75%-1\(\dfrac{1}{2}\)+0,5;\(\dfrac{5}{12}\)-(1\(\dfrac{1}{2}\))2
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75%:2\(\dfrac{1}{5}\)+(0,5)2.(-7)+2,5(7\(\dfrac{2}{3}\)+5\(\dfrac{2}{3}\))
\(75\%:2\dfrac{1}{5}+\left(0,5\right)^2.\left(-7\right)+2,5\left(7\dfrac{2}{3}+5\dfrac{2}{3}\right)\)
\(=\dfrac{3}{4}:\dfrac{11}{5}+\dfrac{1}{4}.\left(-7\right)+2,5\left(12+\dfrac{4}{3}\right)\)
\(=\dfrac{15}{44}-\dfrac{7}{4}+\dfrac{5}{2}.\dfrac{40}{3}\)
\(=-\dfrac{31}{22}+\dfrac{100}{3}\)
\(=\dfrac{2107}{66}\)
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10 tháng 5 2022 lúc 22:27
trả lời z là đủ r đến lượt hỏi:
75% - \(1\dfrac{1}{2}\) + 0,5 . \(\dfrac{12}{5}\)
\(\dfrac{75}{100}-\dfrac{3}{2}+\dfrac{1}{2}\times\dfrac{12}{5}=\dfrac{3}{4}-\dfrac{3}{2}+\dfrac{6}{5}=\dfrac{15}{20}-\dfrac{30}{20}+\dfrac{24}{20}=\dfrac{9}{20}\)
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\(75\%-1\dfrac{1}{2}+0,5\cdot\dfrac{12}{5}=\dfrac{3}{4}-\dfrac{3}{2}+\dfrac{1}{2}\cdot\dfrac{12}{5}=\dfrac{3}{4}-\dfrac{3}{2}+\dfrac{12}{10}=\dfrac{15}{20}-\dfrac{30}{20}+\dfrac{24}{20}=\dfrac{15-30+24}{20}=\dfrac{9}{20}\)
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Xem thêm câu trả lời
12 tháng 3 2022 lúc 14:17
Tính:
\(a,\left(\dfrac{5}{12}-\dfrac{3}{4}\right).\dfrac{-6}{5}+\dfrac{-7}{6}\)
\(b,\left(5\dfrac{1}{2}-5\right)^2+\dfrac{-1}{6}:\dfrac{5}{3}\)
\(c,75\%-1\dfrac{1}{2}+0,5:\dfrac{5}{12}\)
Tìm x, biết:
a) x+\(\dfrac{1}{6}\)=\(\dfrac{-3}{8}\) b) \(2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}\)
c) \(\dfrac{1}{2}x\)+\(\dfrac{1}{8}x=\dfrac{3}{4}\) d) 75%-\(1\dfrac{1}{2}+0,5:\dfrac{5}{12}-\left(\dfrac{-1}{2}\right)^2\)
\(a.x+\dfrac{1}{6}=-\dfrac{3}{8}\)
\(\Leftrightarrow x=-\dfrac{13}{24}\)
\(b.2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}\)
\(\Leftrightarrow2-\dfrac{3}{4}+x=\dfrac{7}{12}\)
\(\Leftrightarrow x=-\dfrac{2}{3}\)
\(c.\dfrac{1}{2}x+\dfrac{1}{8}x=\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{5}{8}x=\dfrac{3}{4}\)
\(\Leftrightarrow x=\dfrac{6}{5}\)
\(d.75\%-1\dfrac{1}{2}+0,5:\dfrac{5}{12}-\left(\dfrac{-1}{2}\right)^2\)
\(=\dfrac{75}{100}-\dfrac{3}{2}+\dfrac{1}{2}:\dfrac{5}{12}-\dfrac{1}{4}\)
\(=-\dfrac{3}{4}+\dfrac{6}{5}-\dfrac{1}{4}\)
\(=\dfrac{1}{5}\)
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a) \(x+\dfrac{1}{6}=\dfrac{-3}{8}\)
\(x=\dfrac{-3}{8}-\dfrac{1}{6}\)
\(x=\dfrac{-13}{24}\)
vậy x =....
b) \(2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}\)
\(\dfrac{3}{4}-x=2-\dfrac{7}{12}\)
\(\dfrac{3}{4}-x=\dfrac{17}{12}\)
\(x=\dfrac{3}{4}-\dfrac{17}{12}\)
\(x=\dfrac{-2}{3}\)
vậy x =....
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Thực hiện phép tính (tính nhanh nếu có thể)
c) \(5\dfrac{2}{5}\)✖\(4\dfrac{2}{7}\)+\(5\dfrac{5}{7}\)✖\(5\dfrac{2}{5}\)
d) 75%-\(1\dfrac{1}{2}\)+0,5:\(\dfrac{5}{12}\)-\(\left(\dfrac{-1}{2}\right)^2\)
\(75\%-1\dfrac{1}{2}+0,5:\dfrac{5}{12}-\left(\dfrac{-1}{2}\right)^2\)
LÀM HỘ MIK BÀI NÀY NHA
=\(\dfrac{75}{100}\)-\(\dfrac{3}{2}\)+\(\dfrac{5}{10}\):\(\dfrac{5}{12}\)-\(\dfrac{1}{4}\)
=\(\dfrac{3}{4}\)-\(\dfrac{3}{2}\)+\(\dfrac{6}{5}\)-\(\dfrac{1}{4}\)
=\(\dfrac{-3}{4}\)+\(\dfrac{6}{5}\)-\(\dfrac{1}{4}\)
=\(\dfrac{9}{20}\)-\(\dfrac{1}{4}\)
=\(\dfrac{1}{5}\)
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tính:
a) 25%-dfrac{5}{4}+1dfrac{5}{6}
b) 75%:2dfrac{1}{5}-left(0,5right)^2.left(-7right)+2,5left(7dfrac{2}{3}-5dfrac{2}{3}right)
c) 45:2dfrac{4}{7}+50%-1,25
d) 350%:dfrac{105}{24}+4dfrac{5}{6}:2-left(0,5right)^2.30%
e) 4dfrac{2}{5}.0,5-1dfrac{3}{7}.14%+left(-0,8right)
Đọc tiếp
tính:
a) \(25\%-\dfrac{5}{4}+1\dfrac{5}{6}\)
b) \(75\%:2\dfrac{1}{5}-\left(0,5\right)^2.\left(-7\right)+2,5\left(7\dfrac{2}{3}-5\dfrac{2}{3}\right)\)
c) \(45:2\dfrac{4}{7}+50\%-1,25\)
d) \(350\%:\dfrac{105}{24}+4\dfrac{5}{6}:2-\left(0,5\right)^2.30\%\)
e) \(4\dfrac{2}{5}.0,5-1\dfrac{3}{7}.14\%+\left(-0,8\right)\)
\(\left(\sqrt{18}+\sqrt{0,5}-3\sqrt{\dfrac{1}{3}}\right)-\left(\sqrt{\dfrac{1}{8}}-\sqrt{75}\right)\)
\(\left(\sqrt{18}+\sqrt{0,5}-3\sqrt{\frac{1}{3}}\right)-\left(\sqrt{\frac{1}{8}}-\sqrt{75}\right)\)
\(=\left(\sqrt{2\cdot3^2}+\sqrt{\frac{1}{2}}-3\sqrt{\frac{3}{3^2}}\right)-\left(\sqrt{\frac{2}{4^2}}-\sqrt{3\cdot5^2}\right)\)
\(=\left(3\sqrt{2}+\sqrt{\frac{2}{2^2}}-3\cdot\frac{1}{3}\sqrt{3}\right)-\left(\frac{\sqrt{2}}{4}-5\sqrt{3}\right)\)
\(=3\sqrt{2}+\frac{\sqrt{2}}{2}-\sqrt{3}-\frac{\sqrt{2}}{4}+5\sqrt{3}\)
\(=\frac{12\sqrt{2}}{4}+\frac{2\sqrt{2}}{4}-\frac{\sqrt{2}}{4}-\sqrt{3}+5\sqrt{3}\)
\(=\frac{13\sqrt{2}}{4}+4\sqrt{3}=\frac{13\sqrt{2}+16\sqrt{3}}{4}\)
Thực hiệp phép tính:
(4-\(\dfrac{5}{12}\)):2+\(\dfrac{5}{24}\).0,2
b)75%-1\(\dfrac{1}{2}+0,5:\dfrac{5}{12}\)
a) =43/12.1/2+1/24 b) =3/4-3/2+1/2.12/5
=43/24+1/24 =-3/4+6/5
=11/6 =9/20
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\(\left(\sqrt{4-2\sqrt{3}}+\sqrt{0,5}-3\sqrt{\dfrac{1}{3}}\right)-\left(\sqrt{\dfrac{1}{8}}-\sqrt{75}\right)\)
Tính giá trị biểu thức
Lời giải:
Đặt biểu thức đã cho là $A$
\(\sqrt{4-2\sqrt{3}}+\sqrt{0,5}-3\sqrt{\frac{1}{3}}=\sqrt{(\sqrt{3}-1)^2}+\sqrt{0,5}-\sqrt{3}=\sqrt{3}-1+\sqrt{0,5}-\sqrt{3}=\sqrt{0,5}-1\)
\(\sqrt{\frac{1}{8}}-\sqrt{75}=0,5\sqrt{0,5}-5\sqrt{3}\)
Do đó:
\(A=\sqrt{0,5}-1-(0,5\sqrt{0,5}-5\sqrt{3})=5\sqrt{3}+0,5\sqrt{0,5}-1\)
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