\dfrac{15}{60}+\dfrac{-3}{4}\)

\(C=\dfrac{181}{20}+\dfrac{-3}{4}\)

\(C=\dfrac{181}{20}+\dfrac{-15}{20}\)

\(C=\dfrac{83}{10}\)

\(6)\)

\(a)\) \(x+\dfrac{7}{8}=\dfrac{13}{12}\)

\(x=\dfrac{13}{12}-\dfrac{7}{8}\)

\(x=\dfrac{104}{96}-\dfrac{84}{96}\)

\(x=\dfrac{5}{24}\)

\(b)\) \(\dfrac{-6}{12}-x=\dfrac{9}{48}\)

\(\dfrac{-1}{2}-x=\dfrac{3}{16}\)

\(x=\dfrac{-1}{2}-\dfrac{3}{16}\)

\(x=\dfrac{-8}{16}-\dfrac{3}{16}\)

\(x=\dfrac{-11}{16}\)

\(c)\) \(x+\dfrac{4}{6}=\dfrac{5}{25}-\left(-\dfrac{7}{15}\right)\)

\(x+\dfrac{4}{6}=\dfrac{5}{25}+\dfrac{7}{15}\)

\(x+\dfrac{4}{6}=\dfrac{75}{375}+\dfrac{105}{375}\)

\(x+\dfrac{4}{6}=\dfrac{12}{25}\)

\(x=\dfrac{12}{25}-\dfrac{4}{6}\)

\(x=\dfrac{72}{150}-\dfrac{100}{150}\)

\(x=\dfrac{-14}{75}\)

\(d)\) \(x+\dfrac{4}{5}=\dfrac{6}{20}-\left(-\dfrac{7}{3}\right)\)

\(x+\dfrac{4}{5}=\dfrac{6}{20}+\dfrac{7}{3}\)

\(x+\dfrac{4}{5}=\dfrac{18}{60}+\dfrac{140}{60}\)

\(x+\dfrac{4}{5}=\dfrac{79}{30}\)

\(x=\dfrac{79}{30}-\dfrac{4}{5}\)

\(x=\dfrac{79}{30}-\dfrac{24}{30}\)

\(x=\dfrac{11}{6}\)

HT.Phong (9A5)
8 tháng 2 2023 lúc 13:48

Giải:

\(A=\dfrac{-7}{21}+\left(1+\dfrac{1}{3}\right)\)

\(A=\dfrac{-7}{21}+\dfrac{4}{3}\)

\(A=\dfrac{-7}{21}+\dfrac{28}{21}\)

\(A=\dfrac{21}{21}=1\)

\(B=\dfrac{2}{15}+\left(\dfrac{5}{9}+\dfrac{-6}{9}\right)\)

\(B=\dfrac{2}{15}+\dfrac{-1}{9}\)

\(B=\dfrac{6}{45}+\dfrac{-5}{45}\)

\(B=\dfrac{1}{45}\)

\(C=\left(9-\dfrac{1}{5}+\dfrac{3}{12}\right)+\dfrac{-3}{4}\)

\(C=\left(\dfrac{44}{5}+\dfrac{1}{4}\right)+\dfrac{-3}{4}\)

\(C=\dfrac{181}{20}+\dfrac{-3}{4}\)

\(C=\dfrac{181}{20}+\dfrac{-15}{20}\)

\(C=\dfrac{166}{20}\)

Bài 6:

\(a)x+\dfrac{7}{8}=\dfrac{13}{12}\)

\(x=\dfrac{13}{12}-\dfrac{7}{8}=\dfrac{5}{24}\)

\(b)\dfrac{-6}{12}-x=\dfrac{9}{48}\)

\(x=\dfrac{-6}{12}-\dfrac{9}{48}=\dfrac{-11}{16}\)

\(c)x+\dfrac{4}{6}=\dfrac{5}{25}-\dfrac{-7}{15}\)

\(\Leftrightarrow x+\dfrac{2}{3}=\dfrac{2}{3}\)

\(\Leftrightarrow x=\dfrac{2}{3}-\dfrac{2}{3}=0\)

\(d)x+\dfrac{4}{5}=\dfrac{6}{20}-\dfrac{-7}{3}\)

\(x+\dfrac{4}{5}=\dfrac{79}{30}\)

\(x=\dfrac{79}{30}-\dfrac{4}{5}=\dfrac{11}{6}\)

 

Dương Linh Nhi
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Đào Tùng Dương
13 tháng 2 2022 lúc 12:43

\(10,x-\dfrac{-6}{15}=\dfrac{4}{24}\)

\(x+\dfrac{6}{15}=\dfrac{1}{6}\)

\(x=\dfrac{1}{6}-\dfrac{6}{15}=\dfrac{-7}{30}\)

\(11,-\dfrac{-6}{12}+x=\dfrac{9}{48}\)

\(\dfrac{1}{2}+x=\dfrac{3}{16}\)

\(x=\dfrac{3}{16}-\dfrac{1}{2}=\dfrac{-5}{16}\)

Nguyễn Ngọc Huy Toàn
13 tháng 2 2022 lúc 12:44

\(10.\)

\(x-\dfrac{-6}{15}=\dfrac{4}{24}\)

\(\Leftrightarrow x=\dfrac{4}{24}+\dfrac{-6}{15}\)

\(\Leftrightarrow x=-\dfrac{7}{30}\)

11.\(-\dfrac{-6}{12}+x=\dfrac{9}{48}\)

\(\Leftrightarrow x=\dfrac{9}{48}+\dfrac{-6}{12}\)

\(\Leftrightarrow x=-\dfrac{5}{16}\)

 

 

 

 

Phạm Bảo Trúc
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A = \(\dfrac{8\times12\times32+4\times27\times24+96\times41}{16\times48-48\times9+4\times3\times12}\)

A = \(\dfrac{96\times32+96\times27+96\times41}{16\times48-48\times9+48\times3}\)

A = \(\dfrac{96\times\left(32+27+41\right)}{48\times\left(16-9+3\right)}\)

A = \(\dfrac{96\times100}{48\times10}\)

A = \(\dfrac{20}{1}\) \(\times\) \(\dfrac{48\times10}{48\times10}\)

A = 20 

thuy duong Doan
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Trần Thị Hồng Ngát
28 tháng 4 2018 lúc 21:08

a) 5 - 4x = 3x - 9

\(\Leftrightarrow5-4x-3x+9=0\)

\(\Leftrightarrow14-7x=0\)

\(\Leftrightarrow7x=14\Leftrightarrow x=2\)

Vậy \(S=\left\{2\right\}\)

b) \(\left(x-4\right)\left(3x+9\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\3x+9=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-3\end{matrix}\right.\)

Vậy \(S=\left\{-3;4\right\}\)

c) \(\dfrac{x}{x+4}+\dfrac{12}{x-4}=\dfrac{4x+48}{x\cdot x-16}\)(1)

ĐKXĐ: \(x\ne\pm4\)

\(\left(1\right)\Leftrightarrow\dfrac{x\left(x-4\right)+12\left(x+4\right)-4x-48}{\left(x+4\right)\left(x-4\right)}=0\)

\(\Leftrightarrow x^2-4x+12x+48-4x-48=0\)

\(\Leftrightarrow x^2+4x=0\)

\(\Leftrightarrow x\left(x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(TM\right)\\x=-4\left(KTM\right)\end{matrix}\right.\)

Vậy \(S=\left\{0\right\}\)

d) \(4-2x=7-x\)

\(\Leftrightarrow4-2x-7+x=0\)

\(\Leftrightarrow-x-3=0\)

\(\Leftrightarrow-x=3\Leftrightarrow x=-3\)

Vậy \(S=\left\{-3\right\}\)

e) \(\left(x+4\right) \left(8-4x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+4=0\\8-4x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=2\end{matrix}\right.\)

Vậy \(S=\left\{-4;2\right\}\)

f) \(\dfrac{x}{x+5}+\dfrac{11}{x-5}=\dfrac{x+55}{x\cdot x-25}\left(2\right)\)

ĐKXĐ: \(x\ne\pm5\)

\(\left(2\right)\Leftrightarrow\dfrac{x\left(x-5\right)+11\left(x+5\right)-x-55}{\left(x+5\right)\left(x-5\right)}=0\)

\(\Leftrightarrow x^2-5x+11x+55-x-55=0\)

\(\Leftrightarrow x^2+5x=0\)

\(\Leftrightarrow x\left(x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(TM\right)\\x=-5\left(KTM\right)\end{matrix}\right.\)

Vậy \(S=\left\{0\right\}\)

g) \(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=\dfrac{5}{3}+2x\)

\(\Leftrightarrow\dfrac{3\left(3x+2\right)-3x-1-10-12x}{6}=0\)

\(\Leftrightarrow9x+6-3x-1-10-12x=0\)

\(\Leftrightarrow-6x-5=0\)

\(\Leftrightarrow-6x=5\)

\(\Leftrightarrow x=-\dfrac{5}{6}\)

Vậy \(S=\left\{-\dfrac{5}{6}\right\}\)

h) \(2x-\left(3-5x\right)=4\left(x+3\right)\)

\(\Leftrightarrow2x-3+5x-4x-12=0\)

\(\Leftrightarrow3x-15=0\)

\(\Leftrightarrow x=5\)

Vậy \(S=\left\{5\right\}\)

i) \(3x-6+x=9-x\)

\(\Leftrightarrow3x-6+x-9+x=0\)

\(\Leftrightarrow5x-15=0\)

\(\Leftrightarrow x=3\)

Vậy \(S=\left\{3\right\}\)

k)\(2t-3+5t=4t+12\)

\(\Leftrightarrow2t-3+5t-4t-12=0\)

\(\Leftrightarrow3t-15=0\)

\(\Leftrightarrow t=5\)

Vậy \(S=\left\{5\right\}\)

Hà Giang
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Phạm Ngân Hà
14 tháng 1 2017 lúc 20:09

1) = 35 . 18 - 35 . 18 = 0

2) = 45 - 5 . 12 + 5 . 9 = 45 - 60 + 45 = 30

3) = 24 . 16 - 24 . 5 - 16 . 24 - 16 . 5

= (24 . 16 - 16 . 24) - 5 (24 - 16)

= 0 - 5 . 8 = 0 - 40 = -40

4) = 29 . 19 - 29 . 13 - 19 . 29 - 19 . 13

= (29 . 19 - 29 . 19) - 13 (29 - 19)

= 0 - 13 . 10 = 0 - 130 = -130

5) = 31 . (-18) + 31 . (-81) - 31 . 1

= 31 [(-18) + (-81) - 1]

= 31 . (-100) = -3100

6) = (-12) . 47 + (-12) . 52 + (-12). 1

= (-12) . (47 + 52 + 1)

= (-12) . 100 = -1200

7) = 13 . 45 - 3 . 45

= 45 (13 - 3)

= 45 . 10 = 450

8) = (-48) + 48 . (-78) + 48 . (-21)

= (-48) . 1 + 48 . (-78) + 48 . (-21)

= 48 . (-1) + 48 . (-78) + 48 . (-21)

= 48 . [(-1) + (-78) + (-21)]

= 48 . (-100) = -4800

Nanami Luchia
18 tháng 1 2017 lúc 21:40

1) 35x18-5x7x18

= 35x18-35x18

= 35x(18-18)

= 35x0=0

3) 24.(16-5)-16.(24-5)

= 24.16-24.5-16.24-16.5

=[24.16-16.24]-[24.5-16.5]

= [ 24. (16-16)]- [(24-16).5]

= [24.0]-[8.5]

= 0-40=-40

4) 29.(19-13)-19.(29-13)

=29.19-29.13-19.29-19.13

=[ 29.19-19.29]-[ 29.13-19.13]

= [ 29.(19-19)]-[(29-19).13]

=[29.0]-[10.13]

= 0-130= -130

5) 31.(-18)+31.(-81)-31

= 31.(-18)+31.(-81)-31.1

= 31.[(-18)+(-81)-1]

=31.(-100)

= -3100

6);7);8 tương tự 4);5);6)

billionaire
15 tháng 3 2020 lúc 9:37
https://i.imgur.com/3KboyRE.jpg
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Lương Thị Quỳnh Trang
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Lương Thị Quỳnh Trang
15 tháng 8 2017 lúc 20:02

Ai lm hộ mk nha

Quang Duy
15 tháng 8 2017 lúc 20:12

Nhiều quá bạn ơi

Quang Duy
15 tháng 8 2017 lúc 20:33

1.\(x-43=\left(35-x\right)-48\)

\(\Rightarrow x-43=35-x-48\)

\(\Rightarrow2x=35+43-48\)

\(\Rightarrow2x=30\)

\(\Rightarrow x=15\)

2.\(305-x+14=48+\left(x-23\right)\)

\(\Rightarrow305-x+14=48+x-23\)

\(\Rightarrow305+14=48+x+x-23\)

\(\Rightarrow2x+25=319\)

\(\Rightarrow2x=294\)

\(\Rightarrow x=147\)

3.\(-\left(x-6+85\right)=\left(x+51\right)-54\)

\(\Rightarrow-x+6-85=x+51-54\)

\(\Rightarrow6-85=x+x+51-54\)

\(\Rightarrow2x-3=-79\)

\(\Rightarrow2x=-76\)

\(\Rightarrow x=-38\)

4.\(-\left(35-x\right)-\left(37-x\right)=33-x\)

\(\Rightarrow-35+x-37+x=33-x\)

\(\Rightarrow2x-72=33-x\)

\(\Rightarrow3x=105\)

\(\Rightarrow x=35\)

5.\(13-\left|x\right|=\left|-4\right|\)

\(\Rightarrow13-\left|x\right|=4\)

\(\Leftrightarrow\left[{}\begin{matrix}13-x=4\\13+x=4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=9\\x=-9\end{matrix}\right.\)

Ngô Hải Long
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34. Đỗ Thiện Nhân
17 tháng 1 2022 lúc 10:05

562 HT

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Nguyễn Minh Tuấn
15 tháng 5 2023 lúc 21:35

😒😒😒

Nguyễn Minh Tuấn
15 tháng 5 2023 lúc 21:36

Trê 

Uyen Nguyen
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