(4,5-2x).11/7=11/4
(4,5-2x).11/7=11/4
4,5-2x=11/4:11/7
4,5 - 2x= 7/4
2x=9/2 - 7/4
2x= 18/4-7/4
2x=11/4
x=11/4:2
x=11/8
(4,5-2x).1 4/7+11/14
\(\left(4,5-2x\right).1\dfrac{4}{7}+\dfrac{11}{14}\)
\(=\dfrac{99}{14}-\dfrac{22}{7}x+\dfrac{11}{14}\)
\(=\left(\dfrac{99}{14}+\dfrac{11}{14}\right)-\dfrac{22}{7}x\)
\(=\dfrac{55}{7}-\dfrac{22}{7}x\)
\(=\dfrac{33}{7}+\dfrac{22}{7}.\left(1-x\right)\)
(4,5-2x) * (-1 4/7) = 11/14
(4,5-2x) * -2=11/14
9/2-2x=11/14:-2
9/2-2x=-11/28
2x=9/2 - (-11/28)
2x=137/28
x=137/28:2
x=137/56
(4,5-2x) * -2=11/14
9/2-2x=11/14:-2
9/2-2x=-11/28
2x=9/2 - (-11/28)
2x=137/28
x=137/28:2
x=137/56
(4,5-2x) * (-1và 4/7) = 11/14
(4,5-2x) * -2=11/14
9/2-2x=11/14:-2
9/2-2x=-11/28
2x=9/2 - (-11/28)
2x=137/28
x=137/28:2
x=137/56
NHA BAN
(4,5-2x) * -2=11/14
9/2-2x=11/14:-2
9/2-2x=-11/28
2x=9/2 - (-11/28)
2x=137/28
x=137/28:2
x=137/56
(4,5-2x) * -2=11/14
9/2-2x=11/14:-2
9/2-2x=-11/28
2x=9/2 - (-11/28)
2x=137/28
x=137/28:2
x=137/56
(4,5 - 2x). 1 4/7 =11/14
Theo bài ra, ta có:
\(\left(4,5-2x\right).1\dfrac{4}{7}=\dfrac{11}{14}\\ \left(4,5-2x\right).\dfrac{11}{7}=\dfrac{11}{14}\\ 4,5-2x=\dfrac{11}{14}:\dfrac{11}{7}\\ 4,5-2x=\dfrac{1}{2}\\ 2x=4,5-\dfrac{1}{2}\\ \Rightarrow2x=4\\ \Rightarrow x=2\)
Vậy x = 2
\(\left(4,5-2x\right).1\dfrac{4}{7}=\dfrac{11}{14}\)
\(\Leftrightarrow\left(4,5-2x\right).\dfrac{11}{7}=\dfrac{11}{14}\)
\(\Leftrightarrow4,5-2x=\dfrac{11}{14}:\dfrac{11}{7}\)
\(\Leftrightarrow4,5-2x=\dfrac{11}{14}.\dfrac{7}{11}\)
\(\Leftrightarrow4,5-2x=\dfrac{1}{2}\)
\(\Leftrightarrow-2x=\dfrac{1}{2}-4,5\)
\(\Leftrightarrow-2x=-4\)
\(\Leftrightarrow x=2\)
Vậy phương trình có ngiệm x = 2 .
\(\left(4,5-2x\right).1\dfrac{4}{7}=\dfrac{11}{14}\)
=>4,5-2x=11/14:11/7=1/2
=>2x=4
hay x=2
\(\left(4,5-2x\right)\cdot1\dfrac{4}{7}=\dfrac{11}{14}\)
\(\left(\dfrac{9}{2}-2x\right)\cdot\dfrac{11}{7}=\dfrac{11}{14}\)
\(\dfrac{9}{2}-2x=\dfrac{11}{14}:\dfrac{11}{7}\)
\(\dfrac{9}{2}-2x=\dfrac{1}{2}\)
\(2x=\dfrac{9}{2}-\dfrac{1}{2}\)
\(2x=\dfrac{8}{2}\)
\(x=\dfrac{8}{2}:2\)
`x=2`
\(\left(4,5-2x\right).\left(-1\dfrac{4}{7}\right)=\dfrac{11}{14}\)
(4,5 - 2\(x\)) (-1\(\dfrac{4}{7}\)) = \(\dfrac{11}{14}\)
(4,5 - 2\(x\)) (-\(\dfrac{11}{7}\)) = \(\dfrac{11}{14}\)
4,5 - 2\(x\) = \(\dfrac{11}{14}\) : ( - \(\dfrac{11}{7}\))
4,5 - 2\(x\) = \(\dfrac{11}{14}\) \(\times\) (- \(\dfrac{7}{11}\))
4,5 - 2\(x\) = - \(\dfrac{1}{2}\)
4,5 - 2\(x\) = -0,5
2\(x\) = 4,5 + 0,5
2\(x\) = 5
\(x\) = 5: 2
\(x\) = 2,5
Tìm x:
\(\left(4,5-2x\right).1\dfrac{4}{7}=\dfrac{11}{14}\)
\(\Leftrightarrow4,5-2x=\dfrac{11}{14}:\dfrac{11}{7}\)
\(\Leftrightarrow4,5-2x=\dfrac{1}{2}\)
\(\Leftrightarrow2x=4,5-\dfrac{1}{2}\)
\(\Leftrightarrow x=4:2\)
\(\Leftrightarrow x=2\)
4,5 -2x = 11/14 : 1 4/7
4,5 -2x = 11/14 : 11/7
4,5 -2x = 1/2
2x = 4,5 - 1/2
2x = 4
x = 4 : 2
x = 2
(đăng cho các CTV thử việc ^-^)
Tìm x:
a, -5/6 - x = 7/12 + -1/3
b, (4,5 - 2x).(-1 4/7) = 11/14
c, (2/11 + 1/3).x = (1/7 - 1/8).56
`a)-5/6-x=7/12+[-1]/3`
`-5/6-x=1/4`
`x=-5/6-1/4`
`x=-13/12`
`b)(4,5-2x).(-1 4/7)=11/14`
`(4,5-2x).(-11/7)=11/14`
`4,5-2x=11/14:(-11/7)=-0,5`
`2x=4,5-(-0,5)=5`
`x=5:2=2,5`
`c)(2/11+1/3)x=(1/7-1/8).56`
`17/33 x=1/56 .56=1`
`x=33/17`