\(2C_xH_yO_z+\dfrac{4x+y-2z}{2}O_2\underrightarrow{t^o}2xCO_2+yH_2O\)

\(2C_xH_yO+\dfrac{4x+y-2}{2}O_2\underrightarrow{t^o}2xCO_2+yH_2O\)

\(6Fe_xO_y+\left(12x-2y\right)H_2SO_{4\left(đ\right)}\underrightarrow{t^o}3xFe_2\left(SO_4\right)_3+\left(3x-2y\right)S+\left(12x-2y\right)H_2O\)

\(8Fe_xO_y+\left(30x-4y\right)HNO_3\rightarrow8xFe\left(NO_3\right)_3+\left(3x-2y\right)N_2O+\left(15x-2y\right)H_2O\)

1) 2

2) C_nH_{2n + 2} + \(\dfrac{3n+1}{2}\) O₂ -> nCO₂ + (n+1)H₂O.

3) C_nH_{2n – 2} + \(\dfrac{3n-1}{2}\) O₂ -> nCO₂ +(n-1) H2O.

4) C_nH_2n-6 +\(\dfrac{3n-3}{2}\) O2 -> nCO2 + (n-3) H2O

5) O+\(\dfrac{3n}{2}\)O2→n+(n+1)H2O

6) 2C_xH_yO_z + \(\dfrac{4x+y-2z}{2}\) O2 →2x CO₂ + yH₂O

7)

8)

9) 2

10)

11)

12) 3

FexOy+yCO--->xFe+yCO2

3CaO+2H3PO4--->Ca3(PO4)2+3H2O

Fe3O4+8HCl--->FeCl2+2FeCl3+4H2O

FexOy+2yHCl--->xFeCl2y/x+yH2O

Al2O3+6HCl--->2AlCl3+3H2O

Fe_xO_y + yCO --to--> xFe + yCO₂

3CaO + 2H₃PO₄ --> Ca₃(PO₄)₂ + 3H₂O

Fe₃O₄ + 8HCl --> FeCl₂ + 2FeCl₃ + 4H₂O

Fe_xO_y + 2yHCl --> xFeCl_2y/x + yH₂O

Al₂O₃ + 6HCl --> 2AlCl₃ + 3H₂O

\(2KHCO_3+Ca\left(OH\right)_2\rightarrow K_2CO_2+CaCO_3+2H_2O\)

\(Al_2O_3+6KHSO_4\rightarrow Al_2\left(SO_4\right)_3+3K_2SO_4+3H_2O\)

\(nFe_2O_3+\left(3y-2x\right)H_2\rightarrow2Fe_xO_y+\left(3y-2x\right)H_2O\)

\(2NaHSO_4+BaCO_3\rightarrow Na_2SO_4+BaSO_4+CO_2+H_2O\)

\(6H_2SO_4+2Fe\rightarrow Fe_2\left(SO_4\right)_3+3SO_2+6H_2O\)

3nAl + (6n-4m)Fe_xO_y \(\underrightarrow{t^0}\) 6Fe_nO_m + (3n-2m)Al₂O₃ 

FeO + 2HCl => FeCl₂ + H₂O

xFeCl_x + Cl₂ => xFeCl₃ 

Bạn xem lại đề nha , mình sửa lại rồi đấy

a) 2FeCl₂ + Cl₂ \(\underrightarrow{to}\) 2FeCl₃

b) Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O

c) 3KOH + H₃PO₄ → K₃PO₄ + 3H₂O

d) 4CO + Fe₃O₄ \(\underrightarrow{to}\) 3Fe + 4CO₂

e) 3Cl₂ + 6KOH → 5KCl + KClO₃ + 3H₂O

g) 4Zn + 5H₂SO₄ → 4ZnSO₄ + H₂S + 4H₂O

a) 2FeCl₂ + Cl₂ \(\rightarrow\) 2FeCl₃

b) Al₂O₃ + 6HCl \(\rightarrow\) 2AlCl₃ + 3H₂O

c) 3KOH + H₃PO₄ \(\rightarrow\) K₃PO₄ + 3H₂O

d) 4CO + Fe₃O₄ \(\rightarrow\) 3Fe + 4CO₂

e) 3Cl₂ + 6KOH \(\rightarrow\) 5KCl + KClO₃ + 3H₂O

g) 4Zn + 5H₂SO₄ \(\rightarrow\) 4ZnSO₄ + H₂S + 4H₂O

1: 2Ag + 2H2SO4 --> Ag2SO4 + SO2 + 2H2O

2: Ba(HCO3)2 + Ca(OH)2 --> BaCO3 + CaCO3 + 2H2O

3: Fe2O3 + 6HNO3 --> 2Fe(NO3)3 + 3H2O

4: 2FexOy + (3x-2y)O2 --to--> xFe2O3

5: 2KMnO4 + 16HCl --> 2KCl + 2MnCl2 + 5Cl2 + 8H2

Mới lớp 8 mà cân bằng electron rồi à bạn :3

a) 1:2:1:2:2

b) 1:2:1:1:2

c) 2:16:2:2:5:8

d) 10:2:8:5:1:2:8

e) 8:30:8:3:9

Cân bằng các PTHH sau :

a) ${\left(N{H}_4\right)}_{2}C{O}_3+2NaOH\to N{a}_{2}C{O}_3+2N{H}_3+2H_{2}O$

b)$Cu+2H_{2}S{O}_4\to CuS{o}_4+S{O}_2+2H_{2}O$

c)2 $KMn{O}_4+16HCl\to 2KCl+2MnC{l}_2+5C{l}_2+8H_{2}O$

d)10$FeS{O}_4+2KMn{O}_4+8H_{2}S{O}_4\to F{e}_2{\left(S{O}_4\right)}_3+2K_{2}S{O}_4+8MnS{O}_4+{\mathrm{H2}}^{}O$

e)8$Al+30HN{O}_3\to 8Al{\left(N{O}_3\right)}_3+3N{H}_{4}N{O}_3+9H_{2}O$

a) \(K_2O+H_2O->2KOH\)

b) \(2Fe+3Cl_2->2FeCl_3\)

c) \(2Al\left(OH\right)_3+3H_2SO_4->Al_2\left(SO_4\right)_3+6H_2O\)

d) \(4FeS_2+11O_2->2Fe_2O_3+8SO_2\)

e)\(2Al+6HCl->2AlCl_3+3H_2\)

f) \(2KClO_3->KCl+3O_2\)

g) \(4P+5O_2->2P_2O_5\)

h) \(3Fe+2O_2->Fe_3O_4\)

i) \(2Al+3CuSO_4->Al_2\left(SO_4\right)_3+3Cu\)

j) \(2K+2H_2O->2KOH+H_2\)