Phân tích đa thức thành nhân tử:
a) 4 x 2 - 12xy + 9 y 2 - 8x + 12y,
b)3 x 2 + 20x - 7;
c) ( 3 x - 1 ) 4 + 2(9 x 2 - 6x + 1) + 1;
d) 2 x 3 -3 x 2 +2x - 1.
Phân tích các đa thức sau thành nhân tử:
a) \(9{x^2} - 16\) b) \(4{x^2} - 12xy + 9{y^2}\) c) \({t^3} - 8\) d) \(2a{x^3}{y^3} + 2a\)
`a, 9x^2 - 16 = (3x+4)(3x-4)`
`b, 4x^2 - 12xy + 9y^2 = (2x-3y)^2`
`c, t^3-8 = (t-2)(t^2 - 2t + 4)`
`d, 2ax^3y^3 + 2a = 2a(x^3y^3 + 1) = 2a(xy+1)(x^2y^2 - xy + 1)`
a) \(\left(9x^2-16\right)=\left(3x-4\right)\left(3x+4\right)\)
b) \(4x^2-12xy+9y^2=\left(2x-3y\right)^2\)
c) \(t^3-8=\left(t-2\right)\left(t^2+2t+4\right)\)
d) \(2ax^3y^3+2a=2a\left(x^3y^3+1\right)\)
Phân tích đa thức thành nhân tử:
a)16xy^2-12xy+24x^y
b)x^3-x^2-x+1
c)16-x^2+2xy-y^2
d)x^2-x-20
a. 16xy2 - 12xy + 24x2y
= 4xy(4y - 3 + 6x)
c. 16 - x2 + 2xy - y2
= 42 - (x2 - 2xy + y2)
= 42 - (x - y)2
= (4 - x + y)(4 + x - y)
b: \(x^3-x^2-x+1=\left(x-1\right)^2\left(x+1\right)\)
d: \(x^2-x-20=\left(x-5\right)\left(x+4\right)\)
Phân tích các đa thức sau thành nhân tử:
a) A= \(x^3\)y - 12xy - x2y
b)B= 4x2 - 3y2 - 4xy - 2x + 3y
c)C= (x+1)(x+2)(x+3)(x+4) - 120
d)D= x5 - x4 + x2 - 1
a: \(A=x^3y-12xy-x^2y\)
\(=xy\cdot x^2-xy\cdot12-xy\cdot x\)
\(=xy\left(x^2-x-12\right)\)
\(=xy\left(x^2-4x+3x-12\right)\)
\(=xy\left[x\left(x-4\right)+3\left(x-4\right)\right]\)
\(=xy\left(x-4\right)\left(x+3\right)\)
c: \(C=\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)-120\)
=(x+1)(x+4)(x+2)(x+3)-120
\(=\left(x^2+5x+4\right)\left(x^2+5x+6\right)-120\)
\(=\left(x^2+5x\right)^2+10\left(x^2+5x\right)+24-120\)
\(=\left(x^2+5x\right)^2+10\left(x^2+5x\right)-96\)
\(=\left(x^2+5x+16\right)\left(x^2+5x-6\right)\)
\(=\left(x^2+5x+16\right)\left(x+6\right)\left(x-1\right)\)
d: \(D=x^5-x^4+x^2-1\)
\(=\left(x^5-x^4\right)+\left(x^2-1\right)\)
\(=x^4\left(x-1\right)+\left(x-1\right)\left(x+1\right)\)
\(=\left(x-1\right)\left(x^4+x+1\right)\)
phân tích các đa thức sau thành nhân tử
1, 15x + 15y
2, 8x - 12y
3, xy-x
4, x mũ 2 + x
5, 3x mũ 2 y - 8xy mũ 2
6, 6x - 12xy - 18x mũ 2
Trả lời:
1, 15x + 15y = 15 ( x + y )
2, 8x - 12y = 4 ( 2x - 3y )
3, xy - x = x ( y - 1 )
4, x2 + x = x ( x + 1 )
5, 3x2y - 8xy2 = xy ( 3x - 8y )
6, 6x - 12xy - 18x2 = 6x ( 1 - 2y - 3x )
1) 15x + 15y = 15(x + y)
2) 8x - 12y = 4(2x - 3y)
3) xy - x = x(y - 1)
4) x2 + x = x(x + 1)
5) 3x2y - 8xy2 = xy(3x - 8y)
6) 6x - 12xy - 18x2 = 6x(1 - 2y - 3x)
1.\(15x+15y=15\left(x+y\right)\)
2.\(8x-12y=4\left(2x-3y\right)\)
3.\(xy-x=x\left(y-1\right)\)
4.\(x^2+x=x\left(x+1\right)\)
5.\(3x^{2y}-8xy^2\)hay là \(\left(3x\right)^{2y}-\left(8xy\right)^2\)??
6.\(6x-12xy-18x^2=6x\left(1-2y-3x\right)\)
Phân tích đa thức thành nhân tử:
a) x^3 - x^2 + 8x - 8
b) 8x^3 - 8x^2y + 2xy^2
c) (x^2 + y^2 - z^2)^2 - 4x^2y^2
d) (x^2 - y^2 - 5)^2 - 4(x^2y^2 + 4xy + 4)
e) x^3 - y^3 - 3x^2 + 3x - 1
a) (x3-x2)+(8x-8)=x(x-1)+8(x-1)=(x2+8)(x-1)
b) 8x3-8x2y+2xy2=2x(4x2-4xy+y2)
c) (x2+y2-z2)2 - 4x2y2=(x2+y2-z2)2 - (2xy)2=(x2+y2-z2-2xy)(x2+y2-z2+2xy)
Phân tích các đa thức sau thành nhân tử:
a/ x2 – 3x – 4xy + 12y b/ x3 – 4x2 + 4x -1
c/ x – y – ax + ay d/ x2 – 4 + ( x + 2)2
e/x3 + x2y – x2z – xyz f/ x2 – y2 – 2x – 2y
a: \(=x\left(x-3\right)-4y\left(x-3\right)\)
=(x-3)(x-4y)
d: \(=\left(x-2\right)\left(x+2\right)+\left(x+2\right)^2\)
\(=\left(x+2\right)\left(x-2+x+2\right)\)
=2x(x+2)
\(a,=x\left(x-3\right)-4y\left(x-3\right)=\left(x-4y\right)\left(x-3\right)\\ b,=\left(x-1\right)\left(x^2+x+1\right)-4x\left(x-1\right)=\left(x-1\right)\left(x^2-3x+1\right)\\ c,=\left(x-y\right)\left(1-a\right)\\ d,=\left(x-2\right)\left(x-2+x+2\right)=2x\left(x-2\right)\\ e,=x^2\left(x+y\right)-xz\left(x+y\right)=x\left(x-z\right)\left(x+y\right)\\ f,=\left(x-y-2\right)\left(x+y\right)\)
Phân tích đa thức sau thành nhân tử
a.3x mũ2 -12xy
b.x mũ 2+7x-2(x+7)
c.8x mũ 3 -8x mũ 2+2x
d.x mũ 2 -y mũ 2+12y-36
Giúp e vs
\(a.3x^2-12xy=3x\left(x-4y\right)\)
\(b.x^2+7x-2\left(x+7\right)=x\left(x+7\right)-2\left(x+7\right)=\left(x-2\right)\left(x+7\right)\)
\(c.8x^3-8x^2+2x=2x\left(4x^2-4+1\right)=2x\left(2x-1\right)^2\)
\(d.x^2-y^2+12y-36=x^2-\left(y-6\right)^2=\left(x-y-6\right)\left(x-y+6\right)\)
Bài làm
a) 3x2 - 12xy
= 3x( x - 4y )
b) x2 + 7x - 2( x + 7 )
= x( x + 7 ) - 2( x + 7 )
= ( x + 7 )( x - 2 )
c) 8x3 - 8x2 + 2x
= 2x( 4x2 - 4x + 1 )
= 2x( 2x - 1 )2
d) x2 - y2 + 12y - 36
= x2 - ( y2 - 12y + 36 )
= x2 - ( y2 - 2.y.6 + 62 )
= x2 - ( y - 6 )2
= ( x - y + 6 )( x + y - 6 )
# Học tốt #
Phân tích đa thức thành nhân tử A. 4x^2-12xy+9y^2-8x+12y B. 3x^2+20x-7 C. (3x-1)^4+2(9y^2-6x+1)+1 D. 2x^3-3x^2+2x-1
a: =(2x-3y)^2-4(2x-3y)
=(2x-3y)(2x-3y-4)
b: =3x^2+21x-x-7
=(x+7)(3x-1)
c: =(3x-1)^4+2(3x-1)^2+1
=[(3x-1)^2+1]^2
d: =2x^3-2x^2-x^2+x+x-1
=(x-1)(2x^2-x+1)
phân tích đa thức thành nhân tử
a, x^4 - x^5
b, -8x^2y^2 - 12xy^3 - 4xy^2
c,(x-y)^3 - x^3 + y^3
a) x4 - x5 = x4( x - 1 )
b) -8x2y2 - 12xy3 - 4xy2
= -4xy( 2xy + 3y2 + y )
c) ( x - y )3 - x3 + y3
= x3 - 3x2y + 3xy2 - y3 - x3 + y3
= 3xy2 - 3x2y
= 3xy( y - x )