2Na+Cl2-to>2NaCl

n Na=9,2\23=0,4 mol

n Cl2=6,72\22,4=0,3 mol

=>Na hết , cl dư 0,1 mol

=>m NaCl=0,2.58,5=11,7g

=>m Cl2 dư=0,1 .71=7,1g

1.

\(4Na+O_2\underrightarrow{t^0}2Na_2O\)

\(4Al+3O_2\underrightarrow{t^0}2Al_2O_3\)

\(4P+5O_2\underrightarrow{t^0}2P_2O_5\)

\(2Ca+O_2\underrightarrow{t^0}2CaO\)

2. 

\(P+3H_2\underrightarrow{t^0}2PH_3\)

\(CuO+H_2\underrightarrow{t^0}Cu+H_2O\)

\(Fe_3O_4+4H_2\underrightarrow{t^0}3Fe+4H_2O\)

3. 

\(Na+H_2O\rightarrow NaOH+\dfrac{1}{2}H_2\)

\(Ca+2H_2O\rightarrow Ca\left(OH\right)_2+H_2\)

\(K_2O+H_2O\rightarrow2KOH\)

\(P_2O_5+3H_2O\rightarrow2H_3PO_4\)

\(CaO+H_2O\rightarrow Ca\left(OH\right)_2\)

\(3NO_2+H_2O\rightarrow2HNO_3+NO\)

1) Na,Al,Ca,P

\(4Na + O_2 \xrightarrow{t^o} 2Na_2O\\ 4Al + 3O_2 \xrightarrow{t^o} 2Al_2O_3\\ 2Ca + O_2 \xrightarrow{t^o} 2CaO\\ 4P + 5O_2 \xrightarrow{t^o} 2P_2O_5\\ \)

2) CuO,Fe₃O₄

\(CuO + H_2 \xrightarrow{t^o} Cu + H_2O\\ Fe_3O_4 + 4H_2 \xrightarrow{t^o} 3Fe + 4H_2O\)

3) Na,Ca,K₂O,P₂O₅,CaO,NO₂

\(2Na + 2H_2O \to 2NaOH + H_2\\ Ca + 2H_2O \to Ca(OH)_2 + H_2\\ K_2O + H_2O \to 2KOH\\ P_2O_5 + 3H_2O \to 2H_3PO_4\\ CaO + H_2O \to Ca(OH)_2\\ 3NO_2 + H_2O \to 2HNO_3 + NO\)

Bảo toàn khối lượng: 

\(m_{Na}+m_{Cl_2}=m_{NaCl}\\ \Rightarrow m_{Cl_2}=5,85-2,3=3,55\left(g\right)\)

Bảo toàn khối lượng : 

\(m_{Cl_2}=m_{NaCl}-m_{Na}=5.85-2.3=3.55\left(g\right)\)

- PT: a, \(2KMnO_4+16HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\) (1)

\(MnO_2+4HCl_đ\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\) (2) 

- Ta có: \(n_{HCl\left(1\right)}=n_{HCl\left(2\right)}=0,2.2=0,4\left(mol\right)\)

Theo PT (1): \(n_{Cl_2}=\dfrac{5}{16}n_{HCl\left(1\right)}=0,125\left(mol\right)\Rightarrow V_1=0,125.22,4=2,8\left(l\right)\)

(2): \(n_{Cl_2\left(2\right)}=\dfrac{1}{4}n_{HCl\left(2\right)}=0,1\left(mol\right)\Rightarrow V_2=0,1.22,4=2,24\left(l\right)\)

\(a,n_{Na}=\dfrac{m_{Na}}{M_{Na}}=\dfrac{4,6}{23}=0,2\left(mol\right)\\ n_{Cl_2}=\dfrac{V_{Cl_2\left(đktc\right)}}{22,4}=\dfrac{4,48}{22,4}=0,2\left(mol\right)\\ PTHH:2Na+Cl_2\rightarrow2NaCl\\ Vì:\dfrac{0,2}{2}< \dfrac{0,2}{1}\Rightarrow Cl_2dư\\ \Rightarrow n_{Cl_2\left(dư\right)}=0,2-\dfrac{0,2}{2}=0,1\left(mol\right)\\ \Rightarrow m_{Cl_2\left(dư\right)}=0,1.71=7,1\left(g\right)\\ b,n_{NaCl}=n_{Na}=0,2\left(mol\right)\\ \Rightarrow m_{NaCl}=58,5.0,2=11,7\left(g\right)\)

\(C+O_2\xrightarrow[]{t^o}CO_2\)

\(S+O_2\xrightarrow[]{t^o}SO_2\)

\(4P+5O_2\xrightarrow[]{t^o}2P_2O_5\)

\(H_2+\dfrac{1}{2}O_2\xrightarrow[]{t^o}H_2O\)

\(4Na+O_2\rightarrow2Na_2O\)

\(Mg+\dfrac{1}{2}O_2\xrightarrow[]{t^o}MgO\)

\(4Al+3O_2\xrightarrow[]{t^o}2Al_2O_3\)

\(3Fe+2O_2\xrightarrow[]{t^o}Fe_3O_4\)

\(Cu+\dfrac{1}{2}O_2\xrightarrow[]{t^o}CuO\)

\(CH_4+2O_2\xrightarrow[]{t^o}CO_2+2H_2O\)

\(4FeS_2+11O_2\xrightarrow[]{t^o}2Fe_2O_3+8SO_2\)

\(C_2H_6O+3O_2\xrightarrow[]{t^o}2CO_2+3H_2O\)

C+ O2 -to-> CO2

S+ O2 -to-> SO2

2 Cl2 + 7 O2 -to-> 2 Cl2O7

4P +5 O2 -to-> 2 P2O5

4Al + 3 O2 -to-> 2 Al2O3

4 Na+ O2 -to-> 2 Na2O

Mg + 1/2 O2 -to-> MgO

3 Fe +2  O2 -to-> Fe3O4

4 FeS2 + 11 O2 -to,xt-> 8 SO2 + 2 Fe2O3

H2 + 1/2 O2 -to->H2O

2 Ag + 1/2 O2 -to-> Ag2O

C2H6O + 3 O2 -to-> 2 CO2 + 3 H2O

CH4 + 2 O2 -to-> CO2 + 2 H2O

Cu + 1/2 O2 -to-> CuO

- Các chất tác dụng với O₂: K, Na, Ba, S, CH₄, C₂H₆O, Mg, Zn, Cu, P, C, FeS₂, SO₂

\(4K+O_2\underrightarrow{t^o}2K_2O\)

\(4Na+O_2\underrightarrow{t^o}2Na_2O\)

\(2Ba+O_2\underrightarrow{t^o}2BaO\)

\(S+O_2\underrightarrow{t^o}SO_2\)

\(CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\)

\(C_2H_6O+3O_2\underrightarrow{t^o}2CO_2+3H_2O\)

\(2Mg+O_2\underrightarrow{t^o}2MgO\)

\(2Zn+O_2\underrightarrow{t^o}2ZnO\)

\(2Cu+O_2\underrightarrow{t^o}2CuO\)

\(4P+5O_2\underrightarrow{t^o}2P_2O_5\)

\(C+O_2\underrightarrow{t^o}CO_2\)

\(4FeS_2+11O_2\underrightarrow{t^o}2Fe_2O_3+8SO_2\)

\(2SO_2+O_2\xrightarrow[V_2O_5]{t^o}2SO_3\)

a, PT: \(Fe+2HCl\rightarrow FeCl_2+H_2\)

\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

\(Zn+2HCl\rightarrow ZnCl_2+H_2\)

\(Mg+2HCl\rightarrow MgCl_2+H_2\)

\(K+HCl\rightarrow KCl+\dfrac{1}{2}H_2\)

\(Na+HCl\rightarrow NaCl+\dfrac{1}{2}H_2\)

\(Ba+2HCl\rightarrow BaCl_2+H_2\)

\(Ca+2HCl\rightarrow CaCl_2+H_2\)

b, \(2Al+2NaOH+2H_2O\rightarrow2NaAlO_2+3H_2\)

\(Zn+2NaOH\rightarrow Na_2ZnO_2+2H_2\)

Bạn tham khảo nhé!