timf x thuộc N biết
a/ 321 + 2(x -4) = 2017
b/ 48 - 3(x +5) =24
c/1230 : 3(x-20) = 10
d/2x - 238 = 2^3 x 3^2
tìm x , biết
a) 17/6- x( x-7/6)= 7/4
b) 3/35 - ( 3/5-x)= 2/7
tìm x thuộc Z , biết
3/4-5/6 < x/12 < 1 -( 2/3-1/4)
tìm x biết
a ) 2x-3=x + 1/2
b) 4x- ( x+ 1/2) = 2x - ( 1/2 - 5 )
Bài 1:
a) Ta có: \(\dfrac{17}{6}-x\left(x-\dfrac{7}{6}\right)=\dfrac{7}{4}\)
\(\Leftrightarrow\dfrac{17}{6}-x^2+\dfrac{7}{6}x-\dfrac{7}{4}=0\)
\(\Leftrightarrow-x^2+\dfrac{7}{6}x+\dfrac{13}{12}=0\)
\(\Leftrightarrow-12x^2+14x+13=0\)
\(\Delta=14^2-4\cdot\left(-12\right)\cdot13=196+624=820\)
Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:
\(\left\{{}\begin{matrix}x_1=\dfrac{14-2\sqrt{205}}{-24}=\dfrac{-7+\sqrt{205}}{12}\\x_2=\dfrac{14+2\sqrt{2015}}{-24}=\dfrac{-7-\sqrt{205}}{12}\end{matrix}\right.\)
b) Ta có: \(\dfrac{3}{35}-\left(\dfrac{3}{5}-x\right)=\dfrac{2}{7}\)
\(\Leftrightarrow\dfrac{3}{5}-x=\dfrac{3}{35}-\dfrac{10}{35}=\dfrac{-7}{35}=\dfrac{-1}{5}\)
hay \(x=\dfrac{3}{5}-\dfrac{-1}{5}=\dfrac{3}{5}+\dfrac{1}{5}=\dfrac{4}{5}\)
Bài 3:
a) Ta có: \(2x-3=x+\dfrac{1}{2}\)
\(\Leftrightarrow2x-x=\dfrac{1}{2}+3\)
\(\Leftrightarrow x=\dfrac{7}{2}\)
b) Ta có: \(4x-\left(x+\dfrac{1}{2}\right)=2x-\left(\dfrac{1}{2}-5\right)\)
\(\Leftrightarrow3x-\dfrac{1}{2}-2x+\dfrac{1}{2}-5=0\)
\(\Leftrightarrow x=5\)
Bài 2. Tìm x, biết:
1) 48 - 3(x + 5) = 24 2) 2x - 20 = 35 : 33 | 3) 1230 : 3(x - 20) = 10 4) 390 - (x - 7) = 169 :13 |
giải giúp em với ạ
tìm số nguyên x biết
a, x/2=8/x
b,x+1/5=x+1/5
c,x+1/5=x+3/10
d,x/4=18/x+1
\(a,\dfrac{x}{2}=\dfrac{8}{x}\\ \Rightarrow x^2=16\\ \Rightarrow x=\pm4\\ b,\dfrac{x+1}{5}=\dfrac{x+1}{5}\left(luôn.đúng\right)\\ c,\dfrac{x+1}{5}=\dfrac{x+3}{10}\\ \Rightarrow\dfrac{2x+2}{10}=\dfrac{x+3}{10}\\ \Rightarrow2x+2=x+3\\ \Rightarrow2x-x=3-2\\ \Rightarrow x=1\\ d,\dfrac{x}{4}=\dfrac{18}{x+1}\\ \Rightarrow x\left(x+1\right)=4.18\\ \Rightarrow x^2+x=72\\ \Rightarrow x^2+x-72=0\\ \Rightarrow\left(x^2+9x\right)-\left(8x+72\right)=0\\ \Rightarrow x\left(x+9\right)-8\left(x+9\right)=0\\ \Rightarrow\left(x-8\right)\left(x+9\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=8\\x=-9\end{matrix}\right.\)
Bài 1: Tìm x thuộc N, biết
a) x=x mũ 5
b)x mũ 4= x mũ 2
c)(x-1)mũ 3 = x-1
Bài 2: Tìm x
(2x -1) mũ 3= 1 mũ 3+ 2 mũ 3+3 mũ 3+ 4 mũ 3+ 5 mũ 3
Bài 1
a) \(x=x^5\)
\(x^5-x=0\)
\(x\left(x^4-1\right)=0\)
\(x=0\) hoặc \(x^4-1=0\)
* \(x^4-1=0\)
\(x^4=1\)
\(x=1\)
Vậy x = 0; x = 1
b) \(x^4=x^2\)
\(x^4-x^2=0\)
\(x^2\left(x^2-1\right)=0\)
\(x^2=0\) hoặc \(x^2-1=0\)
*) \(x^2=0\)
\(x=0\)
*) \(x^2-1=0\)
\(x^2=1\)
\(x=1\)
Vậy \(x=0\); \(x=1\)
c) \(\left(x-1\right)^3=x-1\)
\(\left(x-1\right)^3-\left(x-1\right)=0\)
\(\left(x-1\right)\left[\left(x-1\right)^2-1\right]=0\)
\(x-1=0\) hoặc \(\left(x-1\right)^2-1=0\)
*) \(x-1=0\)
\(x=1\)
*) \(\left(x-1\right)^2-1=0\)
\(\left(x-1\right)^2=1\)
\(x-1=1\) hoặc \(x-1=-1\)
**) \(x-1=1\)
\(x=2\)
**) \(x-1=-1\)
\(x=0\)
Vậy \(x=0\); \(x=1\); \(x=2\)
tìm x thuộc n biết
A. 3\(^x\)=81x3
b.2\(^{x+1}\)=32
c. 3\(^{x+2}\):27=3
d. 2x2=32
e. (2x-1)4=81
f. (2x-6)4=0
a: =>3^x=3^4*3=3^5
=>x=5
b: =>\(2^{x+1}=2^5\)
=>x+1=5
=>x=4
c: \(\Leftrightarrow3^{x+2-3}=3\)
=>x-1=1
=>x=2
d: \(\Leftrightarrow x^2=\dfrac{32}{2}=16\)
=>x=4 hoặc x=-4
e: (2x-1)^4=81
=>2x-1=3 hoặc 2x-1=-3
=>2x=4 hoặc 2x=-2
=>x=-1 hoặc x=2
f: (2x-6)^4=0
=>2x-6=0
=>x-3=0
=>x=3
a) \(3^x=81\cdot3\)
\(\Rightarrow3^x=3^4\cdot3\)
\(\Rightarrow3^x=3^5\)
\(\Rightarrow x=5\)
b) \(2^{x+1}=32\)
\(\Rightarrow2^{x+1}=2^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
c) \(3^{x+2}:27=3\)
\(\Rightarrow3^{x+2}:3^3=3\)
\(\Rightarrow3^{x+2-3}=3\)
\(\Rightarrow3^{x-1}=3\)
\(\Rightarrow x-1=1\)
\(\Rightarrow x=2\)
d) \(2x^2=32\)
\(\Rightarrow x^2=16\)
\(\Rightarrow x^2=4^2\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
e) \(\left(2x-1\right)^4=81\)
\(\Rightarrow\left(2x-1\right)^4=3^4\)
\(\Rightarrow\left[{}\begin{matrix}2x-1=3\\2x-1=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=4\\2x=-2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)
f) \(\left(2x-6\right)^4=0\)
\(\Rightarrow2x-6=0\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=6:2\)
\(\Rightarrow x=3\)
\(a,3^x=81\cdot3\\ \Leftrightarrow3^x=3^4\cdot3\\ \Leftrightarrow3^x=3^5\\ \Leftrightarrow x=5\\ d,2^{x+1}=32\\ \Leftrightarrow x+1=5\\ \Leftrightarrow x=4\\ c,3^{x+2}:27=3\\ \Leftrightarrow3^{x+2}:3^3=3\\ \Leftrightarrow3^{x-1}=3\\ \Leftrightarrow x-1=1\\ \Leftrightarrow x=2\\ d,2x^2=32\\ \Leftrightarrow x^2=16\\ \Leftrightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\\ e,\left(2x-1\right)^4=81\\ \Leftrightarrow\left[{}\begin{matrix}2x-1=3\\2x-1=-3\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\\ f,\left(2x-6\right)^4=0\\ \Leftrightarrow2x-6=0\\ \Leftrightarrow x=3\)
tìm x thuộc n biết:
48-3(x+5)=24
1230:3(x-20)=10
48-3(x+5)=24 1230:3(x-20)=10
3(x+5)=48-24 3(x-20)=1203:10
3(x+5)=24 3(x-20)= 120,3
x+5=24:3 x-20=120,3:3
x+5=8 x-20=40,1
x=8-5 x=40,1+20
x=3 x=60,1
mk nghĩ thế
\(48-3\left(x+5\right)=24\)
\(-3\left(x+5\right)=48-24\)
\(-3x-15=24\)
\(-3x=24+15\)
\(-3x=39\)
\(x=-13\in N\)
\(1230:3\left(x-20\right)=10\)
\(410\left(x-20\right)=10\)
\(x-20=\frac{10}{410}\)
\(x-20=\frac{1}{41}\)
\(x=\frac{1}{41}+20\)
\(x=\frac{821}{41}\in N\)
ko bt có sai sót ko? ^ - ^ <k cho mik nhé>
48-3(x+5)=24
3(x+5)=48-24
(x+5)=24:3
x+5= 8
x=8-5
x=3
15:(x+2) = 3
20:(1+x) = 2
5(x+35) = 515
541+(218-x) = 73
1230:3 (x-20) = 10
48-3(x+5) = 24
4x + 18 : 2=13
X-48:16 = 37
1) 15:(x+2) = 3
x + 2 = 15 : 3
x + 2 = 5
x = 5 - 2
x = 3
2) 20:(1+x) = 2
1 + x = 20 : 2
1 + x = 10
x = 10 - 1
x = 9
3) 5(x+35) = 515
x + 35 = 515 : 5
x + 35 = 103
x = 103 - 35
x = 68
4) 541+(218-x) = 73
218 - x = 73 - 541
218 - x = -468
x = 218 - ( - 468 )
x = 686
5) 1230:3 (x-20) = 10
410 . ( x - 20 ) = 10
x - 20 = 10 : 410
x - 20 = 1/41
x = 1/41 + 20
x = 821/41
6) 48-3(x+5) = 24
3( x + 5 ) = 48 - 24
3( x + 5 ) = 24
x + 5 = 24 : 3
x + 5 = 8
x = 8 - 5
x = 3
7) 4x + 18 : 2=13
4x + 9 = 13
4x = 13 - 9
4x = 4
x = 1
8) X-48:16 = 37
x - 3 = 37
x = 37 + 3
x = 40
a, 15: (x+2) = 3
x+2 =15:3
x+2 = 5
x = 5-2
x = 3
b, 20: (1+x) = 2
1+x = 20:2
1+x = 10
x = 10-1
x = 9
c, 5(x+35) = 515
x+35 = 515 :5
x+35 = 103
x = 103-35
x = 68
d, 541+ (218-x) = 73
218-x = 73-541
218-x = - 468
x = 218 - (-468)
x = 218 + 468
x = 686
e, 1230:3. (x-20) = 10
410(x-20) = 10
x-20 = 10: 410
x-20 = 1/41
x = 1/41 + 20
x = 821/41
f, 48-3(x+5) = 24
3(x+5) = 48-24
3(x+5) = 24
x+5 = 24:3
x +5 = 8
x = 8-5
x =3
g, 4x + 18 : 2 = 13
4x + 9 = 13
4x = 13-9
4x = 4
x = 4:4
x = 1
j, x - 48:16 = 37
x- 3 = 37
x = 37+3
x = 40
Bai 2 timf x biết
A) -2x(x-4)=0
\(-2x\left(x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}-2x=0\\x-4=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)
\(-2x\left(x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)
tìm x biết:
a) (x-3)2-4=0
b) x2-2x=24
c) (x+4)2-(x+1)(x-1)=16
d) (2x+1)2-4(x-1)2=9
e) (x+3)2-(x-4)(x+8)=1
f) (2x-1)2+(x+3)2-5(x+7)(x-7)=0
g) 3(x+2)2+(2x-1)2-7(x+3)(x-3)=36
- Gửi lẻ câu hỏi ra nha bạn 2 3 câu 1 lần thôi .
a) (x-3)2-4=0
⇒ (x-3)2=4
⇒ hoặc x-3=2⇒x=5
hoặc x-3=-2⇒x=1
c) (x+4)2-(x+1)(x-1)=16
⇒ x2+8x+16-x2+1=16
⇒ 8x+17=16
⇒ 8x=-1
⇒ x=-1/8