Phân tích thành nhân tử:
a) 24a2b-36ab2-60b3
b)2x2y-3x+3x2-2xy
c)x2-y2-6x+9
Những câu hỏi liên quan
Phân tích các đa thức sau thành nhân tử:a) 3x - 3y +
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; b)
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-4
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+ 2xy c)
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Phân tích các đa thức sau thành nhân tử:
a) 3x - 3y + x 2 - y 2 ; b) x 2 -4 x 2 y 2 + y 2 + 2xy
c) x 6 - x 4 + 2 x 3 + 2 x 2 ; d) x 3 - 3x 2 +3x - 1 - y 3 .
a) (x - y)(x + y + 3). b) (x + y - 2xy)(2 + y + 2xy).
c) x 2 (x + l)( x 3 - x 2 + 2). d) (x – 1 - y)[ ( x - 1 ) 2 + ( x - 1 ) y + y 2 ].
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Phân tích đa thức thành nhân tử
3x2(a-b+c)+36xy(a-b+c)+108y2(a-b+c)
x2-2xy+y2-4m2+4mn-n2
\(3x^2\left(a-b+c\right)+36xy\left(a-b+c\right)+108y^2\left(a-b+c\right)\)
\(=\left(a-b+c\right)\left(3x^2+36xy+108y^2\right)\)
\(=3\left(a-b+c\right)\left(x^2+12xy+36y^2\right)\)
\(=3\left(a-b+c\right)\left(x+6y\right)^2\)
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\(x^2-2xy+y^2-4m^2+4mn-n^2\)
\(=\left(x^2-2xy+y^2\right)-\left(4m^2-4mn+n^2\right)\)
\(=\left(x-y\right)^2-\left(2m-n\right)^2\)
\(=\left(x-y-2m+n\right)\left(x-y+2m-n\right)\)
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Phân tích đa thức thành nhân tử (bằng phương pháp nhóm hạng tử)
c/ 5x2 + 3y + 15x + xy d/ x2 + 6x + 9 – y2
e/ x2 – y2 + 2x + 1 f/ x2 – 2xy – 9 + y2
c) \(5x^2+3y+15x+xy=5x\left(x+3\right)+y\left(x+3\right)=\left(x+3\right)\left(5x+y\right)\)
d) \(x^2+6x+9-y^2=\left(x+3\right)^2-y^2=\left(x+3-y\right)\left(x+3+y\right)\)
e) \(x^2-y^2+2x+1=\left(x^2+2x+1\right)-y^2=\left(x+1\right)^2-y^2=\left(x+1-y\right)\left(x+1+y\right)\)
f) \(x^2-2xy-9+y^2=\left(x^2-2xy+y^2\right)-9=\left(x-y\right)^2-3^2=\left(x-y-3\right)\left(x-y+3\right)\)
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c: \(5x^2+15x+3y+xy\)
\(=5x\left(x+3\right)+y\left(x+3\right)\)
\(=\left(x+3\right)\left(5x+y\right)\)
d: \(x^2+6x+9-y^2\)
\(=\left(x+3\right)^2-y^2\)
\(=\left(x+3-y\right)\left(x+3+y\right)\)
e: \(x^2+2x+1-y^2\)
\(=\left(x+1\right)^2-y^2\)
\(=\left(x+1-y\right)\left(x+1+y\right)\)
f: \(x^2-2xy+y^2-9\)
\(=\left(x-y\right)^2-9\)
\(=\left(x-y-3\right)\left(x-y+3\right)\)
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Bài 2 Phân tích thành nhân tửa) 3x2 – 7x – 10b) x2 + 6x +9 – 4y2c) x2 – 2xy + y2 – 5x + 5y’d) 4x2 – y2 – 6x + 3ye) 1 – 2a + 2bc + a2 – b2 – c2 f) x3 – 3x2 – 4x + 12g) x4 + 64h) x4 – 5x2 + 4i) (x+1)(x+3)(x+5)(x+7) + 16j) (x2 + 6x +8)( x2 + 14x + 48) – 9k) ( x2 – 8x + 15)(x2 – 16x + 60) – 24x2l) 4( x2 + 15x + 50)(x2 +18x +72) – 3x2 Bài 3 tìm gtnnA 9x2 – 6x + 2B 4x2 + 5x + 10C x2 – x + 10D 4x2 + 3x + 20E x2 + y2 – 6xy + 10y + 35F x2 + y2 – 6x + 4y +2M 2x2 + 4y2 – 4xy – 4x – 4y +2021
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Bài 2 Phân tích thành nhân tử
a) 3x2 – 7x – 10
b) x2 + 6x +9 – 4y2
c) x2 – 2xy + y2 – 5x + 5y’
d) 4x2 – y2 – 6x + 3y
e) 1 – 2a + 2bc + a2 – b2 – c2
f) x3 – 3x2 – 4x + 12
g) x4 + 64
h) x4 – 5x2 + 4
i) (x+1)(x+3)(x+5)(x+7) + 16
j) (x2 + 6x +8)( x2 + 14x + 48) – 9
k) ( x2 – 8x + 15)(x2 – 16x + 60) – 24x2
l) 4( x2 + 15x + 50)(x2 +18x +72) – 3x2
Bài 3 tìm gtnn
A = 9x2 – 6x + 2
B = 4x2 + 5x + 10
C = x2 – x + 10
D = 4x2 + 3x + 20
E = x2 + y2 – 6xy + 10y + 35
F= x2 + y2 – 6x + 4y +2
M= 2x2 + 4y2 – 4xy – 4x – 4y +2021
Bài 2:
a) \(3x^2-7x-10=\left(x+1\right)\left(3x-10\right)\)
b) \(x^2+6x+9-4y^2=\left(x+3\right)^2-\left(2y\right)^2=\left(x+3-2y\right)\left(x+3+2y\right)\)
c) \(x^2-2xy+y^2-5x+5y=\left(x-y\right)^2-5\left(x-y\right)=\left(x-y\right)\left(x-y-5\right)\)
d) \(4x^2-y^2-6x+3y=\left(2x-y\right)\left(2x+y\right)-3\left(2x-y\right)=\left(2x-y\right)\left(2x+y-3\right)\)
e) \(1-2a+2bc+a^2-b^2-c^2=\left(a-1\right)^2-\left(b-c\right)^2=\left(a-1-b+c\right)\left(a-1+b-c\right)\)
f) \(x^3-3x^2-4x+12=\left(x+2\right)\left(x-3\right)\left(x-2\right)\)
g) \(x^4+64=\left(x^2+8\right)^2-16x^2=\left(x^2+8-4x\right)\left(x^2+6+4x\right)\)h) \(x^4-5x^2+4=\left(x+2\right)\left(x+1\right)\left(x-1\right)\left(x-2\right)\)
i) \(\left(x+1\right)\left(x+3\right)\left(x+5\right)\left(x+7\right)+16=\left(x^2+8x+7\right)\left(x^2+8x+15\right)+16=\left(x^2+8x+7\right)^2+8\left(x^2+8x+7\right)+16=\left(x^2+8x+11\right)^2\)
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a: \(3x^2-7x-10\)
\(=3x^2+3x-10x-10\)
\(=\left(x+1\right)\left(3x-10\right)\)
b: \(x^2+6x+9-4y^2\)
\(=\left(x+3\right)^2-4y^2\)
\(=\left(x+3-2y\right)\left(x+3+2y\right)\)
c: \(x^2-2xy+y^2-5x+5y\)
\(=\left(x-y\right)^2-5\left(x-y\right)\)
\(=\left(x-y\right)\left(x-y-5\right)\)
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a) 3x2−7x−10=(x+1)(3x−10)3x2−7x−10=(x+1)(3x−10)
b) x2+6x+9−4y2=(x+3)2−(2y)2=(x+3−2y)(x+3+2y)x2+6x+9−4y2=(x+3)2−(2y)2=(x+3−2y)(x+3+2y)
c) x2−2xy+y2−5x+5y=(x−y)2−5(x−y)=(x−y)(x−y−5)x2−2xy+y2−5x+5y=(x−y)2−5(x−y)=(x−y)(x−y−5)
d) 4x2−y2−6x+3y=(2x−y)(2x+y)−3(2x−y)=(2x−y)(2x+y−3)4x2−y2−6x+3y=(2x−y)(2x+y)−3(2x−y)=(2x−y)(2x+y−3)
e) 1−2a+2bc+a2−b2−c2=(a−1)2−(b−c)2=(a−1−b+c)(a−1+b−c)1−2a+2bc+a2−b2−c2=(a−1)2−(b−c)2=(a−1−b+c)(a−1+b−c)
f) x3−3x2−4x+12=(x+2)(x−3)(x−2)x3−3x2−4x+12=(x+2)(x−3)(x−2)
g) x4+64=(x2+8)2−16x2=(x2+8−4x)(x2+6+4x)x4+64=(x2+8)2−16x2=(x2+8−4x)(x2+6+4x)h) x4−5x2+4=(x+2)(x+1)(x−1)(x−2)x4−5x2+4=(x+2)(x+1)(x−1)(x−2)
i) (x+1)(x+3)(x+5)(x+7)+16=(x2+8x+7)(x2+8x+15)+16=(x2+8x+7)2+8(x2+8x+7)+16=(x2+8x+11)2(x+1)(x+3)(x+5)(x+7)+16=(x2+8x+7)(x2+8x+15)+16=(x2+8x+7)2+8(x2+8x+7)+16=(x2+8x+11)2
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Bài 1: Phân tích đa thức thành nhân tử a) a/ x2 – 2xb) 2bx – 3ay – 6by + ax c) x3 +2x2y + xy2 – 4x d) 4 - x2 – 2xy – y2 đ) 5x2 + 3(x + y)2 – 5y2 e/ 6x2y – 9x b/ 4x3 – 4x2y + xy2 – 16 xf) x2 + (2x +y)y – z2
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Bài 1: Phân tích đa thức thành nhân tử
a) a/ x2 – 2x
b) 2bx – 3ay – 6by + ax
c) x3 +2x2y + xy2 – 4x
d) 4 - x2 – 2xy – y2
đ) 5x2 + 3(x + y)2 – 5y2
e/ 6x2y – 9x
b/ 4x3 – 4x2y + xy2 – 16 x
f) x2 + (2x +y)y – z2
\(a,=x\left(x-2\right)\\ b,=2b\left(x-3y\right)+a\left(x-3y\right)=\left(a+2b\right)\left(x-3y\right)\\ c,=x\left(x^2+2xy+y^2-4\right)=x\left[\left(x+y\right)^2-4\right]=x\left(x+y+2\right)\left(x+y-2\right)\\ d,=4-\left(x+y\right)^2=\left(2-x-y\right)\left(2+x+y\right)\\ đ,=5\left(x-y\right)\left(x+y\right)+3\left(x+y\right)^2=\left(x+y\right)\left(5x-5y+3x+3y\right)\\ =\left(x+y\right)\left(8x-2y\right)=2\left(4x-y\right)\left(x+y\right)\\ e,=3x\left(2xy-3\right)\\ b,=x\left(4x^2-4xy+y^2-4\right)=x\left[\left(2x-y\right)^2-4\right]=x\left(2x-y-2\right)\left(2x-y+2\right)\\ f,=\left(x+y\right)^2-z^2=\left(x+y-z\right)\left(x+y+z\right)\)
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a,=x(x−2)b,=2b(x−3y)+a(x−3y)=(a+2b)(x−3y)c,=x(x2+2xy+y2−4)=x[(x+y)2−4]=x(x+y+2)(x+y−2)d,=4−(x+y)2=(2−x−y)(2+x+y)đ,=5(x−y)(x+y)+3(x+y)2=(x+y)(5x−5y+3x+3y)=(x+y)(8x−2y)=2(4x−y)(x+y)e,=3x(2xy−3)b,=x(4x2−4xy+y2−4)=x[(2x−y)2−4]=x(2x−y−2)(2x−y+2)f,=(x+y)2−z2=(x+y−z)(x+y+z)
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Phân tích tử và mẫu thành nhân tử rồi rút gọn phân thức:
a) x2 + xy +x + y / x2 - xy + x - y
b) x2 - 6x+ 9 / 3x2 - 9x
c) y2 - x2 / x2y - xy2
\(a,=\dfrac{\left(x+1\right)\left(x+y\right)}{\left(x-y\right)\left(x+1\right)}=\dfrac{x+y}{x-y}\\ b,=\dfrac{\left(x-3\right)^2}{3x\left(x-3\right)}=\dfrac{x-3}{3x}\\ c,=\dfrac{\left(y-x\right)\left(y+x\right)}{xy\left(x-y\right)}=\dfrac{-x-y}{xy}\)
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Lời giải:
a.
\(\frac{x^2+xy+x+y}{x^2-xy+x-y}=\frac{x(x+y)+(x+y)}{x(x+1)-y(x+1)}=\frac{(x+y)(x+1)}{(x+1)(x-y)}=\frac{x+y}{x-y}\)
b.
\(\frac{x^2-6x+9}{3x^2-9x}=\frac{(x-3)^2}{3x(x-3)}=\frac{x-3}{3x}\)
c.
\(\frac{y^2-x^2}{x^2y-xy^2}=\frac{(y-x)(y+x)}{-xy(y-x)}=\frac{x+y}{-xy}\)
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phân tích các đa thức sau thành nhân tử
a x2 - y2 -3x + 3y
b 2x + 2y -x2 + y2
c x2 -16 + y2 + 2xy
cứuuu
a) \(x^2-y^2-3x+3y\)
\(=\left(x-y\right)\left(x+y\right)-3\left(x-y\right)\)
\(=\left(x-y\right)\left(x+y-3\right)\)
b) \(2x+2y-x^2+y^2\)
\(=2\left(x+y\right)-\left(x^2-y^2\right)\)
\(=2\left(x+y\right)-\left(x-y\right)\left(x+y\right)\)
\(=\left(x+y\right)\left(2-x+y\right)\)
c) \(x^2-16+y^2+2xy\)
\(=x^2+y^2+2xy-16\)
\(=\left(x+y\right)^2-16\)
\(=\left(x+y+4\right)\left(x+y-4\right)\)
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a) \(x^2-y^2-3x+3y\)
\(=\left(ax+y\right)\left(ax-y\right)-3.\left(x-y\right)\)
b) \(2x+2y-x^2+y^2\)
\(=2\left(x+y\right)-\left(x+y\right)\left(x-y\right)\)
c) \(x^2-16+y^2+2xy\)
\(=\left(x+y\right)\left(x-y\right)+2xy-16\)
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8 tháng 5 2022 lúc 20:50
phân tích các đa thức sau thành nhân tử:
a, A= x2 - 6x + 9 - 9y2
b, B= x3 - 3x2 + 3x - 1 + 2(x2 - 1)
a) \(A=x^2-6x+9-9y^2\)
\(=\left(x-3\right)^2-\left(3y\right)^2\)
\(=\left(x-3-3y\right)\left(x-3+3y\right)\)
b) \(B=x^3-3x^2+3x-1+2\left(x^2-1\right)\)
\(=\left(x-1\right)^3+\left(2x+2\right)\left(x-1\right)\)
\(=\left(x-1\right)\left[\left(x-1\right)^2+2x+2\right]\)
\(=\left(x-1\right).\left(x^2+3\right)\)
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a, \(A=\left(x-3\right)^2-9y^2=\left(x-3-3y\right)\left(x-3+3y\right)\)
b, \(B=\left(x-1\right)^3+2\left(x-1\right)\left(x+1\right)=\left(x-1\right)\left[\left(x-1\right)^2+2\left(x+1\right)\right]\)
\(=\left(x-1\right)\left(x^2-2x+1+2x+2\right)=\left(x-1\right)\left(x^2+3\right)\)
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phân tích các đa thức sau thành nhân tử:
a, A= x2 - 6x + 9 - 9y2
b, B= x3 - 3x2 + 3x - 1 + 2(x2 - 1)
PHÂN TÍCH CÁC ĐA THỨC SAU THÀNH NHÂN TỬ BẰNG PHƯƠNG PHÁP NHÓM NHIỀU HẠNG TỬ :
a) x2 -2x -4y2-4y
b) x4 + 2x3 - 4x -4
c) x3 + 2x2y -x -2y
d) 3x2 -3y2 -2(x-y)2
e) x3 -4x2 -9x +36
f) x2 -y2 -2x -2y
a: Ta có: \(x^2-4y^2-2x-4y\)
\(=\left(x-2y\right)\left(x+2y\right)-2\left(x+2y\right)\)
\(=\left(x+2y\right)\left(x-2y-2\right)\)
c: Ta có: \(x^3+2x^2y-x-2y\)
\(=x^2\left(x+2y\right)-\left(x+2y\right)\)
\(=\left(x+2y\right)\left(x-1\right)\left(x+1\right)\)
d: Ta có: \(3x^2-3y^2-2\cdot\left(x-y\right)^2\)
\(=3\left(x-y\right)\left(x+y\right)-2\cdot\left(x-y\right)^2\)
\(=\left(x-y\right)\left(3x+3y-2x+2y\right)\)
\(=\left(x-y\right)\left(x+5y\right)\)
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e: Ta có: \(x^3-4x^2-9x+36\)
\(=x^2\left(x-4\right)-9\left(x-4\right)\)
\(=\left(x-4\right)\left(x-3\right)\left(x+3\right)\)
f: Ta có: \(x^2-y^2-2x-2y\)
\(=\left(x-y\right)\left(x+y\right)-2\left(x+y\right)\)
\(=\left(x+y\right)\left(x-y-2\right)\)
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