Tính:
\(\dfrac{1}{2\text{×}5}+\dfrac{1}{5\text{×}8}+\dfrac{1}{8\text{×}11}+...+\dfrac{1}{92\text{×}95}+\dfrac{1}{95\text{×}97}\)
Những câu hỏi liên quan
a,\(\dfrac{1}{7}\text{x}\dfrac{2}{7}+\dfrac{1}{7}\text{x}\dfrac{5}{7}+\dfrac{6}{7}\) b,\(\dfrac{6}{11}\text{x}\dfrac{4}{9}+\dfrac{6}{11}\text{x}\dfrac{7}{9}-\dfrac{6}{11}\text{x}\dfrac{2}{9}\)
c, \(\dfrac{4}{25}\text{x}\dfrac{5}{8}\text{x}\dfrac{25}{4}\text{x}24\)
`a)1/7xx2/7+1/7xx5/7+6/7`
`=1/7xx(2/7+5/7)+6/7`
`=1/7xx1+6/7`
`=1/7+6/7=1`
`b)6/11xx4/9+6/11xx7/9-6/11xx2/9`
`=6/11xx(4/9+7/9-2/9)`
`=6/11xx9/9`
`=6/11`
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Sorry nãy ghi thiếu.
`c)4/25xx5/8xx25/4xx24`
`=(4xx5xx25xx24)/(25xx8xx4)`
`=(4xx5xx24)/(4xx8)`
`=(5xx24)/8`
`=5xx3=15`
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a, \(\dfrac{1}{7}.\dfrac{2}{7}+\dfrac{1}{7}.\dfrac{5}{7}+\dfrac{6}{7}\)
\(=\dfrac{1}{7}.\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\dfrac{6}{7}\)
\(=\dfrac{1}{7}.1+\dfrac{6}{7}\)
\(=\dfrac{1}{7}+\dfrac{6}{7}=1\)
b, \(\dfrac{6}{11}.\dfrac{4}{9}+\dfrac{6}{11}.\dfrac{7}{9}-\dfrac{6}{11}.\dfrac{2}{9}\)
\(=\dfrac{6}{11}.\left(\dfrac{4}{9}+\dfrac{7}{9}-\dfrac{2}{9}\right)\)
\(=\dfrac{6}{11}.1=\dfrac{6}{11}\)
c, \(\dfrac{4}{25}.\dfrac{5}{8}.\dfrac{25}{4}.24\)
\(=\left(\dfrac{4}{25}.\dfrac{25}{4}\right).\left(\dfrac{5}{8}.24\right)\)
\(=1.15=15\)
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dfrac{text{3}}{17}text{+}dfrac{text{text{-}5}}{text{1}text{3}}text{+}dfrac{text{1}text{8}}{text{3}text{5}}text{+}dfrac{text{14}}{text{17}}text{+}dfrac{text{17}}{text{text{-}35}}text{+}dfrac{text{ }text{-}text{8}}{text{text{1}text{3}}}?dfrac{text{text{ }text{-}text{3}}}{text{8}}text{+}dfrac{text{1}text{2}}{text{25}}text{+}dfrac{text{5}}{text{-8}}text{+}dfrac{text{2}}{text{-5}}text{+}dfrac{text{1}text{3}}{text{25}}text{}text{?}text{ }text{(}dfrac{text{9}}{text{1}text{6}}text{+}dfrac{text{8}}{text{...
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\(\dfrac{\text{3}}{17}\text{+}\dfrac{\text{\text{-}5}}{\text{1}\text{3}}\text{+}\dfrac{\text{1}\text{8}}{\text{3}\text{5}}\text{+}\dfrac{\text{14}}{\text{17}}\text{+}\dfrac{\text{17}}{\text{\text{-}35}}\text{+}\dfrac{\text{ }\text{-}\text{8}}{\text{\text{1}\text{3}}}\)=?
\(\dfrac{\text{\text{ }\text{-}\text{3}}}{\text{8}}\text{+}\dfrac{\text{1}\text{2}}{\text{25}}\text{+}\dfrac{\text{5}}{\text{-8}}\text{+}\dfrac{\text{2}}{\text{-5}}\text{+}\dfrac{\text{1}\text{3}}{\text{25}}\text{=}\text{?}\)\(\text{ }\text{(}\dfrac{\text{9}}{\text{1}\text{6}}\text{+}\dfrac{\text{8}}{\text{-27}}\text{)}\text{+}\text{(}\text{1}\text{+}\dfrac{\text{7}}{\text{16}}\text{+}\dfrac{\text{-}\text{1}\text{9}}{\text{27}}\text{=}\text{?}\)
\(\dfrac{\text{4}\text{2}}{\text{46}}\text{+}\dfrac{\text{2}\text{5}\text{0}}{\text{2}\text{8}\text{6}}\dfrac{\text{-}\text{2}\text{1}}{\text{2}\text{3}\text{2}}\text{+}\dfrac{\text{-}\text{143143}}{\text{143143}}\text{=}\text{?}\)
Mọi người giúp mình với mình sắp thi rồi còn 1 ngãy nữa thôi
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Thực hiện phép tính (hợp lý nếu có thể):
\(\dfrac{\text{1}}{\text{2}}\). (\(\dfrac{\text{4}}{\text{3}}\) + \(\dfrac{\text{2}}{\text{5}}\text{ }\)) - \(\dfrac{\text{3}}{\text{4}}\text{ }\). (\(\dfrac{\text{8}}{\text{9}}\) + \(\dfrac{\text{16}}{\text{3}}\))
\(=\dfrac{2}{3}+\dfrac{1}{5}-\dfrac{2}{3}-4\)
\(=\dfrac{1}{5}-4=\dfrac{-19}{5}\)
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Tìm số thập phân x biết:a) ^{text{x}}^{ }+ dfrac{3}{4} dfrac{4}{5}b) ^{text{x}} - dfrac{1}{2} dfrac{5}{8}c) ^{text{x}} x dfrac{5}{6} dfrac{4}{5} d)^{text{x}} : dfrac{5}{8} dfrac{1}{25}
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Tìm số thập phân x biết:
a) \(^{\text{x}}\)\(^{ }\)+ \(\dfrac{3}{4}\)= \(\dfrac{4}{5}\) | b) \(^{\text{x}}\) - \(\dfrac{1}{2}\) = \(\dfrac{5}{8}\) | c) \(^{\text{x}}\) x \(\dfrac{5}{6}\) = \(\dfrac{4}{5}\) | d)\(^{\text{x}}\) : \(\dfrac{5}{8}\) = \(\dfrac{1}{25}\) |
a) \(x=0,05\)
b) \(x=1,125\)
c) \(x=0,96\)
d) \(x=0,025\)
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Bạn tự làm đi dễ mà . Cố mag vận động đầu óc đừng copy làm bài nữa khó lắm mới hỏi thôi
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1.Tính a,5text{x}dfrac{7}{3} b,dfrac{13}{4}:72.Tính a,dfrac{3}{7}+dfrac{2}{5}+dfrac{3}{4} b,dfrac{9}{7}-dfrac{5}{11}text{x}dfrac{11}{7} c,dfrac{3}{5}text{x}dfrac{5}{7}text{+}dfrac{4}{7} d,dfrac{7}{9}text{x}dfrac{2}{5}:dfrac{3}{11} e,dfrac{9}{7}+dfrac{2}{3}-dfrac{1}{4} g,dfrac{4}{9}:dfrac{3}{5}text{x}dfrac{2}{11} h,dfrac{7}{2}-dfrac{3}{10}:dfrac{2}{5}
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1.Tính
\(a,5\text{x}\dfrac{7}{3}\) \(b,\dfrac{13}{4}:7\)
2.Tính
\(a,\dfrac{3}{7}+\dfrac{2}{5}+\dfrac{3}{4}\) \(b,\dfrac{9}{7}-\dfrac{5}{11}\text{x}\dfrac{11}{7}\) \(c,\dfrac{3}{5}\text{x}\dfrac{5}{7}\text{+}\dfrac{4}{7}\) \(d,\dfrac{7}{9}\text{x}\dfrac{2}{5}:\dfrac{3}{11}\) e,\(\dfrac{9}{7}+\dfrac{2}{3}-\dfrac{1}{4}\)
g,\(\dfrac{4}{9}:\dfrac{3}{5}\text{x}\dfrac{2}{11}\) h,\(\dfrac{7}{2}-\dfrac{3}{10}:\dfrac{2}{5}\)
\(a,5x\dfrac{7}{3}=\dfrac{5}{1}x\dfrac{7}{3}=\dfrac{35}{3};b,\dfrac{13}{4}:7=\dfrac{13}{4} :\dfrac{7}{1}=\dfrac{13}{4}x\dfrac{1}{7}=\dfrac{13}{28}\)
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\(\dfrac{3}{7}+\dfrac{2}{5}+\dfrac{3}{4}=\dfrac{60}{140}+\dfrac{56}{140}+\dfrac{105}{140}=\dfrac{221}{140}\)
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\(\dfrac{9}{7}-\dfrac{5}{11}x\dfrac{11}{7}=\dfrac{9}{7}-\dfrac{5}{7}=\dfrac{4}{7}\)
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Xem thêm câu trả lời
rút gọn các biểu thức sau
\(B=\dfrac{3\text{x}^2+6\text{x}+12}{x^3-8\dfrac{ }{ }}\)
C=\(\left(\dfrac{x+1}{2\text{x}-2}+\dfrac{3}{x^2-1}-\dfrac{x+3}{2\text{x}+2}\right).\dfrac{4\text{x}^2-4}{5}\)
E=\(\dfrac{x^2-10\text{x}+25}{x^2-5\text{x}}\)
c: \(E=\dfrac{\left(x-5\right)^2}{x\left(x-5\right)}=\dfrac{x-5}{x}\)
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1. Rút gọn biểu thức A = \(\dfrac{\text{√ x + 1}}{\text{√ x − 1 }}-\dfrac{\text{√ x − 1}}{\text{√ x + 1}}+\dfrac{\text{8 √ x}}{\text{1 − x }}\)
2. Rút gọn biểu thức B = \(\dfrac{\text{√ x − x − 3}}{\text{x − 1 }}-\dfrac{\text{1}}{\text{√ x − 1 }}\) với x ≥ 0, x ≠ 1
Tính bằng cách thuận tiện nhất:
\(\left(1-\dfrac{1}{2}\right)\text{× }\left(1-\dfrac{1}{3}\right)\text{ × }\left(1-\dfrac{1}{4}\right)\text{ × }\left(1-\dfrac{1}{5}\right)\text{}\text{}\text{× }\left(1-\dfrac{1}{6}\right)\)
Lời giải:
Gọi tích trên là $A$. Ta có:
$A=\frac{1}{2}\times \frac{2}{3}\times \frac{3}{4}\times \frac{4}{5}\times \frac{5}{6}$
$=\frac{1\times 2\times 3\times 4\times 5}{2\times 3\times 4\times 5\times 6}=\frac{1}{6}$
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Thu gọn đa thức và tìm bậcA x2y + dfrac{text{1}}{text{3}}xy2 + dfrac{text{3}}{text{5}}xy2 - 2xy + 3x2y - dfrac{text{2}}{text{3}}B dfrac{text{9}}{text{5}}xy2z + 2x3y2z + dfrac{text{1}}{text{5}}xy2z - 2x3y2z - 1
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Thu gọn đa thức và tìm bậc
A= x2y + \(\dfrac{\text{1}}{\text{3}}\)xy2 + \(\dfrac{\text{3}}{\text{5}}\)xy2 - 2xy + 3x2y - \(\dfrac{\text{2}}{\text{3}}\)
B= \(\dfrac{\text{9}}{\text{5}}\)xy2z + 2x3y2z + \(\dfrac{\text{1}}{\text{5}}\)xy2z - 2x3y2z - 1
\(A=4x^2y+\dfrac{14}{15}xy^2-2xy-\dfrac{2}{3}\) bậc : 3
\(B=2xy^2z-1\) bậc :4
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+ Thu gọn :
\(A=4x^2y+\dfrac{14}{15}xy^2-2xy-\dfrac{2}{3}\)
\(B=2xy^2z-1\)
+ Bậc
Đa thức \(A\) có 4 hạng tử :
\(4x^2y\) có bậc \(3\)
\(\dfrac{14}{15}xy^2\) có bậc \(3\)
\(-2xy\) có bậc \(2\)
\(-\dfrac{2}{3}\) có bậc \(0\)
Đa thức \(B\) có \(2\) hạng tử :
\(2xy^2z\) có bậc \(4\)
\(-1\) có bậc \(0\)
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