tìm x 

67 - 3x = 31

=> 3x =    36

=> x = 12           ,                

18 + 3x =24

=> 3x = 6

=> x = 2

( x - 36 ) : 18 = 12    

=> x - 36 = 216

=> x = 252

 ,                ( x + 74 ) - 318 = 200

=> x + 74 =  518

=> x = 444

3636 : ( 12x - 91 ) = 36       ,

=> 12x - 91 = 101

=> 12x = 192

=> x  = 16

( x : 23 + 45 ) x 67 = 8911

=> x : 23  + 45 = 133

=> x : 23 = 88

=> x = 2024

Tìm x

67 - 3x = 31

=> 3x = 67 - 31

=> 3x = 46

=> x = 46/3

18 + 3x = 24

=> 3x = 24 - 18

=> 3x = 6

=> x = 2

(x - 36) : 18 = 12

x - 36 = 12.18

x - 36 = 216

x = 216 + 36

x = 252

(x + 74) - 318 = 200

x + 74 = 200 + 318

x + 74 = 518

x = 518 - 74

x = 444

3636 : (12x - 91) = 36

12x - 91 = 3636 : 36

12x - 91 = 101

12x = 101 + 91

12x = 192

x = 16

(x : 23 + 45) x 67 = 8911

x : 23 + 45 = 8911 : 67

x : 23 + 45 = 133

x : 23 = 133 + 45

x : 23 = 178

x = 4094

\(67-3x=31\)

\(3x=36\)

\(x=12\)

\(18+3x=24\)

\(3x=6\)

\(x=2\)

\(\left(x-36\right):18=12\)

\(x-36=216\)

\(x=252\)

\(\left(x+74\right)-318=200\)

\(x+74=518\)

\(x=444\)

\(3636:\left(12x-91\right)=36\)

\(12x-91=101\)

\(12x=192\)

\(x=12\)

\(\left(\frac{x}{23}+45\right).67=8911\)

\(\frac{x}{23}+45=133\)

\(\frac{x}{23}=88\)

\(\Rightarrow\frac{x}{23}=\frac{2024}{23}\)

\(\Rightarrow x=2024\)

g: =>3x-10=200

hay x=70

c) (7x + x – 28) :100 – 38 = 9

<=> 8x - 28 = 4700

<=> x = 591

d) 936 – (4x + 5x ) = 900

<=> 9x = 36

<=> x = 4

a)73+86+968+914+3032

= (86 + 914) +(968 + 3032) + 73

= 1000 + 4000 + 73

= 5073

b)341.67+341.16+659.83

=341 (67 + 16) + 659 * 83

= 341 * 83 + 659 * 83

= (341+ 659) * 83

= 1000 * 83

= 830000

c)252-84:21+7

= 252 - 2 +7

=257

d)4.8.25.125.27

= (8 * 125) (4* 25) * 27

= 1000 * 100 * 27

= 2700000

e)34+35+36+37-24-25-26-27

= (34-24) + (35-25) + (36-26) + (37-27)

= 10 + 10 + 10 + 10

= 40

g)1-2+3-4+...-98+99

= (1 + 99) + (-2-98) + .....+ (-48 - 52) + (49 + 51) - 50

= 100 - 50

= 50

h)1-4+7-10+...-100+103

Bài 2:Tìm số nguyên x,biết:

l)3636:(12.x-91)=36

3636 : (12x - 91) = 36

12x - 91 = 101 

12x = 192

x= 16 

m)(x:23+45).67=8911

x: 23 + 45 = 133

x : 23 = 88

x= 88/23

n)[(6.x-39):7].4=12

6x - 39 = 3

6x = 42

x=7

p)128-3(x+4)=23

3(x+4) = 105

x+4= 35

x= 31

q)[(4.x+28).3+55]:5=35

(4x + 28)*3 +55 = 175

(4x + 28) * 3 = 120

4x + 28 = 40

4x = 12

x=3

r)123-5.(x+4)=38

5(x+4) = 85

x+4 = 17 

x= 13 

t)11-(53+x)=97

53 + x = -86

x= -139

i)23.75+25.23+180

= 23(75+25) + 180

= 2300 + 180 

= 2480 

https://friend20.com/vn/d20/quiz/69707687

6) ĐKXĐ: \(x\le-6\)

\(\sqrt{\left(x+6\right)^2}=-x-6\Leftrightarrow\left|x+6\right|=-x-6\)

\(\Leftrightarrow x+6=x+6\left(đúng\forall x\right)\)

Vậy \(x\le-6\)

7) ĐKXĐ: \(x\ge\dfrac{2}{3}\)

\(pt\Leftrightarrow\sqrt{\left(3x-2\right)^2}=3x-2\Leftrightarrow\left|3x-2\right|=3x-2\)

\(\Leftrightarrow3x-2=3x-2\left(đúng\forall x\right)\)

Vậy \(x\ge\dfrac{2}{3}\)

8) ĐKXĐ: \(x\ge5\)

\(pt\Leftrightarrow\sqrt{\left(4-3x\right)^2}=2x-10\)\(\Leftrightarrow\left|4-3x\right|=2x-10\)

\(\Leftrightarrow4-3x=10-2x\Leftrightarrow x=-6\left(ktm\right)\Leftrightarrow S=\varnothing\)

9) ĐKXĐ: \(x\ge\dfrac{3}{2}\)

\(pt\Leftrightarrow\sqrt{\left(x-3\right)^2}=2x-3\Leftrightarrow\left|x-3\right|=2x-3\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=2x-3\left(x\ge3\right)\\x-3=3-2x\left(\dfrac{3}{2}\le x< 3\right)\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(ktm\right)\\x=2\left(tm\right)\end{matrix}\right.\)

tìm x nha

c, \(3x^2-7x+10=0\)

\(\Leftrightarrow3x^2+3x-10x+10=0\)

\(\Leftrightarrow3x\left(x+1\right)-10\left(x+1\right)=0\)

\(\Leftrightarrow\left(x+1\right)\left(3x-10\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{10}{3}\end{matrix}\right.\)

d, \(2x\left(x-10\right)-x+10=0\)

\(\Leftrightarrow2x\left(x-10\right)-\left(x-10\right)=0\)

\(\Leftrightarrow\left(x-10\right)\left(2x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=\dfrac{1}{2}\end{matrix}\right.\)

chi chi mà cả nhả

b: Ta có: 7x-8=713

nên 7x=721

hay x=103

c: Ta có: x-36:18=12

nên x-2=12

hay x=14

d: Ta có: (x-36):18=12

nên x-36=216

hay x=252

a.      124 + (118 – x) = 217
                     118 - x  = 93
                            - x = - 25
                              x  = 25

b.      7x – 8 = 713
          7x      =721
            x      =103

c.       x- 36:18 = 12
          x- 2        =12
          x             =14

d.      (x- 36):18 = 12
           x-36        = 216
           x             = 252
          

e.      (x-47) -115 = 0
          x-47          = 115
          x               = 162

f.        315 + (146 – x) = 401
                      146-x     =86
                            -x     = -60
                             x     = 60

g.      (6x – 39 ) : 3 = 201
           6x - 39        = 603
           6x               = 642
             x               = 107

h.      23 + 3x = 5⁶ : 5³
         23 +3x   = 125
                3x    = 102
                  x=34

Bài 1: 

c: x=4

b: x=2

a) (x - 140) : 7 = 3³ - 2³ . 3

(x - 140) : 7 = 27 - 8 . 3 = 27 - 24 = 3

x - 140 = 3 x 7 = 21

x = 21 + 140 = 161

b) x³ . x² = 2⁸ : 2³

x⁵ = 2⁵

=> x = 2

c) (x + 2) . ( x - 4) = 0

x = -2 hoặc 4

d) 3^x-3 - 3² = 2 . 3² =

3^x-3 - 9 = 2 . 9 = 18

3^x-3 = 18 + 9 = 27

3^x-3 = 3³

=> x - 3 = 3

x = 3 + 3 = 6

2.

a) 9 : ( x + 2 )

9 ⋮ 1 ; 9 ⋮ 3 ; 9 ⋮ 9

=> x = -1 ; 1 ; 7

a. (3x - 1)² - (x + 3)² = 0

\(\Leftrightarrow\left(3x-1+x+3\right)\left(3x-1-x-3\right)=0\)

\(\Leftrightarrow\left(4x+2\right)\left(2x-4\right)=0\)

\(\Leftrightarrow4x+2=0\)  hoặc  \(2x-4=0\)

1. \(4x+2=0\Leftrightarrow4x=-2\Leftrightarrow x=-\dfrac{1}{2}\)

2. \(2x-4=0\Leftrightarrow2x=4\Leftrightarrow x=2\)

S=\(\left\{-\dfrac{1}{2};2\right\}\)

b. \(x^3=\dfrac{x}{49}\)

\(\Leftrightarrow49x^3=x\)

\(\Leftrightarrow49x^3-x=0\)

\(\Leftrightarrow x\left(49x^2-1\right)=0\)

\(\Leftrightarrow x\left(7x+1\right)\left(7x-1\right)=0\)

\(\Leftrightarrow x=0\) hoặc  \(7x+1=0\) hoặc \(7x-1=0\)

1. x=0

2. \(7x+1=0\Leftrightarrow7x=-1\Leftrightarrow x=-\dfrac{1}{7}\)

3. \(7x-1=0\Leftrightarrow7x=1\Leftrightarrow x=\dfrac{1}{7}\)

*Cách khác:

a) Ta có: \(\left(3x-1\right)^2-\left(x+3\right)^2=0\)

\(\Leftrightarrow\left(3x-1\right)^2=\left(x+3\right)^2\)

\(\Leftrightarrow\left[{}\begin{matrix}3x-1=-x-3\\3x-1=x+3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x=-2\\2x=4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=2\end{matrix}\right.\)

Vậy: \(S=\left\{-\dfrac{1}{2};2\right\}\)

a.

\(\left|5x\right|=3x+8\Leftrightarrow\left[{}\begin{matrix}-5x=3x+8\\5x=3x+8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=4\end{matrix}\right.\)

b.

\(\left|-4x\right|=-2x+11\Leftrightarrow\left[{}\begin{matrix}-4x=-2x+11\\4x=-2x+11\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{11}{2}\\x=\dfrac{11}{6}\end{matrix}\right.\)

c.

\(\left|3x-1\right|=4x+1\Leftrightarrow\left[{}\begin{matrix}-3x+1=4x+1\\3x-1=4x+1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)

d.

\(\left|3-2x\right|=3x-7\Leftrightarrow\left[{}\begin{matrix}-3+2x=3x-7\\3-2x=3x-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=2\end{matrix}\right.\)

e.

\(9-\left|-5x\right|+2x=0\Leftrightarrow\left[{}\begin{matrix}9-5x+2x=0\\9+5x+2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{9}{7}\end{matrix}\right.\)

f.

\(\left(x+1\right)^2+\left|x+10\right|-x^2-12=0\Leftrightarrow\left[{}\begin{matrix}x^2+2x+1-x-10-x^2-12=0\\x^2+2x+1+x+10-x^2-12=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=21\\x=\dfrac{1}{3}\end{matrix}\right.\)