Phân loại mỗi chất sau: \(CaO,SO_2,Na_2O,SO_3,N_2O_5,HNO_3,HNO_2,FeS.CáO_3,Fe\left(OH\right)_3,Al\left(OH\right)_3,KHCO_3,FeHPO_4.Fe\left(NO_3\right)_2,Fe\left(NO_3\right)_3,NaH_2PO_4,Na_2HPO_4\)
Cân bằng PTHH sau:
u) \(S+HNO_3\rightarrow H_2SO_4+NO\)
v) \(Ba\left(NO_3\right)_2+Al_2\left(SO_4\right)_3\rightarrow BaSO_4+Al\left(NO_3\right)_3\)
w) \(Ba\left(OH\right)_2+P_2O_5\rightarrow Ba_3\left(PO_4\right)_2+H_2O\)
x)\(Fe_2O_3+C\rightarrow Fe+CO_2\)
$\rm u)S + 2HNO_3 \rightarrow H_2SO_4 + 2NO \uparrow$
$\rm v)3Ba(NO_3)_2 + Al_2(SO_4)_3 \rightarrow 3BaSO_4 \downarrow + 2Al(NO_3)_3$
$\rm w)3Ba(OH)_2 + P_2O_5 \rightarrow Ba_3(PO_4)_3 \downarrow + 3H_2O$
$\rm x)2Fe_2O_3 + 3C \xrightarrow{t^o} 4Fe + 3CO_2 \uparrow$
\(a,Fe\rightarrow Fe\left(NO_3\right)_2\rightarrow Fe\left(OH\right)_2\rightarrow FeCl_2\rightarrow Fe\\ b,Fe\rightarrow FeCl_3\rightarrow Fe\left(NO_3\right)_3\rightarrow Fe\left(OH\right)_3\rightarrow Fe_2\left(SO_4\right)_3\)
\(a,\\ \left(1\right)Fe+Cu\left(NO_3\right)_2\rightarrow Fe\left(NO_3\right)_2+Cu\\ \left(2\right)Fe\left(NO_3\right)_2+2KOH\rightarrow Fe\left(OH\right)_2\downarrow+2KNO_3\\ \left(3\right)Fe\left(OH\right)_2+2HCl\rightarrow FeCl_2+2H_2O\)
\(\left(4\right)FeCl_2\) \(\rightarrow\left(đpdd\right)\) \(Fe+Cl_2\)
\(b,\\ \left(1\right)2Fe+3Cl_2\rightarrow\left(t^o\right)2FeCl_3\\ \left(2\right)FeCl_3+3AgNO_3\rightarrow Fe\left(NO_3\right)_3+3AgCl\downarrow\\ \left(3\right)Fe\left(NO_3\right)_3+3KOH\rightarrow Fe\left(OH\right)_3+3KNO_3\\ \left(4\right)2Fe\left(OH\right)_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+6H_2O\)
Hoàn thành các phương trình hóa học sau:
a) Fe+H2SO2\(\rightarrow Fe_2\left(SO_4\right)_3+SO_2+H_2O\)
b) \(Cu+HNO_3\rightarrow Cu\left(NO_3\right)_2+NO+H_2O\)
c) \(Fe+HNO_3\rightarrow Fe\left(NO_3\right)_3+NO+H_2O\)
d) \(Al+HNO_3\rightarrow Al\left(NO_3\right)_3+NO_2+H_2O\)
e) \(Cu+HNO_3\rightarrow Cu\left(NO_3\right)_2+NO_2+H_2O\)
a, 2Fe+6H2SO4\(\rightarrow\)Fe2(SO4)3+3SO2+6H2O
b, 3Cu+8HNO3\(\rightarrow\) 3Cu(NO3)2+2NO+4H2O
c, Fe+4HNO3\(\rightarrow\) Fe(NO3)3+NO+2H2O
d, Al+6HNO3\(\rightarrow\)Al(NO3)3+3NO2+3H2O
e, Cu+4HNO3\(\rightarrow\) Cu(NO3)2+2NO2+2H2O
Chúc bạn học tốt!
Cân bằng các PTHH sau:
\(1,FeS_2+H_2SO_4--->Fe_2\left(SO_4\right)_3+SO_2+H_2O\)
\(2,Al+H_2SO_4--->Al_2\left(SO_4\right)_3+SO_2+H_2O\)
\(3,Fe_xO_y+CO--->Fe+CO_2\)
\(4,Fe\left(NO_3\right)_3+Ba\left(OH\right)_2--->Ba\left(NO_3\right)_2+Fe\left(OH\right)_3\)
\(5,C_4H_{10}+O_2--->CO_2+H_2O\)
lưu huỳnh oxi đồng
canxi sắt
mặt trời đồng
1+1=3
hok tốt
*Hoàn thành các PTHH sau:
\(Fe+HNO_3->Fe\left(NO_3\right)_3+NO+H_2O\)
\(Fe+H_2SO_4->Fe_2\left(SO_4\right)_3+SO_2+H_2O\)
\(Al+HNO_3->Al\left(NO_3\right)_3+N_2O+H_2O\)
\(Fe+6HNO_3\rightarrow Fe\left(NO_3\right)_3+3NO_2+3H_2O\)
\(2Fe+6H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+6H_2O+3SO_2\)
\(Al+6HNO_3\rightarrow Al\left(NO_3\right)_3+3NO_2+3H_2O\)
Cân bằng các phương trình sau :
1, \(Cu+HNO_3\rightarrow Cu\left(NO_3\right)_2+NO_2+H_2O\)
2, \(Al+HNO_3\rightarrow AL\left(NO_3\right)_3+NO+H_2O\)
3, \(Al+HNO_3\rightarrow Al\left(NO_3\right)_3+NO_2+H_2O\)
4, \(Fe+H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+SO_2+H_2O\)
1) Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O
2) Al + 4HNO3 → Al(NO3)3 + NO + 2H2O
3) Al + 6HNO3 → Al(NO3)3 + 3NO2 + 3H2O
4) 2Fe + 6H2SO4 → Fe2(SO4)3 + 3SO2 + 6H2O
Viết PTHH của các chất: \(KOH;NaOH;Ca\left(OH\right)_2;Ba\left(OH\right)_2;Cu\left(OH\right)_2;Al\left(OH\right)_3;Mg\left(OH\right)_2;Zn\left(OH\right)_2;Fe\left(OH\right)_2;Fe\left(OH\right)_3\) với \(CO_2\) và \(SO_2\)
1) \(Al\xrightarrow[]{\left(1\right)}Al_2O_3\xrightarrow[]{\left(2\right)}AlCl_3\xrightarrow[]{\left(3\right)}Al\left(OH\right)_3\)
2) \(Al\xrightarrow[]{\left(1\right)}AlCl_3\xrightarrow[]{\left(2\right)}Al\left(OH\right)_3\xrightarrow[]{\left(3\right)}Al_2O_3\)
3) \(Fe\xrightarrow[]{\left(1\right)}FeSO_4\xrightarrow[]{\left(2\right)}FeCl_2\xrightarrow[]{\left(3\right)}Fe\left(OH\right)_2\xrightarrow[]{\left(4\right)}FeO\)
4) \(Fe\left(OH\right)_2\xrightarrow[]{\left(1\right)}FeO\xrightarrow[]{\left(2\right)}FeSO_4\xrightarrow[]{\left(3\right)}FeCl_2\xrightarrow[]{\left(4\right)}Fe\left(OH\right)_2\)
5) \(Fe\xrightarrow[]{\left(1\right)}FeCl_2\xrightarrow[]{\left(2\right)}Fe\left(NO_3\right)_2\xrightarrow[]{\left(3\right)}Fe\left(OH\right)_2\xrightarrow[]{\left(4\right)}FeSO_4\)
6) \(Fe\xrightarrow[]{\left(1\right)}FeCl_3\xrightarrow[]{\left(2\right)}Fe\left(OH\right)_3\xrightarrow[]{\left(3\right)}Fe_2\left(SO_4\right)_3\xrightarrow[]{\left(4\right)}FeCl_3\)
7) \(Fe\left(NO_3\right)_3\xrightarrow[]{\left(1\right)}Fe\left(OH\right)_3\xrightarrow[]{\left(2\right)}Fe_2O_3\xrightarrow[]{\left(3\right)}Fe\xrightarrow[]{\left(4\right)}FeCl_3\)
8) \(Fe_2\left(SO_4\right)_3\xrightarrow[]{\left(1\right)}Fe\left(OH\right)_3\xrightarrow[]{\left(2\right)}Fe_2O_3\xrightarrow[]{\left(3\right)}Fe_2\left(SO_4\right)_3\xrightarrow[]{\left(4\right)}FeCl_3\)
1
1)4 Al+3O2→2Al2O3
(2)Al2O3+6HCl→2AlCl3+3H2O
(3)AlCl3+3NaOH→Al(OH)3+3NaCl
2
4Al+3O2→2Al2O3
Al2O3+6HCl→2AlCl3+3H2O
AlCl3+3NaOH→Al(OH)3+3NaCl
3
Fe+H2SO4→FeSO4+H2
(2)FeSO4+BaCl2→FeCl2+BaSO4
(3)FeCl2+2NaOH→Fe(OH)2+2NaCl
(4)Fe(OH)2→FeO+H2O
4
Fe+H2SO4→FeSO4+H2
FeSO4+BaCl2→FeCl2+BaSO4
FeCl2+2NaOH→Fe(OH)2+2NaCl
Fe(OH)2→FeO+H2O
5
Fe+2HCl→FeCl2+H2
(2)FeCl2+2AgNO3→Fe(NO3)2+2AgCl
(3)Fe(NO3)2+2NaOH→Fe(OH)2+2NaNO3
(4)Fe(OH)2+MgSO4→FeSO4+Mg(OH)2
Câu 1 :
( 1 ) 4Al + 3O2 → 2Al2O3 ( Nhiệt độ )
( 2 ) Al2O3 + 6HCl → 2AlCl3 + 3H2O
( 3 ) AlCl3 + 3NaOH → Al(OH)3 + 3NaCl
Câu 2 :
( 1 ) 2Al + 6HCl → 2AlCl3 + 3H2
( 2 ) AlCl3 + 3NaOH → Al(OH)3 + 3NaCl
( 3 ) 2Al(OH)3 → Al2O3 + 3H2O ( Nhiệt độ )
Câu 3 :
( 1 ) Fe + H2SO4 → H2 + FeSO4
( 2 ) BaCl2 + FeSO4 → FeCl2 + BaSO4
( 3 ) FeCl2 + 2NaOH → NaCl + Fe(OH)2
( 4 ) Fe(OH)2 → FeO + H2O ( Nhiệt độ )
Câu 4 :
( 1 ) Fe(OH)2 → FeO + H2O ( Nhiệt độ )
( 2 ) FeO + H2SO4 → H2O + FeSO4
( 3 ) BaCl2 + FeSO4 → FeCl2 + BaSO4
( 4 ) FeCl2 + 2NaOH → NaCl + Fe(OH)2
Câu 5 :
( 1 ) Fe + 2HCl → FeCl2 + H2
( 2 ) 2AgNO3 + FeCl2 → 2AgCl + Fe(NO3)2
( 3 ) Fe(NO3)2 + NaOH → NaNO3 + Fe(OH)2
( 4 ) H2SO4 + Fe(OH)2 → 2H2O + FeSO4
Câu 6 :
( 1 ) 3Cl2 + 2Fe → 2FeCl3 ( Nhiệt độ )
( 2 ) 3NaOH + FeCl3 → 3NaCl + Fe(OH)3
( 3 ) 3H2SO4 + 2Fe(OH)3 → Fe2(SO4)3 + 6H2O
( 4 ) 3BaCl2 + Fe2(SO4)3 → 2FeCl3 + 3BaSO4
Câu 7 :
( 1 ) 3NaOH + Fe(NO3)3 → 3NaNO3 + Fe(OH)3
( 2 ) 2Fe(OH)3 → Fe2O3 + 3H2O ( Nhiệt độ )
( 3 ) 2Al + Fe2O3 → Al2O3 + 2Fe
( 4 ) 3Cl2 + 2Fe → 2FeCl3 ( Nhiệt độ )
Câu 8 :
( 1 ) Fe2(SO4)3 + 6NaOH → 3Na2SO4 + 2Fe(OH)3
( 2 ) 2Fe(OH)3 → Fe2O3 + 3H2O ( Nhiệt độ )
( 3 ) Fe2O3 + 3H2SO4 → Fe2(SO4)3 + 3H2O
( 4 ) 3BaCl2 + Fe2(SO4)3 → 2FeCl3 + 3BaSO4
Cân bằng các phương trình sau theo phương pháp thăng bằng electron:
\(1.FeO+HNO_3\rightarrow Fe\left(NO_3\right)_3+N_xO_y+H_2O\\ 2.M+HNO_3\rightarrow M\left(NO_3\right)_n+N_xO_y+H_2O\\ 3.Fe_2O_3+Al\rightarrow Fe_xO_y+Al_2O_3\\ 4.Fe_mO_n+HNO_3\rightarrow Fe\left(NO_3\right)_3+NO+H_2O\\ 5.FeS_2+HNO_3\rightarrow Fe\left(NO_3\right)_3+N_2O_x+H_2O+H_2SO_4\)
1)
(5x-2y)FeO+(16x-6y)HNO3\(\rightarrow\)(5x-2y)Fe(NO3)3+NxOy+(8x-3y)H2O
2)
(5x-2y)M+(6nx-2ny)HNO3\(\rightarrow\)(5x-2y)M(NO3)n+nNxOy+(3nx-ny)H2O
3)
3xFe2O3+(6x-4y)Al\(\rightarrow\)6FexOy+(3x-2y)Al2O3
4)
3FemOn+(12m-2n)HNO3\(\rightarrow\)3mFe(NO3)3+(3m-2n)NO+(6m-n)H2O
5)
(10-2x)FeS2+(60-6x)HNO3\(\rightarrow\)(10-2x)Fe(NO3)3+15N2Ox+(10+x)H2O+(20-4x)H2SO4