\(\dfrac{x}{7}=\dfrac{5}{4}\) giải giúp tui nha
\(\dfrac{60}{x-10}-\dfrac{60}{x}=\dfrac{3}{10}\)
Các bạn giải chi tiết chút giúp tui nha
Đáp số x=-40 em nhé, lúc nãy anh nhầm dạng =)
đk : x khác 10 ; 0
\(\Rightarrow600x-600\left(x-10\right)=3x\left(x-10\right)\)
\(\Leftrightarrow6000=3x^2-30x\Leftrightarrow x^2-10x-2000=0\Leftrightarrow x=50;x=-40\)(tm)
B1 : Tìm x,y
a) \(\dfrac{x}{-15}=\dfrac{60}{x}\)
b)\(\dfrac{-2}{x}=\dfrac{-x}{\dfrac{8}{25}}\)
c)\(\dfrac{37-x}{x+13}=\dfrac{3}{7}\)
d) \(\dfrac{x}{2}=\dfrac{y}{5}=xy=10\)
Giúp tui đi :< Tui tick
d: Đặt x/2=y/5=k
=>x=2k; y=5k
Ta có: xy=10
nên k2=1
Trường hợp 1: k=1
=>x=2; y=5
Trường hợp 2: k=-1
=>x=-2; y=-5
1)\(\dfrac{7}{12}-\left(x+\dfrac{7}{10}\right):\dfrac{6}{5}=\dfrac{-5}{4}\)
2)\(\left(5+\dfrac{4}{7}\right):x=13\)
giúp mik giải câu này với
1.Tính hợp lí
a) \(0,7+\dfrac{-7}{19}-\left(-0,3\right)\)
b) \(\dfrac{5}{3}.\left(-2,5\right):\dfrac{5}{6}\)
c) \(0,6.\dfrac{-5}{17}-\dfrac{3}{5}.\dfrac{12}{17}\)
d) \(\dfrac{7}{4}.\dfrac{5}{2}-\dfrac{7}{4}.\dfrac{3}{2}\)
Giúp tui với!
1. Tính hợp lí
a) \(0,7+\dfrac{-7}{19}-\left(-0,3\right)\)
\(=\dfrac{7}{10}+\dfrac{-7}{19}+\dfrac{3}{10}\)
\(=\left(\dfrac{7}{10}+\dfrac{3}{10}\right)+\dfrac{-7}{19}\)
\(=1+\dfrac{-7}{19}\)
\(=\dfrac{12}{19}\)
b) \(\dfrac{5}{3}.\left(-2,5\right):\dfrac{5}{6}\)
\(=\dfrac{5}{3}.\dfrac{-5}{2}.\dfrac{6}{5}\)
\(=\left(\dfrac{5}{3}.\dfrac{6}{5}\right).\dfrac{-5}{2}\)
\(=2.\dfrac{-5}{2}\)
\(=-5\)
c) \(0,6.\dfrac{-5}{17}-\dfrac{3}{5}.\dfrac{12}{17}\)
\(=\dfrac{3}{5}.\dfrac{-5}{17}-\dfrac{3}{5}.\dfrac{12}{17}\)
\(=\dfrac{3}{5}.\left(\dfrac{-5}{17}-\dfrac{12}{17}\right)\)
\(=\dfrac{3}{5}.-1\)
\(=\dfrac{-3}{5}\)
d) \(\dfrac{7}{4}.\dfrac{5}{2}-\dfrac{7}{4}.\dfrac{3}{2}\)
\(=\dfrac{7}{4}.\left(\dfrac{5}{2}-\dfrac{3}{2}\right)\)
\(=\dfrac{7}{4}.1\)
\(=\dfrac{7}{4}\)
Chúc bạn học tốt
a)
b)
c)
d)
mình giúp rùi đó nhớ tick mình nha
Rút gọn biểu thức sau: Q=(\(\dfrac{1}{2\sqrt{x}+1}+\dfrac{1}{2\sqrt{x}-1}\)):\(\dfrac{1}{1-4x}\) với x≥0,x≠\(\dfrac{1}{4}\)
giúp tui giải bài này vs tui c.ơn
\(Q=\left(\dfrac{1}{2\sqrt{x}+1}+\dfrac{1}{2\sqrt{x}-1}\right):\dfrac{1}{1-4x}\)
\(=\left(\dfrac{2\sqrt{x}-1}{\left(2\sqrt{x}+1\right)\left(2\sqrt{x}-1\right)}+\dfrac{2\sqrt{x}+1}{\left(2\sqrt{x}+1\right)\left(2\sqrt{x}-1\right)}\right).\left(1-4x\right)\)
\(=\left(\dfrac{2\sqrt{x}-1+2\sqrt{x}+1}{4x-1}\right)\left(1-4x\right)\)
\(=\dfrac{-4\sqrt{x}.\left(4x-1\right)}{4x-1}=-4\sqrt{x}\)
\(Q=\left(\dfrac{1}{2\sqrt{x}+1}+\dfrac{1}{2\sqrt{x}-1}\right):\dfrac{1}{1-4x}\left(dkxd:x\ge0;x\ne\dfrac{1}{4}\right)\)
\(=\left[\dfrac{2\sqrt{x}-1}{\left(2\sqrt{x}-1\right)\left(2\sqrt{x}+1\right)}+\dfrac{2\sqrt{x}+1}{\left(2\sqrt{x}-1\right)\left(2\sqrt{x}+1\right)}\right]\cdot\left(1-4x\right)\)
\(=\dfrac{2\sqrt{x}-1+2\sqrt{x}+1}{4x-1}\cdot\left[-\left(4x-1\right)\right]\)
\(=4\sqrt{x}\cdot\left(-1\right)\)
\(=-4\sqrt{x}\)
Giúp mik giải câu này z ạ!!
a)\(\dfrac{x-1}{1x-2}+\dfrac{5}{x+2}2=\dfrac{12}{x^2-4}+1\)
b)\(\dfrac{x-4}{5}+\dfrac{1+x}{3}=7\)
c) (3x - 7) (x + 7)=(5 +x) (3 - x)
a,sửa đề : đk x khác -2; 2
\(x^2+x-2+5x-10=12+x^2-4\)
\(\Leftrightarrow6x-20=0\Leftrightarrow x=\dfrac{10}{3}\left(tm\right)\)
b, \(3x-12+5+5x=105\Leftrightarrow8x=112\Leftrightarrow x=14\)
c, \(3x^2+14x-49=-\left(x^2+2x-15\right)\)
\(\Leftrightarrow4x^2+16x-34=0\Leftrightarrow x=\dfrac{-4\pm5\sqrt{2}}{2}\)
a. ko hỉu đề lắm :v
b.\(\dfrac{x-4}{5}+\dfrac{1+x}{3}=7\)
\(\Leftrightarrow\dfrac{3\left(x-4\right)+5\left(1+x\right)}{15}=\dfrac{105}{15}\)
\(\Leftrightarrow3\left(x-4\right)+5\left(1+x\right)=105\)
\(\Leftrightarrow3x-12+5+5x-105=0\)
\(\Leftrightarrow8x-112=0\)
\(\Leftrightarrow8x=112\)
\(\Leftrightarrow x=14\)
c.\(\left(3x-7\right)\left(x+7\right)=\left(5+x\right)\left(3-x\right)\)
\(\Leftrightarrow3x^2+21x-7x-49=15-5x+3x-x^2\)
\(\Leftrightarrow4x^2+16x-64=0\)
Nghiệm xấu lắm bạn
7 x \(\dfrac{3}{14}\) - \(\dfrac{1}{14}\) ; \(\dfrac{3}{2}\) + \(\dfrac{7}{4}\) : \(\dfrac{5}{2}\)
giúp mình nhưng làm bài này theo kiểu lớp 4 nha
a) Ta có: \(7\cdot\dfrac{3}{14}-\dfrac{1}{14}\)
\(=\dfrac{3}{2}-\dfrac{1}{14}\)
\(=\dfrac{21}{14}-\dfrac{1}{14}\)
\(=\dfrac{10}{7}\)
b) Ta có: \(\dfrac{3}{2}+\dfrac{7}{4}:\dfrac{5}{2}\)
\(=\dfrac{3}{2}+\dfrac{7}{4}\cdot\dfrac{2}{5}\)
\(=\dfrac{3}{2}+\dfrac{7}{10}\)
\(=\dfrac{15}{10}+\dfrac{7}{10}=\dfrac{22}{10}=\dfrac{11}{5}\)
Lời giải:
\(7\times \frac{3}{14}-\frac{1}{14}=\frac{7\times 3}{14}-\frac{1}{14}=\frac{21}{14}-\frac{1}{14}=\frac{21-1}{14}=\frac{20}{14}=\frac{2\times 10}{2\times 7}=\frac{10}{7}\)
\(\frac{3}{2}+\frac{7}{4}:\frac{5}{2}=\frac{3}{2}+\frac{7}{4}\times \frac{2}{5}=\frac{3}{2}+\frac{7\times 2}{4\times 5}=\frac{3}{2}+\frac{7\times 2}{2\times 2\times 5}\)
\(=\frac{3}{2}+\frac{7}{2\times 5}=\frac{3\times 5}{2\times 5}+\frac{7}{2\times 5}=\frac{3\times 5+7}{2\times 5}=\frac{22}{2\times 5}=\frac{2\times 11}{2\times 5}=\frac{11}{5}\)
a. 7 x \(\dfrac{3}{14}\) - \(\dfrac{1}{14}\)
= \(\dfrac{7}{1}\) x \(\dfrac{3}{14}\) - \(\dfrac{1}{14}\)
= \(\dfrac{98}{14}\) x \(\dfrac{3}{14}\) - \(\dfrac{1}{14}\)
= \(\dfrac{3}{2}\) - \(\dfrac{1}{14}\)
= \(\dfrac{21}{14}\) - \(\dfrac{1}{14}\)
= \(\dfrac{10}{7}\)
b. \(\dfrac{3}{2}\) + \(\dfrac{7}{4}\) : \(\dfrac{5}{2}\)
= \(\dfrac{6}{4}\) + \(\dfrac{7}{4}\) : \(\dfrac{5}{2}\)
= \(\dfrac{13}{4}\) : \(\dfrac{5}{2}\)
= \(\dfrac{13}{4}\) . \(\dfrac{2}{5}\)
= \(\dfrac{13}{10}\)
a) \(\dfrac{5}{7}\) + x =\(\dfrac{8}{9}\)
b)\(\dfrac{7}{9}\) : =\(\dfrac{2}{3}\)
c)\(\dfrac{3}{4}\) x x =\(\dfrac{7}{12}\)
cứu tui bài này với các thánh ui
\(a,\Rightarrow x=\dfrac{8}{9}-\dfrac{5}{7}\\ \Rightarrow x=\dfrac{11}{63}\)
\(b,\Rightarrow x=\dfrac{7}{9}:\dfrac{2}{3}\\ \Rightarrow x=\dfrac{7}{6}\\ c,\Rightarrow x=\dfrac{7}{12}:\dfrac{3}{4}\\ \Rightarrow x=\dfrac{7}{9}\)
Bài 3 : Tính
a) \(\dfrac{2}{5}+\dfrac{11}{15}\) b) \(\dfrac{2}{7}-\dfrac{2}{11}\) c) \(\dfrac{11}{13}\) x \(\dfrac{26}{31}\) d) \(\dfrac{1}{2}:\dfrac{1}{3}\) x \(\dfrac{2}{5}\)
giúp mik với , giải rõ ràng ra nha . ( đùưng vào nói ltinh gì zới mik nha )
a \(\dfrac{6}{15}+\dfrac{11}{15}=\dfrac{17}{15}\)
b \(\dfrac{22}{77}-\dfrac{14}{77}=\dfrac{8}{77}\)
c \(\dfrac{11}{13}\times\dfrac{26}{31}=11\times\dfrac{2}{31}=\dfrac{22}{31}\)
d \(\dfrac{1}{2}\times3\times\dfrac{2}{5}=\dfrac{3}{5}\)
a, 2/5 + 11/15 = 6/15 + 11/15 = 17/15
b,2/7 - 2/11 = 22/77 - 14/77 = 8/77
c, 11/13 x 26/31= 11 x 2/31 =22/31
d, 1/2 : 1/3 x 2/5
= ( 1/2 x 2/5 ) : 1/3
= 1/5 : 1/3
= 3/5
Bài3:Tìm x
a,\(\dfrac{x}{7}\)=\(\dfrac{6}{12}\) b,\(\dfrac{-5}{x}\)=\(\dfrac{20}{28}\) c,\(\dfrac{x-2}{8}\)=\(\dfrac{3}{4}\) d,\(\dfrac{x}{-5}\)=\(\dfrac{-5}{x}\)
các ban giúp mình nha, cảm ơn các bạn
\(a,\dfrac{x}{7}=\dfrac{6}{12}\\ x\cdot12=7\cdot6=42\\ x=42:12\\ x=\dfrac{7}{2}\\ b,\dfrac{-5}{x}=\dfrac{20}{28}\\ x\cdot20=\left(-5\right)\cdot28=-140\\ x=\left(-140\right):20\\ x=-7\\ c,\dfrac{x-2}{8}=\dfrac{3}{4}\\ \left(x-2\right)4=8\cdot3=24\\ x-2=24:4\\ x-2=6\\ x=6+2\\ x=8\\ d,\dfrac{x}{-5}=\dfrac{-5}{x}\\ x^2=\left(-5\right)\cdot\left(-5\right)=25\\ x=5\)