Tìm x:
3/5 x x +9
___________ +9 =16:8/9
21
Tìm số nguyên x, biết:
a. 9 - x = 8 - (2x + 16)
b. 18 - 2x = 21 - (3x - 5)
a) Tìm số nguyên x, biết:
Với \(x\in Z\), ta có:
9 - x = 8 - (2x + 16)
<=> 9 - x = 8 - 2x - 16
<=> 9 - x = -2x - 8
<=> x = -17 (TM)
Vậy x = -17
b) Với \(x\in Z\), ta có:
18 - 2x = 21 - (3x - 5)
<=> 18 - 2x = 21 - 3x + 5
<=> 18 - 2x = 26 - 3x
<=> x = 8 (TM)
Vậy x = 8
a) Ta có: 9-x=8-(2x+16)
\(\Leftrightarrow9-x=8-2x-16\)
\(\Leftrightarrow9-x=-2x-8\)
\(\Leftrightarrow9-x+2x+8=0\)
\(\Leftrightarrow x+17=0\)
hay x=-17
Vậy: x=-17
b) Ta có: 18-2x=21-(3x-5)
\(\Leftrightarrow18-2x=21-3x+5\)
\(\Leftrightarrow18-2x+3x-26=0\)
\(\Leftrightarrow x-8=0\)
hay x=8
Vậy: x=8
16 : (3/5 x X + 8 / 21 +9 = 7/10
\(16:\left(\frac{3}{5}x+\frac{8}{21}+9\right)=\frac{7}{10}\)
\(\frac{3}{5}x+\frac{8}{21}+9=\frac{160}{7}\)
\(\frac{3}{5}x=\frac{283}{21}\)
\(x=\frac{1415}{63}\)
Vậy ...
Tính bằng cách thuận tiện:
a, 7/9 x 13/25 x 9/7
b, 5/9 x 21/25 + 21/25 x 4/9
c, 19/5 x 11/16 - 9/5 x 11/16
a) \(\dfrac{7}{9}\times\dfrac{13}{25}\times\dfrac{9}{7}=\left(\dfrac{7}{9}\times\dfrac{9}{7}\right)\times\dfrac{13}{25}=1\times\dfrac{13}{25}=\dfrac{13}{25}\)
b) \(\dfrac{5}{9}\times\dfrac{21}{25}+\dfrac{21}{25}\times\dfrac{4}{9}\)
\(=\dfrac{21}{25}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\)
\(=\dfrac{21}{25}\times1=\dfrac{21}{25}\)
c) \(\dfrac{19}{5}\times\dfrac{11}{16}-\dfrac{9}{5}\times\dfrac{11}{16}\)
\(=\dfrac{11}{16}\times\left(\dfrac{19}{5}-\dfrac{9}{5}\right)\)
\(=\dfrac{11}{16}\times2=\dfrac{22}{16}=\dfrac{11}{8}\)
1. 8/11 + 8/33 x 3/4
7/9 x 3/14 : 5/8
5/12 - 7/32 : 21/16
1.\(\dfrac{8}{11}+\dfrac{8}{33}\times\dfrac{3}{4}=\dfrac{8}{11}+\dfrac{8\times3}{33\times4}=\dfrac{8\times12}{11\times12}+\dfrac{8\times3}{33\times4}=\dfrac{8\times15}{132}=\dfrac{120}{132}=\dfrac{10}{11}\)
2.\(\dfrac{7}{9}\times\dfrac{3}{14}:\dfrac{5}{8}=\dfrac{7}{9}\times\dfrac{3}{14}\times\dfrac{8}{5}=\dfrac{4}{15}\)
3.\(\dfrac{5}{12}-\dfrac{7}{32}:\dfrac{21}{16}=\dfrac{5}{12}-\dfrac{7}{32}\times\dfrac{16}{21}=\dfrac{5}{12}-\dfrac{1}{6}=\dfrac{5-2}{12}=\dfrac{3}{12}=\dfrac{1}{4}\)
`@V.Tr.V`
`8/11+8/33xx3/4=8/11+2/11=10/11`
`7/9xx3/14:5/8=7/9xx3/14xx8/5=[7xx3xx4xx2]/[3xx3xx7xx2xx5]=4/[3xx5]=4/15`
`5/12-7/32:21/16=5/12-7/32xx16/21=5/12-2/12=3/12=1/4`
8/11 + 8/33 x 3/4 = 8/11 + 2/11 = 10/11
7/9 x 3/14 : 5/8 = 1/6 : 5/8 = 4/15
5/12 - 7/32 : 21/16 = 5/12 - 1/6 = 1/4
Tính
a, -(-5)-(+7)+(+3)+(-8)
b, -(-15)-|-10|+|-9|-|5|
c, 14-(-13)-(17)+(-12)
d, -|-14| + |-10| - (-12) + (-8)
e, -(-11) + (-15) + (13) - 21
Bài 2 tìm x
1, -x + 20 = - (-15) - (8) + 13
2, -(-10) + x = -13 + (-9) + (-6)
3, 8-(-12) + 10 = - (-14) - x
4. - (+12) + (-x) - (-3) = 5 - (-7)
5. 14 - x + (-10) = - (-9) + (+15)
6. 12 - (-17) + (-3) = -5 + x
7. X - (-19) - (+32) = 14 - (+16)
8. X - |-15| - |7| = - (-9) + |-5|
9. 15 - x + 17 = 13 - (-21)
10. - |-5| - (-x) +4 = 3 - (-25)
Mọi NGƯỜI GIẢI GIÚP MÌNH VỚI MK CẦN GẤP, MỌI NGƯỜI GHI RÕ CÁCH LÀM RA NHÉ! CẢM ƠN MỌI NGƯỜI
Bạn ơi bạn làm đc bao nhiêu thì làm phụ mình nhé
bài1
a,
5 - 7 + 3 +(-8)
= -2 + 3 + ( - 8)
= 1 + (-8)= -7
a; - (-5) - (+7) + (+3) + (-8)
= 5 - 7 + 3 - 8
= (5 + 3 - 8) - 7
= (8 - 8) - 7
= 0 - 7
= - 7
b) 16:( 3/5* x + 8 /21 +9) = 7/10
3/5*x+8/21+9=16:7/10
3/5*x+8/21=160/7-9
3/5*x=97/7-8/21
x=283/21:3/5
x=1415/63
16/(3/5*x+8/21+9) bảng 7/10
a) 92/9 + 13/5 - 56/9
b) 58/7 - (31/9 + 30/7)
c) 2/3 + 1/3 x 9/4 - 13/12
d) 41/8 - 7/4 : 11/5
e) 478/19 : 5/4 - 668/19 : 5/4
f) 32/21 x 49/45 : 16/22 x 15/33
g) 2020x2018+9 / 2019x2020-2011.
Giup minh voi minh dang can gap!!!
58/7 - (31/9 + 30/7)
= 58/7 - 31/9 - 30/7
= (58/7 - 30/7) - 31/9
= 28/7- 31/9
= 4 - 31/9 = 36/9 - 31/9
= 5/9
478/19÷(-5/4)-668/19÷(-5/4)
=(478/19-668/19):(-5/4)
=-10 . (-4/5)
=8
16 : (3 /5 × x +8 +9/ 21 ) = 7/10
\(16\div\left(\frac{3}{5}\times x+8+\frac{9}{21}\right)=\frac{7}{10}\)
\(\Rightarrow\frac{3}{5}x+\frac{59}{7}=\frac{160}{7}\)
\(\Rightarrow\frac{3}{5}x=\frac{101}{7}\)
\(\Rightarrow x=\frac{35}{303}\)
~Study well~
#KSJ
\(16:\left(\frac{3}{5}.x+8+\frac{9}{21}\right)=\frac{7}{10}\)
\(\frac{3}{5}x+\frac{59}{7}=\frac{160}{7}\)
\(\frac{3}{5}x=\frac{101}{7}\)
\(x=\frac{35}{303}\)