1. A

2. C

3. C

\(\dfrac{-2}{-2}=\dfrac{3}{3}=\dfrac{-5}{-5}=\dfrac{7}{7}=\dfrac{-9}{-9}\)=1

\(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{1}{4}\right)< ...........< \dfrac{1}{48}-\left(\dfrac{1}{16}-\dfrac{1}{6}\right)\)

\(\dfrac{-1}{12}< .........< \dfrac{1}{8}\)và số ghi trong ô trống là số nguyên nên số đó phải là 0 .

a)6

b,-7

c)15

d)-4

e)20

a) \(\dfrac{1}{2}\)=\(\dfrac{6}{12}\)       b) \(\dfrac{-7}{8}\)=\(\dfrac{-28}{32}\)      c)\(\dfrac{3}{4}\)=\(\dfrac{15}{20}\)       d) \(\dfrac{-4}{9}\)=\(\dfrac{-16}{36}\)

e) \(\dfrac{3}{4}\)=\(\dfrac{15}{20}\)

HỌC TỐT

\(\dfrac{18}{30}=\dfrac{3}{5}=\dfrac{34}{40}\)

\(\dfrac{18}{30}=\dfrac{3}{5}=\dfrac{24}{40}\)

18 với 40 

a.1/3=5/15=9/27=135/405

b.63/35=54/30=45/25

a) \(\dfrac{3}{4}=\dfrac{15}{20}\)

b) \(\dfrac{4}{5}=\dfrac{12}{15}\)

c) \(\dfrac{-4}{9}=\dfrac{-16}{36}\)

d) \(\dfrac{7}{-13}=\dfrac{21}{-39}\)

a ) \(\dfrac{3}{4}\)= \(\dfrac{15}{20}\)

b )\(\dfrac{4}{5}\)= \(\dfrac{12}{15}\)

c) \(\dfrac{-4}{9}\)=\(\dfrac{-16}{36}\)

d) \(\dfrac{7}{-13}\)=\(\dfrac{21}{-39}\)

\(\dfrac{1}{3}+\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{32}{40}+\dfrac{48}{56}+\dfrac{14}{21}\\ =\dfrac{1}{3}+\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{4}{5}+\dfrac{6}{7}+\dfrac{2}{3}\\ =\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\left(\dfrac{1}{7}+\dfrac{6}{7}\right)+\left(\dfrac{1}{5}+\dfrac{4}{5}\right)\\ =1+1+1=3\)

Lời giải:

$\frac{1}{3}+\frac{1}{7}+\frac{1}{5}+\frac{32}{40}+\frac{48}{56}+\frac{14}{21}$

$=\frac{1}{3}+\frac{1}{7}+\frac{1}{5}+\frac{4}{5}+\frac{6}{7}+\frac{2}{3}$

$=(\frac{1}{3}+\frac{2}{3})+(\frac{1}{7}+\frac{6}{7})+(\frac{1}{5}+\frac{4}{5})$

$=\frac{3}{3}+\frac{7}{7}+\frac{5}{5}=1+1+1=3$

=(7/21 +14/21)+(8/56+48)+(8/40+32/40)

=1+1+1

=3