tìm x biết
a) (3x-1)2 - (x+3)3 = (2-x) (x2 + 2x +4)
b) ( x +1)(x2 +1) (x-1) - (x2 - 1)2 = 2
c) x2 - 2\(\sqrt{3x}\) + 3 = 0
d) ( x- \(\sqrt{2}\) ) ( x + \(\sqrt{2}\) ) - ( x - \(\sqrt{2}\) ) 2 = 0
e) (2x-3)2 - (3x-2)2= 0
f) \(\dfrac{3}{4}\left(2x+1\right)^2-\dfrac{1}{3}=0\)