AlCl3 +3 NaOH-->Al(OH)3 + 3NaCl
Al(OH)3 + NaOH----->NaAlO2+2H2O
Al2O3+ 2NaOH------>2NaAlO2+H2O
Alcl3----->al(OH)
AlCl3 + 3NaOH -> Al(OH)3 + 3NaCl
Al(OH)3 ---->NaAlo2
Al(OH)3 + NaOH -> NaAlO2 + 2H2O
Al2o3 ------>NaAlo2
Al2O3 + 2NaOH -> 2NaAlO2 + H2O
AlCl3 +3 NaOH-->Al(OH)3 + 3NaCl
Al(OH)3 + NaOH----->NaAlO2+2H2O
Al2O3+ 2NaOH------>2NaAlO2+H2O
Alcl3----->al(OH)
AlCl3 + 3NaOH -> Al(OH)3 + 3NaCl
Al(OH)3 ---->NaAlo2
Al(OH)3 + NaOH -> NaAlO2 + 2H2O
Al2o3 ------>NaAlo2
Al2O3 + 2NaOH -> 2NaAlO2 + H2O
al → al2o3 → al2(so4)3 → alcl3 → al(oh)3 → al(no3)3 → al → al2(so4)3 → al(oh)3 → al2o3 → al →naalo2
Viết PTHH
a, Al-->Al2O3-->AlCl3-->Al(OH)3-->Al203-->Al
"(AlCl3-->Al(NO3)3
b, Fe-->Fe3O4-->FeCl3-->Fe(OH)3-->Fe2O3-->Fe
c, Fe(OH)3-->Fe2(SO4)3-->FeCl3-->Fe(NO3)3
AL--->AL2O3--->ALCL3--->AL(OH)3--->AL2O3--->AL--->ALCL3
Al---->Al2O3---->AlCl3---->Al(OH)3 ---->NaAlO2
GIÚP MÌNH
Al --> Al2O3 --> AlCl3 --> Al2(SO4)3 --> Al(OH)3 --> Al2O3 --> Al
hoàn thành sơ đồ sau :
AL ---> Al2O3 ---> AlCl3 ---> Al(OH)3 ---> Al2(SO4)3
Them 0,6 mol NaOH vao dung dich chua x mol AlCl3 thu duoc 0,2 mol Al(OH)3.Them tiep 0,9 mol NaOH thay so mol cua Al(OH)3 la 0,5. Them tiep 1,2 mol NaOH nua thay so mol Al(OH)3 van la 0,5 mol. Tinh x?
hoàn thành sơ đồ phản ơngs sau giúp em với
Al -> Al2 -> AlCl3 -> Al (OH)3 -> Al2 (SO4)3