1.I think you ought to give up playing video games. (should)

-->I think you should give up playing video games.

2.It's necessary for me to finish the work on time. (have to)

--->I have to finish the work on time.

3.It wasn't necessary for you to clean that car. (have to)

--->You didn't have to clean that car.

4.It was quite unnecessary for you to adopt a green lifestyle. (have to)

---->You didn't have to adopt a green lifestyle.

5.It was careless of you to leave the windows open last night. (shouldn't)

----->You shouldn't have left the windows open last night.

6.It is advisable for each member in the family to share the housework equally. (should)

---->Each member in the family should share the housework equally.

7.You are required to come back home before 10 p.m. (must)

--->You must come back home before 10 p.m.

8.Lina is advised to prepare carefully in the morning. (should)

----->Lina should prepare carefully in the morning.

9.Tu is responsible for picking up litter. (have to)

------>Tu has to pick up litter.

1.You are required to ask your parents for permission before staying out late. (must)

You must ask your parents for permission before staying out late.

2.I think you ought to give up smoking immediately. (should)

I think you should give up smoking immediately.

3.It is not a good idea for me to stay up late. (shouldn't)

I shouldn't stay up late.

4.It wasn't necessary for you to send these letters. (have to)

You didn't have to send these letters.

5.It was unnecessary for Tim to finish the work. (have to)

Tim didn't have to finish the work.

6.It was careless of you to leave your children alone at home. (shouldn't)

You shouldn't have left your children alone at home.

Bằng 1 cách nào đó 1 câu hỏi từ 2023 ở đây và tôi vẫn trả lời nó sau 1 năm :v

PTHH : 2Al     +     6HCl  --> 2AlCl3   +    3H2 ↑   (1)

n_AlCl3 = \(\dfrac{m}{M}=\dfrac{13,35}{27+35,5.3}=0.1\left(mol\right)\) 

Từ (1) => n_HCl   =   2n_H2  = 0.2 (mol)

=> m_HCl = n.M  =  0.2 x  36.5 = 7.3 (g)

\(PTHH:2Al+6HCl\rightarrow2AlCl_3+3H_2\\ n_{AlCl_3}=\dfrac{m}{M}=\dfrac{13,35}{133,5}=0,1\left(mol\right)\\ Theo.PTHH:n_{HCl}=3.n_{AlCl_3}=3.0,1=0,3\left(mol\right)\\ m_{HCl}=n.M=0,3.36,5=10,95\left(g\right)\)

`81^8=3^x`

`=>3^x=(3^4)^8`

`=>3^x=3^32`

`=>x=32`

Vậy `x=32`

x=32

\(81^8=3^x\)

\(\Leftrightarrow\left(3^4\right)^8=3^x\)

\(\Leftrightarrow3^{32}=3^x\)

\(\Leftrightarrow x=32\)

Câu 3: 

a: \(BD=\sqrt{BC^2-DC^2}=4\left(cm\right)\)

b: \(\widehat{A}=180^0-2\cdot70^0=40^0< \widehat{B}\)

nên BC<AC=AB

c: Xét ΔEBC vuông tại E và ΔDCB vuông tại D có

BC chung

\(\widehat{EBC}=\widehat{DCB}\)

Do đó:ΔEBC=ΔDCB

d: Xét ΔOBC có \(\widehat{OBC}=\widehat{OCB}\)

nên ΔOBC cân tại O

Câu 2

a) Thay y = -2 vào biểu thức đã cho ta được:

2.(-2) + 3 = -1

Vậy giá trị của biểu thức đã cho tại y = -2 là -1

b) Thay x = -5 vào biểu thức đã cho ta được:

2.[(-5)² - 5] = 2.(25 - 5) = 2.20 = 40

Vậy giá trị của biểu thức đã cho tại x = -5 là 40

Đăng lại vì ko ai giải 🥺

thôi bọn mềnh cũng chệu boạn nhóe

III. 

A. 

1. B

2. C

3. B

4. A

5. D

B. 

1. C

2. B

3. B

4. A

5. C

1 b c b a d

2 c b b a c nha

Đề dài thế này sao giải thích nhanh cho e đc

Part 1

1 C

2 B

3 D

4 C

5 B

6 A

Part 2

1 T

2 F

3 F

4 F

V

1 That old house has just been bought

2 If he doesn't take these pills, he won't be better

3 I suggest taking a train

4 Spending the weekend in the countryside is very wonderful

nhiều thật đấy

Lời giải:

$(x-15)-x.13=0$

$x-15-x.13=0$

$(x-x.13)-15=0$

$x(1-13)-15=0$

$x.(-12)-15=0$

$x.(-12)=15$

$x=15:(-12)=\frac{-5}{4}$

A = 1/(5.6) + 1/(6.7) + ... + 1/(24.25)

= 1/5 - 1/6 + 1/6 - 1/7 + ... + 1/24 - 1/25

= 1/5 - 1/25

= 4/25

B = 2/(1.3) + 2/(3.5) + 2/(5.7) + ... + 2/(99.101)

= 1 - 1/3 + 1/3 - 1/5 + 1/5 - 1/7 + ... + 1/99 - 1/101

= 1 - 1/101

= 100/101

`a) A = 1/(5.6) + 1/(6.7)+...+1/(24.25)`

`= 1/5 - 1/6 + 1/6 - 1/7 +...+1/24-1/25`

`= 1/5-1/25`

`= 5/25 - 1/25`

`= 4/25`

Vậy:`A = 4/25`

`b) B = 2/(1.3)+2/(3.5)+...+2/(99.101)`

`= 1- 1/3 + 1/3 - .... +1/99-1/101`

`= 1 - 1/101`

`= 100/101`

Vậy: `B = 100/101`