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Thanh Nguyễn
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\(a,2Al_2O_3\rightarrow\left(đpnc,criolit\right)4Al+3O_2\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3\rightarrow\left(t^o\right)Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

\(b,2Cu+O_2\rightarrow\left(t^o\right)2CuO\\ CuO+2HCl\rightarrow CuCl_2+H_2O\\ CuCl_2+2KOH\rightarrow Cu\left(OH\right)_2+2KCl\\ Cu\left(OH\right)_2\rightarrow\left(t^o\right)CuO+H_2O\)

Chien Nhu
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Nguyễn Hoàng Minh
3 tháng 12 2021 lúc 20:44

\((1)4Al+3O_2\xrightarrow{t^o} 2Al_2O_3\\ (2)Al_2O_3+6HCl\to 2AlCl_3+3H_2O\\ (3)AlCl_3+3NaOH\to Al(OH)_3\downarrow +3NaCl\\ (4)2Al(OH)_3\xrightarrow{t^o}Al_2O_3+3H_2O\\ (5)2Al_2O_3\xrightarrow{đpnc}4Al+3O_2\)

Nguyễn Văn Long
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Luminos
9 tháng 12 2021 lúc 14:25

Al+H2SO4 -> Al2(SO4)3+ H2 \(\uparrow\)

Al2(SO4)3 +HCl -> AlCl3+ H2SO4

AlCl3 +Ca(OH)2 -> Al(OH)3 +CaCl2 

Al(OH)3 - to> Al2O3 +H20

Nguyễn Hoàng Minh
9 tháng 12 2021 lúc 14:53

\(2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+3BaCl_2\to 3BaSO_4\downarrow+2AlCl_3\\ AlCl_3+3NaOH\to Al(OH)_3\downarrow+3NaCl\\ 2Al(OH)_3\xrightarrow{t^o} Al_2O_3+3H_2O\)

Vương Hương Giang
9 tháng 12 2021 lúc 15:43

Al+H2SO4 -> Al2(SO4)3+ H2 

 

Al2(SO4)3 +HCl -> AlCl3+ H2SO4

 

AlCl3 +Ca(OH)2 -> Al(OH)3 +CaCl2 

 

Al(OH)3 - to> Al2O3 +H20

bin0707
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hưng phúc
16 tháng 11 2021 lúc 18:40

a. 

\(\left(1\right)Fe+2HCl--->FeCl_2+H_2\)

\(\left(2\right)FeCl_2+2NaOH--->2NaCl+Fe\left(OH\right)_2\)

\(\left(3\right)4Fe\left(OH\right)_2+O_2+2H_2O\overset{t^o}{--->}4Fe\left(OH\right)_3\)

\(\left(4\right)2Fe\left(OH\right)_3\overset{t^o}{--->}Fe_2O_3+3H_2O\)

\(\left(5\right)Fe_2O_3+6HCl--->2FeCl_3+3H_2O\)

b.

\(\left(1\right)4Al+3O_2\overset{t^o}{--->}2Al_2O_3\)

\(\left(2\right)Al_2O_3+6HCl--->2AlCl_3+3H_2O\)

\(\left(3\right)AlCl_3+3NaOH--->Al\left(OH\right)_3+3NaCl\)

\(\left(4\right)2Al\left(OH\right)_3\overset{t^o}{--->}Al_2O_3+3H_2O\)

\(\left(5\right)Al_2O_3+3H_2SO_4--->Al_2\left(SO_4\right)_3+3H_2O\)

Minh Anh
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Nguyễn Hoàng Minh
18 tháng 11 2021 lúc 15:47

\(b,\left(1\right)4Al+3O_2\rightarrow^{t^o}2Al_2O_3\\ \left(2\right)Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ \left(3\right)AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ \left(4\right)2Al\left(OH\right)_3\rightarrow^{t^o}Al_2O_3+3H_2O\\ \left(5\right)Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

Nguyễn Hoàng Minh
18 tháng 11 2021 lúc 15:43

\(a,\left(1\right)Fe+2HCl\rightarrow FeCl_2+H_2\\ \left(2\right)FeCl_2+2NaOH\rightarrow Fe\left(OH\right)_2+2NaCl_2\\ \left(3\right)4Fe\left(OH\right)_2+O_2+2H_2O\rightarrow4Fe\left(OH\right)_3\\ \left(4\right)2Fe\left(OH\right)_3\rightarrow^{t^o}Fe_2O_3+3H_2O\\ \left(5\right)Fe_2O_3+6HCl\rightarrow2FeCl_3+3H_2O\)

Thái hoàng
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hnamyuh
25 tháng 12 2022 lúc 21:28

$(1) 2Al_2O_3 \xrightarrow{đpnc} 4Al + 3O_2$
$2Al + 6HCl \to 2AlCl_3 + 3H_2$
$AlCl_3 + 3KOH \to Al(OH)_3 + 3KCl$
$(2) Fe_2O_3 + 3CO \xrightarrow{t^o} 2Fe + 3CO_2$
$2Fe  + 3Cl_2 \xrightarrow{t^o} 2FeCl_3$
$FeCl_3 + 3KOH \to Fe(OH)_3 + 3KCl$
$(3) 2Fe  + 3Cl_2 \xrightarrow{t^o} 2FeCl_3$
$FeCl_3 + 3KOH \to Fe(OH)_3 + 3KCl$
$2Fe(OH)_3 \xrightarrow{t^o} Fe_2O_3 + 3H_2O$
$Fe_2O_3 + 3CO \xrightarrow{t^o} 2Fe + 3CO_2$
$Fe + 6H_2SO_4 \to Fe_2(SO_4)_3 + 3SO_2 + 6H_2O$

Huy Huy Anh
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Nguyễn Sỹ Tấn
29 tháng 12 2020 lúc 21:42

4Al+3O2----to--->2Al2O3

Al2O3 +3H2SO4----->Al2(SO4)3+3H2O

Al2(SO4)3+3BaCl2------>2AlCl3+3BaSO4

2AlCl3+3Ca(OH)2---->2Al(OH)3+3CaCl2

Al(OH)3+3HNO3---->Al(NO3)3+3H2O

2Al(NO3)3+3Mg----->3Mg(NO3)2+2Al

2Al+3H2SO4------->Al2(SO4)3+3H2

Al2(SO4)3+3Ca(OH)2------>2Al(OH)3+3CaSO4

2Al(OH)3-----to----->Al2O3+3H2O

2Al2O3----\(\dfrac{t^o}{criolit}\)---->4Al+3O2

2Al+2H2O+2NaOH------>2NaAlO2+3H2

Kresol♪
29 tháng 12 2020 lúc 21:50

4Al+3O2\(\underrightarrow{t^o}\) 2Al2O3

Al2O3+H2SO4 —> Al2(SO4)3+3H2O

Al2(SO4)3+3BaCl2–>3BaSO4\(\downarrow\)+2AlCl3

AlCl3+3NaOH—>Al(OH)3\(\downarrow\)+3NaCl

Al(OH)3+HNO3 —>Al(NO3)3+NO2\(\uparrow\)+H2O

2Al(NO3)3+3Mg—>3Mg(NO3)2+2Al\(\downarrow\)

2Al+3H2SO4–>Al2(SO4)3+3H2\(\uparrow\)

Al2(SO4)3+6NaOH—>2Al(OH)3+3Na2SO4

2Al(OH)3\(\underrightarrow{t^o}\)Al2O3+3H2O

2Al2O3\(\xrightarrow[criolit]{đien.phan.nong.chay}\)

4Al+3O2

2Al+2NaOH+2H2O—>2NaAlO2+3H2

Nguyễn Mạnh Tuấn
29 tháng 12 2020 lúc 23:04

\(\begin{array}{l} 4Al+3O_2\xrightarrow{t^o} 2Al_2O_3\\ Al_2O_3+3H_2SO_4\to Al_2(SO_4)_3+3H_2O\\ Al_2(SO_4)_3+3BaCl_2\to 3BaSO_4\downarrow+2AlCl_3\\ AlCl_3+3NaOH\to Al(OH)_3\downarrow+3NaCl\\ Al(OH)_3+3HNO_3\to Al(NO_3)_3+3H_2O\\ 2Al(NO_3)_3+3Mg\to 3Mg(NO_3)_2+2Al\\ 2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\uparrow\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ 2Al(OH)_3\xrightarrow{t^o} Al_2O_3+3H_2O\\ 2Al_2O_3\xrightarrow{\text{đpnc, Criolit}} 4Al+3O_2\uparrow\\ 2Al+2NaOH+2H_2O\to 2NaAlO_2+3H_2\uparrow\end{array}\)

Phương Phơi phới
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Thảo Uyên Lưu
14 tháng 11 2016 lúc 20:24

AlCl3 +3 NaOH-->Al(OH)3 + 3NaCl

Al(OH)3 + NaOH----->NaAlO2+2H2O

Al2O3+ 2NaOH------>2NaAlO2+H2O

Vy Kiyllie
15 tháng 11 2016 lúc 13:52

Alcl3----->al(OH)

AlCl3 + 3NaOH -> Al(OH)3 + 3NaCl

Al(OH)3 ---->NaAlo2

Al(OH)3 + NaOH -> NaAlO2 + 2H2O

Al2o3 ------>NaAlo2

Al2O3 + 2NaOH -> 2NaAlO2 + H2O

Nhưu ý Nguyễn
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Phước Lộc
5 tháng 1 2023 lúc 15:22

(1) \(4Al+3O_2\xrightarrow[]{t^\circ}2Al_2O_3\)

(2) \(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)

(3) \(AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\downarrow\)

(4) \(Al\left(NO_3\right)_3+3LiOH\rightarrow Al\left(OH\right)_3\downarrow+3LiNO_3\)

(5) \(2Al\left(OH\right)_3\xrightarrow[]{t^\circ}Al_2O_3+3H_2O\uparrow\)

(6) \(Al_2O_3+2NaOH\rightarrow2NaAlO_2+H_2O\)