Học tại trường Chưa có thông tin
Đến từ Hà Nội , Chưa có thông tin
Số lượng câu hỏi 37
Số lượng câu trả lời 4732
Điểm GP 123
Điểm SP 186

Người theo dõi (9)

Đang theo dõi (8)

Cô Tuyết Ngọc
Đỗ Tuệ Lâm
Hà Đức Thọ
Citii?

Câu trả lời:

\(a.\) \(A=\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+\dfrac{1}{6\cdot7}\)

\(A=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}\)

\(A=\dfrac{1}{2}-\dfrac{1}{7}\)

\(A=\dfrac{7}{14}-\dfrac{2}{14}\)

\(A=\dfrac{5}{14}\)

\(b.\) \(D=\dfrac{2}{3\cdot4}+\dfrac{2}{4\cdot5}+...+\dfrac{2}{2022\cdot2023}\)

\(D=\dfrac{2}{3}-\dfrac{2}{4}+\dfrac{2}{4}-\dfrac{2}{5}+...+\dfrac{2}{2022}-\dfrac{2}{2023}\)

\(D=\dfrac{2}{3}-\dfrac{2}{2023}\)

\(D=\dfrac{4046}{6069}-\dfrac{6}{6069}\)

\(D=\dfrac{4040}{6969}\)

\(c.\) \(E=\dfrac{1}{1\cdot4}+\dfrac{1}{4\cdot7}+...+\dfrac{1}{37\cdot40}\)

\(E=\dfrac{1}{1}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{37}-\dfrac{1}{40}\)

\(E=\dfrac{1}{4}-\dfrac{1}{40}\)

\(E=\dfrac{10}{40}-\dfrac{1}{40}\)

\(E=\dfrac{9}{40}\)

\(d.\) \(J=\dfrac{1\cdot2\cdot3+2\cdot4\cdot6+4\cdot8\cdot12+7\cdot14\cdot21}{1\cdot3\cdot5+2\cdot6\cdot10+4\cdot12\cdot20+7\cdot21\cdot35}+\dfrac{3}{5}\)

\(J=\dfrac{1\cdot2\cdot3+1\cdot2\cdot3\cdot2\cdot2\cdot2+1\cdot2\cdot3\cdot4\cdot4\cdot4+1\cdot2\cdot3\cdot7\cdot7\cdot7}{1\cdot3\cdot5+1\cdot2\cdot5\cdot2\cdot2\cdot2+1\cdot2\cdot5\cdot4\cdot4\cdot4+1\cdot2\cdot3\cdot7\cdot7\cdot7}+\dfrac{3}{5}\)

\(J=\dfrac{1\cdot2\cdot3\cdot\left(1+2^3+4^3+7^3\right)}{1\cdot3\cdot5\cdot\left(1+2^3+4^3+7^3\right)}+\dfrac{3}{5}\)

\(J=\dfrac{1\cdot2\cdot3}{1\cdot3\cdot5}\cdot1+\dfrac{3}{5}\)

\(J=\dfrac{6}{15}+\dfrac{3}{5}\)

\(J=\dfrac{2}{5}+\dfrac{3}{5}\)

\(J=\dfrac{5}{5}=1\)