Question

Cân bằng các PTHH sau :

a) \(\left(NH_4\right)_2CO_3+NaOH\rightarrow Na_2CO_3+NH_3+H_2O\)

b) \(Cu+H_2SO_4\rightarrow CuSo_4+SO_2+H_2O\)

c) \(KMnO_4+HCl\rightarrow KCl+MnCl_2+Cl_2+H_2O\)

d) \(FeSO_4+KMnO_4+H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+K_2SO_4+MnSO_4+H_2O\)

e) \(Al+HNO_3\rightarrow Al\left(NO_3\right)_3+NH_4NO_3+H_2O\)

Answer 1

Mới lớp 8 mà cân bằng electron rồi à bạn :3

a) 1:2:1:2:2

b) 1:2:1:1:2

c) 2:16:2:2:5:8

d) 10:2:8:5:1:2:8

e) 8:30:8:3:9

Answer 2

Cân bằng các PTHH sau :

a) ${\left(N{H}_4\right)}_{2}C{O}_3+2NaOH\to N{a}_{2}C{O}_3+2N{H}_3+2H_{2}O$

b)$Cu+2H_{2}S{O}_4\to CuS{o}_4+S{O}_2+2H_{2}O$

c)2 $KMn{O}_4+16HCl\to 2KCl+2MnC{l}_2+5C{l}_2+8H_{2}O$

d)10$FeS{O}_4+2KMn{O}_4+8H_{2}S{O}_4\to F{e}_2{\left(S{O}_4\right)}_3+2K_{2}S{O}_4+8MnS{O}_4+{\mathrm{H2}}^{}O$

e)8$Al+30HN{O}_3\to 8Al{\left(N{O}_3\right)}_3+3N{H}_{4}N{O}_3+9H_{2}O$