Bài 2:

a. $=62-81-12+59-9=(62-12)+(59-9)-81$

$=50+50-81=100-81=19$

b. $=39+13-26-62-39=(39-39)+13-(26+62)$

$=0+13-88=-(88-13)=-75$

c. $=(32-42)+(36-34)+(40-38)=10+2+2=14$
d. $=92-55+8-45=(92+8)-(55+45)=100-100=0$

Bài 1:

a. $=(387-87)-224=300-224=76$

b. $=-(75+35)+379=-110+379=379-110=269$

c. $=(11+15)-(13+17)=25-30=-5$

d. $=(31-21)-(27-24)=10-3=7$

\(\left(62-81\right)-\left(12-59+9\right)\)

\(=\left(-19\right)-\left(-38\right)\)

\(=19\)

\(\text{( 62 - 81) - (12 - 59 + 9 ) }=\left(-19\right)-\left(-38\right)=\left(-57\right)\)

\(=62-81-12+59-9=19\)

\(\left(62-81\right)-\left(12-59+9\right)=-19-\left(-38\right)=-19+38=19\)

\(\left(62-81\right)-\left(12-59+9\right)=-19-\left(-47+9\right)=-19-\left(-38\right)=-19+38=19\)

a: \(=168:\left[180-\left(36+2^3\cdot8\right)\right]=168:80=\dfrac{21}{10}\)

b: =62-81-12+59-9

=50+50-81

=100-81

=19

c: \(=298\cdot198-298\cdot127+198\cdot127-198\cdot298\)

=127x(-100)=-12700

a) 232 - (581 + 132 - 331)

= 232 - 581 - 132 + 331

= (232 - 132) - (581 - 331)

= 100 - 250

= -(250 - 100)

= -150

b) [12 + (-57)] - [-57 - (-12)]

= 12 - 57 + 57 - 12

= (12 - 12) + (57 - 57)

= 0 + 0

= 0

a) (-21) + 24 + (-27) + 31

= 3 + (-27 + 31)

= 3 + 4

= 7

b) (62 - 81) - (12 - 59 + 9)

= -19 - (-47 + 9)

= -19 + 38

= -19

a) 152 + (-73) - (-18) - 127 = 152 – 73 +18 -127

= (152 + 18) – (127 + 73) = 170 - 200 = -(200 - 170) = -30

b) 7 + 8 + (-9)  + (-10) = (7 + 8) + [(-9)  + (-10)]

= 15 + (-19) = -(19 - 15) = -4.

a) (-2 019) + (-550) + (-451)  = [(-2 019) + (-451)] + (-550) = (-2 470) + (-550) = -(2 470 + 550) = -3 020

b) (-2) + 5 + (-6) + 9 = [(-2) + 5 ]+[ (-6) + 9] = 3 + 3 = 6