x +(x 2)+ (x 3) = 20
Tìm x
x^2-16=5x+20
TÌM X
\(\Rightarrow x^2-5x-36=0\Rightarrow x\left(x-9\right)+4\left(x-9\right)=0\Rightarrow\left(x-9\right)\left(x+4\right)=0\Rightarrow\left[{}\begin{matrix}x=9\\x=-4\end{matrix}\right.\)
[(2x-11):3+1].5=20
Tìm x nha mn
\(\left[\left(2x-11\right):3+1\right].5=20\\\left(2x-11\right):3+1=20:5\\ \left(2x-11\right):3+1=4\\ \left(2x-11\right):3=4-1\\ \left(2x-11\right):3=3\\ 2x-11=3.3\\ 2x-11=9\\ 2x=11+9\\ 2x=20\\ x=20:2\\ x=10 \)
<=> (2X-11):3+1=20:5
<=> (2X-11):3=4-1
<=> 2X-11=3x3
<=> 2X-11=9
<=> 2X=9+11
<=>X=20:2
<=> X=10
(s:48)-(s:50) = 20
tìm s
`(s:48)-(s:50)=20`
`<=>s/48-s/50=20`
`<=>(25s)/1200-(24s)/1200=20`
`<=>s/1200=20`
`<=>s=24000`
Vậy `s=24000`
\(\dfrac{S}{48}-\dfrac{S}{50}=20\)
\(\Leftrightarrow\dfrac{50S-48S}{48\cdot50}=20\)
\(\Leftrightarrow2S=48\cdot50\cdot20=48000\)
\(\Leftrightarrow S=24000\)
\(\dfrac{s}{48}-\dfrac{s}{50}=20\)
\(\Leftrightarrow\dfrac{25s}{1200}-\dfrac{24s}{1200}=\dfrac{24000}{1200}\)
\(\Rightarrow s=24000\)
cho a,b,c>0 thỏa mãn a+2b+3c>=20
tìm GTNN: a+b+c+3/a+9/(2b)+4/c
đặt
\(A=a+b+c+\dfrac{3}{a}+\dfrac{9}{2b}+\dfrac{4}{c}\)
\(=>4A=4a+4b+4c+\dfrac{12}{a}+\dfrac{36}{2b}+\dfrac{16}{c}\)
\(=>4A=a+2b+3c+3a+\dfrac{12}{a}+2b+\dfrac{36}{2b}+c+\dfrac{16}{c}\)
áp dụng BDT AM-GM
\(=>\dfrac{12}{a}+3a\ge2\sqrt{12.3}=12\)
\(=>2b+\dfrac{36}{2b}\ge2\sqrt{36}=12\)
\(=>c+\dfrac{16}{c}\ge2\sqrt{16}=8\)
\(=>4A\ge20+12+12+8=52=>A\ge13\)
dấu"=" xảy ra<=>a=2,b=3,c=4
giải phương trình:
a) 2/x+1 - 1/x-3= 3x-11/x^2-2x-3
b) 3/x-2 +1/x=-2/x.(x-2)
c) x-3/x+3 - 2/x-3=3x+1/9-x^2
d) 2/x+1 - 1/x-2=3x-5/x^2-x-2
e) x-2/x+2 + 3/x-2=x^2-11/x^2-4
f) x+3/x+1 + x-2/x=2
g) x+5/x-5 - x-5/x+5=20/x^2-25
h) x+4/x+1 + x/x-1=2x^2/x^2-1
i) x+1/x-1 - 1/x+1=x^2+2/x^2-1
Tìm x biết : 6(x+2)(x-3)-3(x-2)^2-3(x-1)(x+1)=1
3(x+2)^2+(2x-1)^2-7(x+3)(x-3)=36
(x-1)(x^2+x+1)+x(x+2)(2-x)=5
(x-1)^3-(x+3)(x^2-3x+9)+3(x^2-4)=2
Tìm x biết : 6(x+2)(x-3)-3(x-2)^2-3(x-1)(x+1)=1
3(x+2)^2+(2x-1)^2-7(x+3)(x-3)=36
(x-1)(x^2+x+1)+x(x+2)(2-x)=5
(x-1)^3-(x+3)(x^2-3x+9)+3(x^2-4)=2
giải các phương trình sau
1/ ( x-2)(x-5)=(x-3)(x-4)
2/ (x-7)(x+7) +x^2 -2=2(x^2+5)
3/ (x-1)^2 +(x+3)^2 =2(x-2)(x=2)
4/ (x+1)^2= (x+3)(x-2)
5/ x^2-(2x-1)(x+3)= 3-x(5+x)
6/ 3(5-2x) -4( x+2) =5x-18
1.
$(x-2)(x-5)=(x-3)(x-4)$
$\Leftrightarrow x^2-7x+10=x^2-7x+12$
$\Leftrightarrow 10=12$ (vô lý)
Vậy pt vô nghiệm.
2.
$(x-7)(x+7)+x^2-2=2(x^2+5)$
$\Leftrightarrow x^2-49+x^2-2=2x^2+10$
$\Leftrightarrow 2x^2-51=2x^2+10$
$\Leftrightarrow -51=10$ (vô lý)
Vậy pt vô nghiệm.
3.
$(x-1)^2+(x+3)^2=2(x-2)(x+2)$
$\Leftrightarrow (x^2-2x+1)+(x^2+6x+9)=2(x^2-4)$
$\Leftrightarrow 2x^2+4x+10=2x^2-8$
$\Leftrightarrow 4x+10=-8$
$\Leftrightarrow 4x=-18$
$\Leftrightarrow x=-4,5$
4.
$(x+1)^2=(x+3)(x-2)$
$\Leftrightarrow x^2+2x+1=x^2+x-6$
$\Leftrightarrow x=-7$
5.
$x^2-(2x-1)(x+3)=3-x(5+x)$
$\Leftrightarrow x^2-(2x^2+5x-3)=3-(5x+x^2)$
$\Leftrightarro -x^2-5x+3=3-5x-x^2$ (luôn đúng)
Vậy pt có nghiệm $x\in\mathbb{R}$
6.
$3(5-2x)-4(x+2)=5x-18$
$\Leftrightarrow 15-6x-4x-8=5x-18$
$\Leftrightarrow 7-10x=5x-18$
$\Leftrightarrow 25=15x$
$\Leftrightarrow x=\frac{5}{3}$
1. (x-6)^2 = 2(x-6)
2. 2(x-3)^2 = (x-3)(x+5)
3. 4(x-3)=2x-5(2x+3)
4. x2 +4 -2 (x-1) = (x-2)^2
5. x-3/5 = 6 - 1-2x/3
6. x+2 = 6-5x/2
7. x+2/5 - x+3 = x-2/2
8. 2x-5/x-4 = 2x+1/x+2
9. X+3/x-3 - x-1/x+3 = x2 + 4x + 6/x2 -9
10. 3x-3/x2-9 -1/x-3 = x+1/x+3
11. X+1/x-1 - x-1/x+1 = 4/x2 -1
Bài dài quá, lần sau chia nhỏ câu hỏi nhé!!!!!