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Phạm Minh Đức
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Lê Phương Mai
26 tháng 1 2022 lúc 21:01

1, Nam wanted to watch Tom And Jerry so he turned to  the Cartoon channel.

2, You turn the TV on and you can watch your favourite show. 

3,  I’m interested in the history of television so I like reading books about it.

4, I love films but I don’t like watching them on television. 

5, Mang Tien Ve Cho Me is a meaningful song so many  listeners love it. 

Phạm Vĩnh Linh
26 tháng 1 2022 lúc 21:02

1. Nam wanted to watch Tom And Jerry. He turned to the Cartoon channel. (so)

→ Nam wanted to watch Tom And Jerry so he turned to the Cartoon channel.

2. You turn the TV on. You can watch your favourite show. (and)

→ You turn the TV on and you can watch your favourite show _______________________________________________________________________________

3. I’m interested in the history of television. I like reading books about it. (so) I’m interested in the history of television. I like reading books about it.

→  I’m interested in the history of television so I like reading books about it. _______________________________________________________________________________

4. I love films. I don’t like watching them on television. (but)

→ I love films but I don’t like watching them on television _______________________________________________________________________________

5. Mang Tien Ve Cho Me is a meaningful song. Many listeners love it. (so)

→ Mang Tien Ve Cho Me is a meaningful song so many listeners love it. _________________________________________________________________________

Hiếu Ceo
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minh nguyet
19 tháng 11 2021 lúc 16:19

A

sky12
19 tháng 11 2021 lúc 16:20

A nhé

Chu Diệu Linh
19 tháng 11 2021 lúc 16:24

A

Hihihi
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nguyễn thị hương giang
24 tháng 10 2021 lúc 18:48

Bài 9.a) Quãng đường vật rơi trong 3s đầu tiên:

              \(S_3=\dfrac{1}{2}gt^2=\dfrac{1}{2}\cdot9,8\cdot3^2=44,1\left(m\right)\)

              Quãng đường vật đi trong giây thứ 3 là:           \(S'=\dfrac{1}{2}gt^2-\dfrac{1}{2}g\left(t-1\right)^2=\dfrac{1}{2}\cdot9,8\cdot3^2-\dfrac{1}{2}\cdot9,8\cdot2^2=24,5\left(m\right)\)

Bài 10.

 a) Thời gian vật rơi khi chạm đất: \(t=\sqrt{\dfrac{2S}{g}}=\sqrt{\dfrac{2\cdot45}{10}}=3\left(s\right)\)

     Vận tốc vật khi chạm đất: \(v=g\cdot t=10\cdot3=30\)m/s

b) Quãng đường vật rơi trong giây cuối cùng:

   \(S=\dfrac{1}{2}gt^2-\dfrac{1}{2}g\left(t-1\right)^2=\dfrac{1}{2}\cdot10\cdot3^2-\dfrac{1}{2}\cdot10\cdot2^2=25\left(m\right)\)

Bài 11.

a) Quãng đường vật rơi trong 2s đầu tiên:

     \(S=\dfrac{1}{2}gt^2=\dfrac{1}{2}\cdot10\cdot2^2=20\left(m\right)\)

NGUYỄN HƯƠNG GIANG
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Nguyễn Trần Thành Đạt
13 tháng 9 2021 lúc 15:34

\(n_{Na_2O}=\dfrac{6,2}{62}=0,1\left(mol\right)\\ a.Na_2O+H_2O\rightarrow2NaOH\\ 2NaOH+CuSO_4\rightarrow Na_2SO_4+Cu\left(OH\right)_2\\ Cu\left(OH\right)_2\underrightarrow{^{to}}CuO+H_2O\\ b.n_{CuO}=n_{Cu\left(OH\right)_2}=\dfrac{n_{NaOH}}{2}=n_{Na_2O}=0,1\left(mol\right)\\ \Rightarrow m_Y=m_{CuO}=0,1.80=8\left(g\right)\\ CuO+CO\underrightarrow{^{to}}Cu+H_2O\\ n_{CO}=n_{CuO}=0,1\left(mol\right)\\ V_{CO\left(đktc\right)}=0,1.22,4=2,24\left(l\right)\)

Trương Quang Minh
24 tháng 10 2021 lúc 17:57

nNa2O=6,262=0,1(mol)a.Na2O+H2O→2NaOH2NaOH+CuSO4→Na2SO4+Cu(OH)2Cu(OH)2to→CuO+H2Ob.nCuO=nCu(OH)2=nNaOH2=nNa2O=0,1(mol)⇒mY=mCuO=0,1.80=8(g)CuO+COto→Cu+H2OnCO=nCuO=0,1(mol)VCO(đktc)=0,1.22,4=2,24(l)

123....
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Nguyễn Lê Phước Thịnh
22 tháng 8 2021 lúc 21:40

Ta có: \(\sqrt{\dfrac{3\sqrt{5}-1}{2\sqrt{5}+3}}-\sqrt{\dfrac{\sqrt{5}+11}{7-2\sqrt{5}}}\)

\(=\sqrt{\dfrac{\left(3\sqrt{5}-1\right)\left(2\sqrt{5}-3\right)}{11}}-\sqrt{\dfrac{\left(11+\sqrt{5}\right)\left(7+2\sqrt{5}\right)}{29}}\)

\(=\sqrt{\dfrac{11\cdot\left(30-9\sqrt{5}-2\sqrt{5}+3\right)}{121}}-\sqrt{29\cdot\left(\dfrac{77+22\sqrt{5}+7\sqrt{5}+20}{841}\right)}\)

\(=\dfrac{\sqrt{363-121\sqrt{5}}}{11}+\dfrac{\sqrt{2813+841\sqrt{5}}}{29}\)

\(=\dfrac{\sqrt{726-242\sqrt{5}}}{11\sqrt{2}}+\dfrac{\sqrt{5626+1682\sqrt{5}}}{29\sqrt{2}}\)

 

Trà my Hoàng
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Nguyễn Hoàng Minh
16 tháng 10 2021 lúc 15:55

3.

Áp dụng t/c dtsbn:

\(\dfrac{x}{y}=\dfrac{13}{9}\Rightarrow\dfrac{x}{13}=\dfrac{y}{9}=\dfrac{x-y}{13-9}=\dfrac{24}{4}=6\\ \Rightarrow\left\{{}\begin{matrix}x=78\\y=54\end{matrix}\right.\)

jojo
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☞Tᖇì  ᑎGâᗰ ☜
2 tháng 5 2022 lúc 14:55

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Thu Hồng đã xóa
Sunn
2 tháng 5 2022 lúc 14:58

...eating lots of food, she is still very slim

...is it from Hanoi to HCM city?

...interested in English

...dance very well 

...the weather was bad, we went to school

Phan Thị Diệu Linh
2 tháng 5 2022 lúc 15:50

...eating lots of food, she is still very slim

 ...is it from Hanoi to HCM city? ...interested in English ...dance very well  ...the weather was bad, we went to school
jojo
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HACKER VN2009
4 tháng 5 2022 lúc 14:49

did - go

went - didn't enjoy 

take

takes

goes

playing

am wanting

used to play - was

did - ever heard

will - travel

will be taking

will spend

haven't seen

Thu Hồng
5 tháng 5 2022 lúc 10:42

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jojo
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Đinh Minh Đức
7 tháng 5 2022 lúc 9:19

she is interested in reading comic

Tomorrow in this time I wil be lieing on the beach

My car isn't as expensive as his

She has started live in Paris since 2005

A new dam will build near the rive next year

Thu Hồng
7 tháng 5 2022 lúc 15:27

She is interested in reading comic.

Tomorrow in this time I wil be lying on the beach.

My car isn't as expensive as his.

She has started living in Paris since 2005.

A new dam will be built near the rive next year.