a) 29,42 + 20,58 - 34,23 + (-25,77)

=(29,42+20,58)+(-34,23+-25,77)

=50+-60

=-10

b) (-212,49) - (87,51 - 99,9) 

=-212,49-87,51+99,9

=(-212,49-87,51)+99,9

=-300+99,9

=-200,1

`a) 29,42 + 20,58 - 34,23 + (-25,77)`
`=29+0,42+20+0,58-34-0,23-25-0,77`
`=29+20-34-25+0,42+0,58-(0,23+0,77)`
`=49-59+1-1`
`=-10`
`b) (-212,49) - (87,51 - 99,9).`
`=-212,49-87,51+99,9`
`=-(212,49+87,51)+99,99=`
`=-299,9+99,9`
`=-200`

a) 29,42+20,58-34,23+(-25,77)

=🥰💓👍🦹🤝💓🥰👍🤝🦹👍🥰💓🤝🦹👍🥰💓

`(-225,65)-(87,51-99,9)`

`=-225,65-87,51+99,99`

`=-313,16+99,9`

`=-213,26`

\(-413,06\)

`(-225,65)-(87,51-99,9)`

`=-225,65-87,51+99,9`

`=-313.16+99,9`

`=-213.26`

a) 80-(4x5^2-3x2^3)

   = 80-(4x25-3x8)

   = 80-(100-24)

   = 80-76

   = 4

b) 125-2x[56-48:(15-7)]

  = 125-2x[56-48:8]

  = 125-2x[56-6]

   =125-2x50

   =125-100

   =25.

a: =4700

c: =1900

các bn tính từng bước nhé

a, = 47 . ( 36 + 64 )

= 47 . 100 = 4700

b,  = -43 + 1315 - 126 - 1315 - 57

= ( - 43 - 57 ) - 126 

= - 100 - 126

 = -226

c, = 19 .  ( 35 - 2 + 67 )

= 19 . 100 = 1900

d, = -25 + 117 - 117 + 25

= 0

\(a,\dfrac{-19}{34}-\left(\dfrac{31}{51}-\dfrac{54}{35}\right)=\dfrac{-19}{34}-\left(-\dfrac{1669}{1785}\right)=\dfrac{79}{210}\\ b,\dfrac{-2}{5}.\dfrac{4}{15}+\left(-0,4\right).\dfrac{26}{15}=-\dfrac{8}{75}-\dfrac{52}{75}=-\dfrac{4}{5}\)

`@` `\text {Ans}`

`\downarrow`

`1,`

`a)`

`5 \times 72 \times 10 \times 2`

`= 5 \times 2 \times 10 \times 72`

`= 10 \times 10 \times 72`

`= 100 \times 72`

`= 7200`

`b)`

`40 \times 125`

`= 4 \times 10 \times 25 \times 5`

`= (5 \times 10) \times (4 \times 25)`

`= 50 \times 100`

`= 5000`

`c)`

`4 \times 2021 \times 25`

`= (4 \times 25) \times 2021`

`= 100 \times 2021`

`= 202100`

`d)`

`16 \times 6 \times 25`

`= 4 \times 4 \times 6 \times 25`

`= (4 \times 25) \times 4 \times 6`

`= 100 \times 24`

`= 2400`

`2,`

`a)`

`24 \times 57 + 43 \times 24`

`= 24 \times (57+43)`

`= 24 \times 100`

`= 2400`

`b)`

`12 \times 19 + 80 \times 12 +12`

`= 12 \times (19 + 80 + 1)`

`= 12 \times 100`

`= 1200`

`c)`

`(36 \times 15 \times 169) \div (5 \times 18 \times 13)`

`= 36 \times 15 \times 169 \div 5 \div 18 \div 13`

`= 6 \times 6 \times 3 \times 5 \times 13 \times 13 \div 5 \div 3 \times 6 \div 13`

`= (6 \div 6) \times (3 \div 3) \times (5 \div 5) \times (13 \div 13) \times 6 \times 13`

`= 6 \times 13`

`= 78`

`d)`

`(44 \times 52 \times 60) \div ( 11 \times 13 \times 15)`

`= 44 \times 52 \times 60 \div 11 \div 13 \div 15`

`= 4 \times 11 \times 13 \times 4 \times 15 \times 4 \div 11 \div 13 \div 15`

`= (11 \div 11) \times (13 \div 13) \times (15 \div 15) \times 4 \times 4 \times`

`= 4 \times 4 \times 4`

`= 64`

`3,`

`a)`

`x - 280 \div 35 = 5 \times 54`

`x - 8 = 270`

`x = 270 + 8`

`x = 278`

`b)`

`(x - 280) \div 35 = 54 \div 4`

`(x - 280) \div 35 = 13,5`

`x - 280 = 13,5 \times 35`

`x - 280 = 472,5`

`x = 472,5 + 280`

`x = 752,5`

`c)`

`(x - 128 + 20) \div 192 = 0`

`x - 128 + 20 = 0 \times 192`

`x - 128 + 20 = 0`

`x - 108 = 0`

`x = 0 + 108`

`x = 108`

`d)`

`4 \times (x + 200) = 460 + 85 \times 4`

`4 \times (x+200) = 460 + 340`

`4 \times (x+200) = 800`

`x + 200 = 800 \div 4`

`x + 200 = 200`

`x = 200 - 200`

`x = 0`

`4,`

`a)`

`7/12 - 5/12`

`= (7 - 5)/12`

`= 2/12`

`= 1/6`

`b)`

`8/11 + 19/11`

`= (8+19)/11`

`= 27/11`

`c)`

`3/8 + 5/12`

`= 9/24 + 10/24`

`= 19/24`

`d)`

`3/4 + 7/12`

`= 9/12 + 7/12`

`= 16/12`

`= 4/3`

`5,`

`a)`

`x - 6/7 = 5/2`

`x = 5/2 + 6/7`

`x = 47/14`

`b)`

`12/7 \div x + 2/3 = 7/5`

`12/7 \div x = 7/5 - 2/3`

`12/7 \div x = 11/15`

`x = 12/7 \div 11/15`

`x = 180/77`

`@` `\text {Kaizuu lv uuu}`

a: =-64(32+68)=64x100=-6400

b: =76(-54-12+36)=76x(-30)=-2380

c: =19x50+38x5=950+190=1140

`1 - 2 + 3 - 4 + 5 - 6 +...+ 2021 - 2022`

`= (1 - 2) + (3 - 4) + (5 - 6) +...+ (2021 - 2022)`

`= (-1) + (-1) + (-1) + ... + (-1) `  [có `2022 : 2 = 1011` nhóm]

`= (-1) xx 1011 = -1011`

a, \(\dfrac{3}{5}.\left(-\dfrac{8}{3}\right)-\dfrac{3}{5}:\left(-\dfrac{3}{2}\right)=\dfrac{3}{5}.\left(-\dfrac{8}{3}\right)-\dfrac{3}{5}.\left(-\dfrac{2}{3}\right)==\dfrac{3}{5}\left(-\dfrac{8}{3}-\dfrac{2}{3}\right)=\dfrac{3}{5}.\left(-\dfrac{10}{3}\right)=-2\)

b, \(-\dfrac{5}{6}.\left(-\dfrac{12}{7}\right)-\left(-\dfrac{21}{15}\right)=-\dfrac{5}{6}.\left(-\dfrac{12}{7}\right)+\dfrac{7}{5}=\dfrac{10}{7}+\dfrac{7}{5}=\dfrac{50+49}{35}=\dfrac{99}{35}\)

a: \(=\dfrac{3}{5}\cdot\left(-\dfrac{8}{3}+\dfrac{-2}{3}\right)=\dfrac{3}{5}\cdot\dfrac{-10}{3}=-2\)

c: \(=\left(0.125\right)^{650}\cdot8^{102}\)

\(=\left(0.125\cdot8\right)^{102}\cdot\left(0.125\right)^{548}\)

\(=\dfrac{1}{8^{548}}\)