phần e là cả hai dòng nhé các bạn

bn viết rõ đề đi bn

Vd:x2 là 2.x hay x\(^2\)

Có nhiều chỗ vậy lắm bn ạ,bn viết lại đề đi rồi tụi mk giúp cho.

a) \(3x-3y+x^2-y^2\)

\(=3\left(x-y\right)+\left(x+y\right)\left(x-y\right)\)

\(=\left(3+x+y\right)\left(x-y\right)\)

b) \(\left(2xy+1\right)^2-\left(2x+y\right)^2\)

\(=\left[\left(2xy+1\right)-\left(2x+y\right)\right]\left[\left(2xy+1\right)+\left(2x+y\right)\right]\)

\(=\left(2xy+1-2x-y\right)\left(2xy+1+2x+y\right)\)

\(=\left(y+1\right)\left(2x+1\right)\left(y-1\right)\left(2x-1\right)\)

c) \(\left(x^2+y^2-5\right)^2-4\left(x^2y^2+4xy+4\right)\)

↓

\(=\left(x^2-y^2-2y-1\right)\left(x^2-2xy+y^2-9\right)\)

\(=\left[x^2-\left(y^2+2y+1\right)\right]\left(x^2-2xy+y^2-9\right)\)

\(=\left[x^2-\left(y+1\right)^2\right]\left[\left(x-y\right)^2-3^2\right]\)

\(=\left[x^2-\left(-y-1\right)^2\right]\left(x-y+3\right)\left(x-y-3\right)\)

\(=\left(x+y+1\right)\left(x-y-1\right)\left(x-y+3\right)\left(x-y-3\right)\)

d) \(\left(x^2+y^2-z^2\right)^2-4x^2y^2\)

\(=\left(x^2+y^2-z^2\right)^2-\left(2xy\right)^2\)

\(=\left(x^2+y^2-z^2-2xy\right)\left(x^2+y^2-z^2+2xy\right)\)

\(=\left[\left(x-y\right)^2-z^2\right]\left[\left(x+y\right)^2-z^2\right]\)

\(=\left(x-y-z\right)\left(x-y+z\right)\left(x+y-z\right)\left(x+y+z\right)\)

e)

- \(9x^2+90=9\left(x+10\right)\)

- \(x+225-\left(x-7\right)^2\)

\(=x+225-\left(x^2-14x+49\right)\)

\(=x+225-x^2+14x-49\)

\(=-x^2+15x+176\)

\(=-\left(x^2-15x-176\right)\)

e: \(x^2+6x+9-y^2\)

\(=\left(x+3\right)^2-y^2\)

\(=\left(x+3-y\right)\left(x+3+y\right)\)

f: \(x^2-2x+7x-14\)

\(=x\left(x-2\right)+7\left(x-2\right)\)

=(x-2)(x+7)

h: \(5x^2-10xy+5y^2-20\)

\(=5\left(x^2-2xy+y^2-4\right)\)

\(=5\left(x-y-2\right)\left(x-y+2\right)\)

a: \(3x^4-6x^3+2x^2=x^2\left(3x^2-6x+2\right)\)

b: \(x^3y+12x^2y+36xy=xy\left(x^2+12x+36\right)=xy\left(x+6\right)^2\)

c: \(x^3y-9xy^3=xy\left(x^2-9y^2\right)=xy\left(x-3y\right)\left(x+3y\right)\)

d: \(x^2y^2-2xy^2+y^2=y^2\left(x-1\right)^2\)

a) \(=x^2+7x-12x-84-2x+14\)

\(=x^2-7x-70\)

b)\(=x^2-4x-2x+8\)

\(=x\left(x-4\right)-2\left(x-4\right)\)

 \(=\left(x-4\right)\left(x-2\right)\)

c) \(=9x\left(x+y\right)-\left(x+y\right)\)

\(=\left(9x-1\right)\left(x+y\right)\)

d)\(=\left(x-y\right)^2-9^2\)

\(=\left(x-y+9\right)\left(x-y-9\right)\)

e)\(=x^2+8x+16-60+15x\)

\(=x^2+23x-44\)

a) Ta có: \(\left(x-12\right)\left(x+7\right)-2x-14\)

\(=\left(x-12\right)\left(x+7\right)-2\left(x+7\right)\)

\(=\left(x+7\right)\left(x-14\right)\)

b) Ta có: \(x^2-6x+8\)

\(=x^2-2x-4x+8\)

\(=\left(x-2\right)\left(x-4\right)\)

c) Ta có: \(9x^2+9xy-\left(x+y\right)\)

\(=9x\left(x+y\right)-\left(x+y\right)\)

\(=\left(x+y\right)\left(9x-1\right)\)

d) Ta có: \(\left(x^2-2xy+y^2\right)-81\)

\(=\left(x-y\right)^2-81\)

\(=\left(x-y-9\right)\left(x-y+9\right)\)

a) 3(x-y) - (x-y)^2

 =(x-y)(3-x+y)

b) =(x+y)^2 - (2xy)^2

= (x+y-2xy)(x+y+2xy)

\(a,=3\left(x-y\right)-\left(x-y\right)^2=\left(x-y\right)\left(3-x+y\right)\\ b,=\left(x+y\right)^2-4x^2y^2=\left(x-2xy+y\right)\left(x+2xy+y\right)\\ c,=\left(x+y-x+y\right)\left[\left(x+y\right)^2+\left(x+y\right)\left(x-y\right)+\left(x-y\right)^2\right]\\ =2y\left(x^2+2xy+y^2+x^2-y^2+x^2-2xy+y^2\right)\\ =2y\left(3x^2+y^2\right)\\ d,=x^2+2x-7x-14=\left(x+2\right)\left(x-7\right)\)

Lần sau bạn chú ý viết đầy đủ yêu cầu của đề bài.

a) \(A=x^2+x-2=\left(x+2\right)\left(x-1\right)\)

b) \(B=-x^2+4x+5=-\left(x^2-4x-5\right)=-\left(x-5\right)\left(x+1\right)\)

c) \(C=9x^2-6x+3=3\left(3x^2-2x+1\right)\)

\(1,Sửa:A=4x^4+4x^2y+y^2+2=\left(2x^2+y\right)^2+2\ge2\\ A_{min}=2\Leftrightarrow2x^2+y=0\Leftrightarrow x^2=-\dfrac{y}{2}\\ 2,B=\left(x+y\right)^2+\left(y+1\right)^2+12\ge12\\ B_{min}=12\Leftrightarrow\left\{{}\begin{matrix}x=-y=1\\y=-1\end{matrix}\right.\)

1) \(=\left(9x^2-25y^2\right)-\left(6x-10y\right)=\left(3x-5y\right)\left(3x+5y\right)-2\left(3x-5y\right)=\left(3x-5y\right)\left(3x+5y-2\right)\)

2) \(=9x^2y^2-\left(x^2-2xy+y^2\right)=9x^2y^2-\left(x-y\right)^2=\left(3xy-x+y\right)\left(3xy+x-y\right)\)

Chia nhỏ ra cậu ơi :v

Cậu đặt câu hỏi free nên đặt nhỏ ra thì mới có người làm nha để như này dày cộp không ai dám làm đou =(((