Cân bằng các phản ứng sau theo phương pháp electron:
1. SO2 + H2S \(\rightarrow\) S + H2O
2. Al + Fe3O4 \(\rightarrow\) Al2O3 + Fe
3. SO2 + Cl2 + H2O \(\rightarrow\) H2SO4 + HCl
4. MnO2 + HCl \(\rightarrow\) MnCl2 + Cl2 + H2O
5. Cu + HNO3 \(\rightarrow\) Cu(NO3)2 + NO2 + H2O
6. Mg + H2SO4(n) \(\rightarrow\) MgSO4 + S + H2O
7*. FeSO4 + KMnO4 + H2SO4 \(\rightarrow\) Fe2(SO4)3 + MnSO4 + K2SO4 + H2O
8*. H2S + KMnO4 + H2SO4 \(\rightarrow\) MnSO4 + K2SO4 + S\(\downarrow\) + H2O
Hoàn thành chuỗi phản ứng trcacs phương trình
1 Mno\(_2\) \(\rightarrow Cl_2\rightarrow HCl\rightarrow NaCl\rightarrow Cl_2\rightarrow H_2SO_4\rightarrow HCl\)
2. \(KMnO_4\rightarrow Cl_2\rightarrow FeCl_3\rightarrow KCl\rightarrow KOH\)
3. \(HCl\rightarrow Cl_2\rightarrow FeCl_3\rightarrow NaCl\rightarrow HCl\rightarrow CuCl_2\rightarrow AgCl\)
4 \(NaCl\rightarrow HCl\rightarrow Cl_2\rightarrow KClO_3\rightarrow KCl\rightarrow Cl_2\rightarrow CaOCl_2\)
1/
MnO2+ 4HCl\(\rightarrow\) MnCl2+ Cl2+ 2H2O
Cl2+H2\(\xrightarrow[]{as}\) 2HCl
HCl+ NaOH\(\rightarrow\) NaCl+ H2O
2NaCl\(\xrightarrow[]{đpnc}\) 2Na+ Cl2
Cl2+ SO2+ 2H2O\(\rightarrow\) H2SO4+ 2HCl
H2SO4 đặc+ NaCltinh thể\(\xrightarrow[]{< 250\cdot C}\) NaHSO4+ HCl
4/
H2SO4 đặc+ NaCltinh thể\(\xrightarrow[]{< 250\cdot C}\) NaHSO4+ HCl
MnO2+ 4HCl\(\rightarrow\) MnCl2+ Cl2+ 2H2O
3Cl2+ 6KOHđặc\(\rightarrow\) KClO3+ 5KCl+ 3H2O
2KClO3\(\xrightarrow[MnO2]{to}\) 2KCl+ 3O2
2KCl\(\xrightarrow[]{đpnc}\) K+ Cl2
Cl2+ Ca(OH)2\(\xrightarrow[]{30\cdot C}\) CaOCl2+ H2O
1, \(MnO_2+4HCl\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\)
\(Cl_2+H_2\underrightarrow{as,t^o}2HCl\)
\(HCl+NaOH\rightarrow NaCl+H_2O\)
\(2NaCl+2H_2O\xrightarrow[cmn]{đpdd}2NaOH+Cl_2+H_2\)
\(4Cl_2+4H_2O+H_2S\rightarrow H_2SO_4+8HCl\)
\(H_2SO_4+NaCl\underrightarrow{>400^oC}Na_2SO_4+HCl\uparrow\)
2, \(2KMnO_4+18HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\)
\(3Cl_2+2Fe\underrightarrow{t^o}2FeCl_3\)
\(FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3\downarrow+3KCl\)
\(2KCl+2H_2O\xrightarrow[cmn]{đpdd}2KOH+Cl_2+H_2\)
3, \(4HCl+MnO_2\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\)
\(3Cl_2+2Fe\underrightarrow{t^o}2FeCl_3\)\(FeCl_3+3NaOH\rightarrow3NaCl+Fe\left(OH\right)_3\downarrow\)
\(2NaCl+H_2SO_4\underrightarrow{>400^oC}Na_2SO_4+2HCl\)
\(2HCl+Cu\left(OH\right)_2\rightarrow CuCl_2+2H_2O\)
\(CuCl_2+2AgNO_3\rightarrow Cu\left(NO_3\right)_2+2AgCl\downarrow\)
4, \(H_2SO_4+2NaCl\underrightarrow{>400^oC}Na_2SO_4+2HCl\uparrow\)
\(4HCl+MnO_2\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\)
\(3Cl_2+6KOH\underrightarrow{80-100^oC}5KCl+KClO_3+3H_2O\)
\(2KClO_3\underrightarrow{t^o}2KCl+3O_2\)
\(2KCl+2H_2O\xrightarrow[cmn]{đpdd}2KOH+Cl_2+H_2\)
\(Cl_2+Ca\left(OH\right)_2\underrightarrow{30^oC}CaOCl_2+H_2O\)
Bạn tham khảo nhé!
1.
\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+H_2O\)
\(Cl_2+H_2\underrightarrow{^{to}}2HCl\)
\(NaOH+HCl\rightarrow NaCl+H_2O\)
\(2NaCl\underrightarrow{^{đpnc}}2Na+Cl_2\)
\(Cl_2+SO_2+2H_2O\rightarrow2HCl+H_2SO_4\)
\(NaCl+H_2SO_{4_đ}\underrightarrow{^{to}}NaHSO_4+HCl\)
2.
\(2KMnO_4+16HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\)
\(2Fe+3Cl_2\underrightarrow{^{to}}2FeCl_3\)
\(FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3+3KCl\)
\(2KCl+2H_2O\underrightarrow{^{đpmn}}2KOH+H_2+Cl_2\)
3.
\(MnO_2+4HCl\underrightarrow{^{to}}MnCl_2+Cl_2+2H_2O\)
\(2Fe+3Cl_2\underrightarrow{^{to}}2FeCl_3\)
\(FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\)
\(NaCl+H_2SO_{4_Đ}\underrightarrow{^{to}}NaHSO_4+HCl\)
\(CuO+2HCl\rightarrow CuCl_2+H_2O\)
\(CuCl_2+2AgNO_3\rightarrow2AgCl+Cu\left(NO_3\right)_2\)
4.
\(NaCl+H_2SO_{4_Đ}\underrightarrow{^{to}}NaHSO_4+HCl\)
\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O\)
\(3Cl_2+6KOH\underrightarrow{^{to}}5KCl+KClO_3+3H_2O\)
\(KClO_3+6HCl\rightarrow KCl+3Cl_2+3H_2O\)
\(Cl_2+CaO\underrightarrow{^{to}}CaOCl_2\)
Câu 4. Viết PTHH thực hiện sơ đồ chuyển hóa sau
a) HCl \(\rightarrow\) Cl2 \(\rightarrow\) FeCl3 \(\rightarrow\) NaCl \(\rightarrow\) HCl --> CuCl2 --> AgCl
b) KMnO4\(\rightarrow\)Cl2\(\rightarrow\)HCl \(\rightarrow\)FeCl3 \(\rightarrow\) AgCl\(\rightarrow\) Cl2\(\rightarrow\)Br2\(\rightarrow\)I2\(\rightarrow\)ZnI2 \(\rightarrow\)Zn(OH)2
c) KCl\(\rightarrow\) Cl2\(\rightarrow\)KClO\(\rightarrow\)KClO3\(\rightarrow\)KClO4\(\rightarrow\)KCl\(\rightarrow\)KNO3
d) Cl2\(\rightarrow\)KClO3\(\rightarrow\)KCl\(\rightarrow\) Cl2\(\rightarrow\)Ca(ClO)2\(\rightarrow\)CaCl2\(\rightarrow\)Cl2\(\rightarrow\)O2
e) KClO3 \(\rightarrow\) Cl2 \(\rightarrow\) KClO3 \(\rightarrow\) KCl \(\rightarrow\) Cl2 \(\rightarrow\) HCl \(\rightarrow\) FeCl2 \(\rightarrow\) FeCl3 \(\rightarrow\) Fe(OH)3
a) 4HCl + MnO2 --> MnCl2 + Cl2 +2H2O
2Fe + 3Cl2 ---> 2FeCl3
FeCl3 + 3NaOH --> Fe(OH)3 + 3NaCl
NaCl + H2SO4 đ---> NaHSO4 + HCl
2HCl + CuO ---> CuCl2 + H2O
CuCl2 +2AgNO3 ---> Cu(NO3)2 + 2AgCl
b) 2KMnO4 + 16HCl ---> 2KCl + 2MnCL2 +5Cl2 +8H2O
Cl2 + H2--->2HCl
6HCl + Fe2O3 ---> 2FeCl3 +3H2O
FeCl3 + 3AgNO3 --> Fe(NO3)3 +3AgCl
2AgCl --to---> 2Ag + Cl2
Cl2 + 2NaBr ---> 2NaCl + Br2
Br2 + 2NaI --> 2NaBr + I2
I2 +Zn --to--> ZnI2
ZnI2 + 2NaOH --> Zn(OH)2 +2NaI
c) 2KCl ---dpnc--> 2K + Cl2
Cl2 + 2KOH --> KCl + KClO + H2O
4KClO --> KClO3 +3 KCl
4KClO3 ---> 3KClO4 + KCl
3KClO4 + 8Al ---> 4Al2O3 + 3KCl
KCl + AgNO3 --> AgCl + KNO3
d) 3Cl2 + 6KOH ---> KClO3 + 5KCl +3H2O
2KClO3 ---> 2KCl +#O2
2KCl --> 2K + Cl2
2Cl2 + Ca(OH)2 ---> CaCl2 +Ca(ClO)2
Ca(ClO)2 ---> CaCl2 + O2
CaCl2 ---> Ca + Cl2
Cl2 ra O2 ????
e)6HCl + KClO3 ---> KCl +3Cl2 +3H2O
3Cl2 +6KOH --> 5KCl + KClO +3 H2O
2KClO3 --> 2KCl + 3O2
2KCl --> 2K + CL2
CL2 +H2 --> 2HCl
2HCl +Fe--> FeCl2 + H2
Cl2 + 2FeCl2 -->2FeCl3
FeCl3 +3NaOH --> Fe(OH)3 +3NaCl
Câu 1 : Hoàn thành sơ đồ phản ứng
a , MnO2 \(\rightarrow\)Cl2\(\rightarrow\) HCl\(\rightarrow\)NaCl\(\rightarrow\)Cl2\(\rightarrow\)H2SO4\(\rightarrow\)HCl
b , BaCl2\(\rightarrow\)Cl2\(\rightarrow\)HCl\(\rightarrow\)FeCl2\(\rightarrow\)FeCl3\(\rightarrow\)BaCl2\(\rightarrow\)HCl
c , BaCl2\(\rightarrow\)HCl\(\rightarrow\)CuCl2\(\rightarrow\)KCl\(\rightarrow\)KOH\(\rightarrow\)KClO3\(\rightarrow\)Cl2
a) (1) MnO2 + 4 HCl(đặc) -to-> MnCl2 + Cl2 + 2 H2O
(2) Cl2 + H2 \(\Leftrightarrow\) 2 HCl
(3) HCl + NaOH -> NaCl + H2O
(4) 2 NaCl + 2 H2O -đpddcmnx-> 2 NaOH + H2 + Cl2
(5) Cl2 + 2 H2O + SO2 -> H2SO4 + 2 HCl
(6) H2SO4 + BaCl2 -> BaSO4 + 2 HCl
b)
(1) BaCl2 -điện phân nóng chảy nhiệt độ cao-> Ba + Cl2
(2) Cl2 + H2 \(\Leftrightarrow\) 2 HCl
(3) Fe + 2 HCl -> FeCl2 + H2
(4) 2 FeCl2 + Cl2 -to-> 2 FeCl3
(5) 2 FeCl3 + 3 Ba(OH)2 -> 2 Fe(OH)3 +3 BaCl2
(6) BaCl2 + H2SO4 -> BaSO4 + 2 HCl
c) (1) BaCl2 + H2SO4 -> BaSO4 +2 HCl
(2) 2 HCl + CuO -> CuCl2 + H2O
(3) CuCl2 + 2 KOH -> Cu(OH)2 + 2 KCl
(4) KCl + H2O -đpddcmnx-> KOH + 1/2 Cl2 + 1/2 H2
(5) 6 KOH + 3 Cl2 -to->5 KCl + KClO3 +3 H2O
(6) 2 KClO3 -to-> 2 KCl + 3 O2
a)
(1) MnO2 + 4HCl(đ) -to-> MnCl2 + Cl2 + 2H2O
(2) Cl2 + H2 <-as-> 2 HCl
(3) HCl + NaOH => NaCl + H2O
(4) 2NaCl + 2H2O -đpddcmn-> 2NaOH + H2 + Cl2
(5) Cl2 + 2H2O + SO2 => H2SO4 + 2HCl
(6) H2SO4 + BaCl2 => BaSO4 + 2HCl
b)
(1) BaCl2 -đpdd-> Ba + Cl2
(2) Cl2 + H2 ⇔ 2HCl (Đk : ánh sáng hoặc nhiệt độ)
(3) Fe + 2HCl => FeCl2 + H2
(4) 2FeCl2 + Cl2 -to-> 2FeCl3
(5) 2FeCl3 + 4Ba(OH)2 => 2Fe(OH)3 + 3BaCl2
(6) BaCl2 + H2SO4 => BaSO4 + 2HCl
c)
(1) BaCl2 + H2SO4 => BaSO4 +2HCl
(2) 2HCl + CuO => CuCl2 + H2O
(3) CuCl2 + 2KOH => Cu(OH)2 + 2KCl
(4) 2KCl + 2H2O -đpddcmn-> 2KOH + Cl2 + H2
(5) 6KOH + 3Cl2 -to-> 5KCl + KClO3 +3H2O
(6) 2KClO3 -to-> 2KCl + 3O2
Cân bằng pt sau:
1, Fe2SO4 + KMnO4 + H2SO4 \(\rightarrow\) Fe2(SO4)3+K2SO4 + MnSO4 + H2O
2, HCl + K2Cr2O7 \(\rightarrow\)KCl + CrCl3 + Cl2 + H2O
3, Mg + HNO3 \(\rightarrow\) Mg(NO3)2 + N2O + H2O
4, CuFeS2 + H2SO4 \(\rightarrow\) CuSO4 + Fe2(SO4)3 +SO2 + H2O
1, 10FeSO4 + 2KMnO4 + 8H2SO4 \(\rightarrow\) 5Fe2(SO4)3 + K2SO4 + 2MnSO4 + 8H2O
2, 14HCl + K2Cr2O7 \(\rightarrow\)2KCl + 2CrCl3 + 3Cl2 + 7H2O
3, 8Mg + 20HNO3 \(\rightarrow\) 8Mg(NO3)2 + 2N2O + 10H2O
4, 2CuFeS2 + 18H2SO4 \(\rightarrow\) 2CuSO4 + Fe2(SO4)3 +17SO2 + 18H2O
Chúc bạn học tốt 
Câu nào ko biết vào đây nhé bạn:chemistry
Thực hiện chuyển hóa:
\(a)K\rightarrow KO_2\rightarrow KOH\rightarrow K_2SO_4\rightarrow KCl\rightarrow KNO_3\)
\(b)K\rightarrow KOH\)
\(c)Ba\rightarrow BaO\rightarrow Ba\left(OH\right)_2\rightarrow BaCO_3\rightarrow BaO\rightarrow Ba\left(OH\right)_2\rightarrow Cu\left(OH\right)_2\rightarrow CuO\rightarrow Cu\rightarrow SO_2\)
Chọn các chất X1,X2,X3...X20( có thể trùng lặp giữa các pt) để hoàn thành các pthh sau:
1. X1+X2\(\underrightarrow{t0}\)Cl2 +MnCl2+KCl+H2O
2. X3+X4+X5\(\rightarrow\)HCl+H2SO4
3. X6+X7dư\(\underrightarrow{t0}\)SO2+H2O
4. X8+X9+X10\(\rightarrow\)Cl2 +MnSO4+K2SO4+Na2SO4+H2O
5. KHCO3+ Ca(OH)2 dư\(\rightarrow\)X11+X12+X13
6. Al2O3+KHSO4\(\rightarrow\)X14+X15+X16
7.X17+X18\(\rightarrow\)BaCO3+CaCO3+H20
8. X19+X20+H2O\(\rightarrow\)Fe(OH)3 + CO2+NaCl
1.X1:KMnO4 X2:HCl
2.X3:SO2 X4:Cl2 X5:H2O
3.X6:H2S X7:O2
4.X8:NaCl X9:KMnO4 X10:H2SO4
5.X11:K2CO3 X12:CaCO3 X13 H2O
6.X14:Al2(SO4)3 X15:K2SO4 X16:H2O
7.X17:Ba(HCO3)2 X18:Ca(OH)2
8.X19:Na2CO3 X20:FeCl3 X21:H2O
hoàn thành chuổi phản ứng
a)\(HCl\rightarrow Cl_2\rightarrow FeCl_3\rightarrow NaCl\rightarrow HCl\rightarrow CuCl_2\rightarrow AgCl\)
b)\(KMnO_4\rightarrow Cl_2\rightarrow HCl\rightarrow FeCl_3\rightarrow AgCl\rightarrow Cl_2\rightarrow Br_2\rightarrow I_2\)
c)\(KMnO_4\rightarrow Cl_2\rightarrow HCl\rightarrow FeCl_2\rightarrow AgCl\rightarrow Ag\)
d)\(HCl\rightarrow Cl_2\rightarrow FeCl_3\rightarrow Fe\left(OH\right)_3\rightarrow Fe_2\left(SO_4\right)_3\)
e)\(HCl\rightarrow Cl_2\rightarrow NaCl\rightarrow HCl\rightarrow CuCl_2\rightarrow AgCl\rightarrow Ag\)
f)\(MnO_2\rightarrow Cl_2\rightarrow KClO_3\rightarrow KCl\rightarrow HCl\rightarrow Cl_2\rightarrow Clorua\) vôi
phương trình nào lặp lại khỏi viết cũng được nha mọi người. Mình đang khá cần trợ giúp của mấy bạn!!@
Tự cân bằng nhá!
a,
\(HCl+MnO_2\rightarrow MnCl_2+Cl_2+H_2O\\
Cl_2+Fe\rightarrow FeCl_3\\
FeCl_3+NaOH\rightarrow Fe\left(OH\right)_3+NaCl\\
NaCl+H_2SO_{4\left(dn\right)}\rightarrow Na_2SO_4+HCl\\
HCl+CuO\rightarrow CuCl_2+H_2O\\
CuCl_2+AgNO_3\rightarrow Cu\left(NO_3\right)_2+AgCl\)
b,
\(KMnO_4+HCl\rightarrow KCl+MnCl_2+Cl_2+H_2O\\ Cl_2+H_2\rightarrow HCl\\ HCl+Fe\left(OH\right)_3\rightarrow FeCl_3+H_2O\\ FeCl_3+AgNO_3\rightarrow Fe\left(NO_3\right)_3+AgCl\\ AgCl-as,t^o->Ag+Cl_2\\ Cl_2+NaBr\rightarrow NaCl+Br_2\\ Br_2+NaI\rightarrow NaBr+I_2\)
c, Giống câu b 3 pt đầu
\(HCl+Fe\left(OH\right)_2\rightarrow FeCl_2+H_2O\\
FeCl_2+AgNO_3\rightarrow Fe\left(NO_3\right)_2+AgCl\\
AgCl-as,t^o->Ag+Cl_2\)
d,
\(HCl+MnO_2\rightarrow MnCl_2+Cl_2+H_2O\\
Cl_2+Fe\rightarrow FeCl_3\\
FeCl_3+NaOH\rightarrow Fe\left(OH\right)_3+NaCl\\
Fe\left(OH\right)_3+H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+H_2O\)
e,
\(HCl+MnO_2\rightarrow MnCl_2+Cl_2+H_2O\\
Cl_2+NaOH\rightarrow NaCl+NaClO+H_2O\\
NaCl+H_2SO_{4\left(dn\right)}\rightarrow Na_2SO_4+HCl\\
CuO+HCl\rightarrow CuCl_2+H_2O\\
CuCl_2+AgNO_3\rightarrow Cu\left(NO_3\right)_2+AgCl\\
AgCl-as,t^o->Ag+Cl_2\)
f,
\(MnO_2+HCl\rightarrow MnCl_2+Cl_2+H_2O\\ Cl_2+KOH-t^o->KClO_3+KCl+H_2O\\ KClO_3\rightarrow KCl+O_2\\ KCl+H_2SO_{4\left(dn\right)}\rightarrow K_2SO_4+HCl\\ HCl+MnO_2\rightarrow MnCl_2+Cl_2+H_2O\\ Ca\left(OH\right)_2+Cl_2\rightarrow CaCl_2+Ca\left(ClO\right)_2+H_2O\)
a)
KMnO4 \(\rightarrow\) Cl2 \(\rightarrow\) HCl \(\rightarrow\) NaCl \(\rightarrow\)AgCl
NaClO \(\leftrightarrow\) Cl2 \(\rightarrow\) FeCl3 \(\leftarrow\) FeCl2 \(\leftarrow\) HCl
b) KI \(\rightarrow\) I2 \(\rightarrow\) HI \(\rightarrow\) HCl \(\rightarrow\)KCl \(\rightarrow\)Cl2 \(\rightarrow\) HClO \(\rightarrow\)O2 \(\rightarrow\)Cl2 \(\rightarrow\)Br2 \(\rightarrow\)I2
b, PTHH :
\(2KI+SO_3\rightarrow2I+K_2SO_3\)
\(I_2+H_2\rightarrow2HI\)
\(2HI+Cl_2\rightarrow2HCl+I_2\)
\(HCl+KOH\rightarrow KCl+H_2O\)
\(F_2+2KCl\rightarrow Cl_2+2KF\)
\(Cl_2+H_2O\rightarrow HClO+HCl\)
\(HClO\rightarrow HCl+O_2\)
\(4HCl+O_2\rightarrow2H_2O+2Cl_2\)
\(Cl_2+2NaBr\rightarrow2NaCl+Br_2\)
\(Br_2+2NaI\rightarrow2NaBr+I_2\)
