Lời giải:

\(P=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\\ =\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\\ =\frac{2^{19}.3^9+2^{18}.3^9.5}{2^{19}.3^9+2^{20}.3^{10}}\\ =\frac{2^{18}.3^9(2+5)}{2^{19}3^9(1+2.3)}\\ =\frac{1}{2}\)

\(a,4^9:4^4=4^5\\b,17^8:17^5=17^3\\ c,2^{10}:8^2=2^{10}:2^6=2^4\\ d,18^{10}:3^{10}=2^{10}\cdot3^{20}:3^{10}=2^{10}\cdot3^{10}=6^{10}\\ e,27^5:81^3=3^{15}:3^{12}=3^3 \)

\(f,10^6:100=10^6:10^2=10^4\\ g,5^9:25^3=5^9:5^6=5^3\\ h,4^{10}:64^3=4^{10}:4^9=4\\ i,2^{25}:32^4:18^4:9^4=2^{25}:2^{20}:2^4:3^8:3^8=2\)

b: \(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)

\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+3^8\cdot2^{10}\cdot5}\)

\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{11}\cdot3^9}\)

\(=\dfrac{1}{2}\cdot\dfrac{-2}{3}=\dfrac{-1}{3}\)

Sửa đề câu a) phải là (-2020/2021)⁰

Xin lỗi mn

\(a,=\dfrac{3}{4}+\dfrac{15}{6}\cdot\dfrac{1}{5}-\dfrac{1}{36}\cdot9-\dfrac{2020}{2021}=\dfrac{3}{4}+\dfrac{1}{2}-\dfrac{1}{4}-\dfrac{2020}{2021}=1-\dfrac{2020}{2021}=\dfrac{1}{2021}\\ b,=\dfrac{2^{10}\cdot3^8-2\cdot2^9\cdot3^9}{2^{10}\cdot3^8+2^8\cdot3^8\cdot2\cdot5}=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^9\cdot3^8\left(2+5\right)}=\dfrac{2\left(-2\right)}{3}=-\dfrac{4}{3}\)

sao nhieu qua zay

a)

4⁹:4⁴=4⁵

17⁸:17⁵=17³

2¹⁰:8²=2¹⁰:2⁴=2⁶

18¹⁰:3¹⁰=15¹⁰

27⁵:81³=3¹⁵:3¹²=3³

b)10⁶:10²=10⁴

5⁹:5⁶=5³

4¹⁰:64³=4

2²⁵:32⁴=2²⁵:2²⁰=2⁵

18⁴:9⁴=9⁴

\(4^9:4^4\)
=\(4^{9-4}\)
=\(4^5\)
\(17^8:17^5\)
=\(17^{8-5}\)
= \(17^3\)
\(2^{10}:8^2\)
\(=2^{^{ }10}:\left(2^3\right)^2\)
=\(2^{10}:2^6\)
\(=2^4\)
\(18^{10}:3^{10}\)
=\(\left(18:3\right)^{10}\)
=\(6^{10}\)

a) \(4^9:4^4\)

\(=4^{9-4}\)

\(=4^5\)

b) \(17^8:17^5\)

\(=17^{8-5}\)

\(=17^3\)

c) \(2^{10}:8^2\)

\(=2^{10}:\left(2^3\right)^2\)

\(=2^{10-6}\)

\(=2^4\)

d) \(18^{10}:3^{10}\)

\(=\left(18:3\right)^{10}\)

\(=6^{10}\)

e) \(27^5:81^3\)

\(=\left(3^3\right)^5:\left(3^4\right)^3\)

\(=3^{15}:3^{12}\)

\(=3^{15-12}\)

\(=3^3\)

f) \(10^6:100\)

\(=10^6:10^2\)

\(=10^{6-2}\)

\(=10^4\)

g) \(5^9:25^3\)

\(=5^9:\left(5^2\right)^3\)

\(=5^9:5^6\)

\(=5^{9-6}\)

\(=5^3\)

h) \(4^{10}:64^3\)

\(=4^{10}:\left(4^3\right)^3\)

\(=4^{10-9}\)

\(=4\)

i) \(2^{25}:32^4:18^4:9^4\)

\(=\left(2^{25}:2^{20}\right):\left(18^4\cdot9^4\right)\)

\(=2^5:9^8:2^4\)

\(=2:9^8\)

\(=\dfrac{2}{9^8}\)

a,4^9-4

b,17^8-5

c,2^10-5

d,6^10

e,81

f,

a: \(\dfrac{4^9}{4^4}=4^{9-4}=4^5\)

b: \(\dfrac{17^8}{17^5}=17^{8-5}=17^3\)

c: \(2^{10}:8^2=2^{10}:2^6=2^4\)

d: \(18^{10}:3^{10}=\left(\dfrac{18}{3}\right)^{10}=6^{10}\)

e: \(=\dfrac{3^{15}}{3^{12}}=3^3\)

f: \(=\dfrac{10^6}{10^2}=10^4\)

g: =5^9:5^6=5^3

h: \(=\dfrac{4^{10}}{\left(4^3\right)^3}=\dfrac{4^{10}}{4^9}=4\)

i: \(=2^{25}:2^{20}\cdot\dfrac{1}{18^4}\cdot\dfrac{1}{9^4}\)

\(=\dfrac{2^5}{9^8\cdot2^4}=\dfrac{2}{9^8}\)

a: \(\left(24-234\right)+\left(234-24-77\right)\)

\(=24-234+234-24-77\)

\(=\left(24-24\right)+\left(234-234\right)-77\)

=0+0-77

=-77

b: \(\left(13-135+49\right)-\left(13+49\right)\)

\(=13-135+49-13-49\)

\(=\left(13-13\right)+\left(49-49\right)-135\)

=0+0-135

=-135

c: \(159-524-\left(59-424\right)\)

\(=159-524-59+424\)

\(=\left(159-59\right)-\left(524-424\right)\)

=100-100

=0

d: \(\left(36+79\right)+\left(145-79-36\right)\)

\(=36+79+145-79-36\)

\(=\left(36-36\right)+\left(79-79\right)+145\)

=0+0+145

=145

e: \(334-\left(117+234\right)+\left(42+117\right)\)

\(=334-117-234+42+117\)

\(=\left(334-234\right)+\left(117-117\right)+42\)

=100+0+42

=142

f: \(271-\left[\left(-43\right)+271-\left(-17\right)\right]\)

\(=271+43-271+\left(-17\right)\)

\(=\left(271-271\right)+\left(43-17\right)\)

=0+26

=26

1.

a) = 354

b) = -54

c) = -167

b: =-2021+21-75+2021=-54

a) = 354

b) = -54

c) = -167

Bài 1: 

a: =-153-45=-198

b: =65+274=339