a) 49 - 9 . [ 3⁴ : 3¹ - ( 12 - 4 ) : 2²  ]

= 49 - 9 . [ 3³ - 8 : 2² ]

=  49 - 9 . [ 3³ -2³ : 2² ]

=  49 - 9 . [ 3³ - 2 ]

= 49 - 9 . [ 27 - 2 ]

= 49 - 9 . 25

= 49 - 225 = -176

b) 4.5² + 16 : 2²

= 4. 25 + 2⁴ : 2²

= 100 + 2² = 100+ 4 =104

--tho--là tớ💋

c) 5³ : 5 - 2017⁰

= 5² - 1 = 25 - 1= 24 

d) 2² . 3 - ( 10⁰ + 8 ) : 3²

= 4. 3 - ( 1 + 8 ) : 3²

= 4. 3 - 9 : 3²

= 12 - 3² : 3²

= 12 - 1 = 11.

--tho--là tớ💋

a) 352 + 48 : 2^{3 .} 3 -101

= 352 + 48 : 8 . 3 -101

= 352 + 6.3 -101

= 352 +18 - 101

= 370 -101

= 269

b) 3^4.52 + 48.3⁴ -11²

= 81 .52 + 48 .81 - 121

= 81.(52 + 48) - 121

= 81.100 - 121

= 8100 - 121

= 7979

c) 12 + (-13) + (-54) + 27

= [12 + (-13)] + [(-2).27 + 27.1]

= (-1) + [27.(-2 + 1)]

= (-1) + 27.(-1)

= (-1).(27 + 1)

= (-1).28

= (-28)

a) $34-29+(-14)+129-(-114)$

$=34-29-14+129+114$

$=34+(129-29)+(114-14)$

$=34+100+100$

$=234$

b) $27\cdot(-35)+(-27)\cdot64-27$

$=(-27)\cdot35+(-27)\cdot64+(-27)\cdot1$

$=(-27)\cdot(35+64+1)$

$=(-27)\cdot(99+1)$

$=(-27)\cdot100$

$=-2700$

c) $160-(4\cdot5^2-3\cdot2^3)\cdot2-(-12)$

$=160-(4\cdot25-3\cdot8)\cdot2+12$

$=160-(100-24)\cdot2+12$

$=160-76\cdot2+12$

$=160-152+12$

$=160-(152-12)$

$=160-140$

$=20$

a, 34 - 29 + (-14) + 129 - (-114)

= 34 + (129 - 29) + (114  - 14)

= 34 + 100 + 100

= 234

b, 27.(-35) + (-27).64 - 27

= (-27).(35 + 64 + 1)

= - 27 . 100

= - 2700

c, 160 - (4.5² - 3.2³).2 - (-12)

= 160 - (4.25 - 3.8).2 + 12

=  160 - (100 - 24).2 + 12

=  160 - 76.2 + 12

= 160 - 152 + 12

= 8 + 12

= 20 

a, 34-29+(-14)+129-(-114)
= 34-29-14+129+114
= (34-14)+(-29+129)+114
= 20 + 100 + 114
= 234

a: \(\Leftrightarrow\left(2x-5\right)^3=225-4\cdot100=125\)

=>2x-5=5

=>2x=10

hay x=5

b: \(\Leftrightarrow\left(x-2\right)\left(x-5\right)=0\)

hay \(x\in\left\{2;5\right\}\)

c: =>x-5-2x-7=-8

=>-x-12=-8

=>x+12=8

hay x=-4

\(\left(2x-5\right)^3=15^2-4.5^2\)

\(\Leftrightarrow\left(2x-5\right)^3=125\)

\(\Leftrightarrow2x-5=5\)

\(\Leftrightarrow x=5\)

________________________________________________

\(\left(x-2\right)\left(15-3x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\15-3x=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)

____________________________________________

\(\left(x-5\right)-\left(2x+7\right)=-8\)

\(\Leftrightarrow x-5-2x-7=-8\)

\(\Leftrightarrow-x=4\)

\(\Leftrightarrow x=-4\)

a, Ta có : \(64^x+4^{3x+2}=17.64\)

=> \(64^x+64^x.16=17.64\)

=> \(17.64^x=17.64\)

=> \(64^x=64\)

=> \(x=1\)

Vậy phương trình có tập nghiệm là \(S=\left\{1\right\}\)

b, Ta có : \(123-2\left(\left|2x-3\right|\right)=41\)

=> \(\left|2x-3\right|=41\)

TH₁ : \(2x-3\ge0\left(x\ge\frac{3}{2}\right)\)

=> \(\left|2x-3\right|=2x-3=41\)

=> \(x=22\) ( TM )

TH₂ : \(2x-3< 0\left(x< \frac{3}{2}\right)\)

=> \(\left|2x-3\right|=3-2x=41\)

=> \(x=-19\left(TM\right)\)

Vậy phương trình trên có tập nghiệm là \(S=\left\{22,-19\right\}\)

a) \(64^x+4^{3x+2}=17\cdot64\)

\(\Leftrightarrow4^{3x}+4^{3x}.4^2=17.64\)

\(\Leftrightarrow4^{3x}\left(1+4^2\right)=17.64\)

\(\Leftrightarrow4^{3x}=64=4^3\)

\(\Leftrightarrow x=1\)

b) \(123-2\left|2x-3\right|=41\)

\(\Leftrightarrow\left|2x-3\right|=41\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-3=41\\2x-3=-41\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=22\\x=-19\end{matrix}\right.\)

a) \(\frac{18.\left(27-23\right)}{4.\left(34-52\right)}=\frac{18.4}{4.\left(-18\right)}=-1\)

b) \(\frac{15^2.16^3.\left(16-15\right)}{12^2.20^2.\left(20-12\right)}=\frac{15^2.16^3}{12^2.20^2.8}=\frac{3^2.5^2.4^3.4^3}{4^2.3^2.4^2.5^2.8}=\frac{1}{8}\)

=A*97*(8-3-4-1)=0

bnj nên tách ra zồi làm sẽ nhanh hơn giống như rút gọn

\(=80-100+24=4\)

=55

\(=80-4.25+3.8=4\)