tìm x biết:
x*11,8+x*9,1=100,8
tìm chu vi hình chữ nhật có chiều rộng là 11,8 và chiều dài gấp 3 lần chiều rộng.
1: 100,8 m
2: 94,4
3: 94,1 m
4: 96m
5: 98m
Tìm x∈Z, biết:
x+x+x+81=-3-x
Tìm x,biết:
x*95+x+x:0,25=7963
`x xx 95 + x + x : 0,25 = 7963`
`x xx (95 + 1 + 4) = 7963`
`x xx 100 = 7963`
`=> x = 79,63`.
\(x\times\left(95+1+4\right)=7963\)
\(100\times x=7963\)
\(x=79,63\)
\(=>x\left(95+1+4\right)=7963\)
\(x=\dfrac{7963}{95+1+4}=\dfrac{7963}{100}=79,63\)
Tìm x ,biết:
x*95+x+x:0,25=102,34
`x xx95+x+x:0,25=102,34`
`x xx95+x+x xx4=102,34`
`x xx(95+1+4)=102,34`
`x xx100=102,34`
`x=102,34:100=1,0234`
`x xx 95 + x + x :0,25 = 102,34`
`x xx 95 + x + x xx 4 = 102,34`
`x xx ( 95+1+4)=102,34`
`x xx 100 = 102,34`
`x = 102,34 : 100`
`x = 1,0234`
`x xx95+x+x:0,25=102,34`
`x xx(95+1+4)=102,34`
`x xx100=102,34`
`x=102,34:100`
`x=1,0234`
Tìm x ,biết:
X * 45 + X +X * 54 =9872
\(x\left(45+1+54\right)=9872\)
\(x\times100=9872\)
\(x=9872:100\)
\(x=98.72\)
X x45 + X +X x 54 =9872
X x45 + Xx1 +Xx54=9872
X x ( 45 + 1 + 54) = 9872
X x 100 = 9872
X = 9872 : 100
X = 98,72
Tìm x,biết:
x(x+1)-(x-1)(x+2)=8
x(x+1)-(x-1)(x+2)=8
\(\Leftrightarrow\)\(x^2+x-x^2-2x+x+2=8\)
\(\Leftrightarrow0x=6\left(ptvn\right)\)
\(\Rightarrow S=\varnothing\)
Tìm x,biết:
x:0,25+x:0,5+x+x*93=24,6
`x:0,25+x:0,5+x+x xx93=24,6`
`x xx4+x xx2+x+x xx93=24,6`
`x xx(4+2+1+93)=24,6`
`x xx100=24,6`
`x=24,6:100`
`x=0,246`
Tìm x, biết:
x+(x+1)+(x+2)+...+(x+30)=1240
`x+(x+1)+(x+2)+...+(x+30)=1240`
`=> (x + x + x + ... + x) + (1 + 2 + 3 +... + 30) = 1240`
`=> 31x + 465 = 1240`
`=> 31 x = 1240 - 465`
`⇒ 31x = 775`
`⇒ x = 775 : 31`
`⇒ x = 25`
\(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\\ \left(x+x+...+x\right)+\left(1+2+...+30\right)=1240\\ 31x+465=1240\\ 31x=1240-465\\ 31x=775\\ x=775:31\\ x=25\)
\(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(\Leftrightarrow\left(x+x+...+x\right)+\left(1+2+...+30\right)=1240\)
\(\Leftrightarrow31x+465=1240\)
\(\Leftrightarrow x=25\)
Tìm x biết:x/125=69/115. Tìm x ?
x:125=\(\frac{69}{115}\)
x=\(\frac{69}{115}\times125\)
x=75