Theo bài ra, ta có:
\(\left(4,5-2x\right).1\dfrac{4}{7}=\dfrac{11}{14}\\ \left(4,5-2x\right).\dfrac{11}{7}=\dfrac{11}{14}\\ 4,5-2x=\dfrac{11}{14}:\dfrac{11}{7}\\ 4,5-2x=\dfrac{1}{2}\\ 2x=4,5-\dfrac{1}{2}\\ \Rightarrow2x=4\\ \Rightarrow x=2\)
Vậy x = 2
\(\left(4,5-2x\right).1\dfrac{4}{7}=\dfrac{11}{14}\)
\(\Leftrightarrow\left(4,5-2x\right).\dfrac{11}{7}=\dfrac{11}{14}\)
\(\Leftrightarrow4,5-2x=\dfrac{11}{14}:\dfrac{11}{7}\)
\(\Leftrightarrow4,5-2x=\dfrac{11}{14}.\dfrac{7}{11}\)
\(\Leftrightarrow4,5-2x=\dfrac{1}{2}\)
\(\Leftrightarrow-2x=\dfrac{1}{2}-4,5\)
\(\Leftrightarrow-2x=-4\)
\(\Leftrightarrow x=2\)
Vậy phương trình có ngiệm x = 2 .