d: =>-x-5/6=7/12-4/12=3/12=1/4

=>-x=1/4+5/6=13/12

hay x=-13/12

e: =>x+3=-5

hay x=-8

f: =>4,5-2x=-1/2

=>2x=5

hay x=5/2

(4,5 - 2\(x\)) (-1\(\dfrac{4}{7}\)) = \(\dfrac{11}{14}\)

(4,5 - 2\(x\)) (-\(\dfrac{11}{7}\)) = \(\dfrac{11}{14}\)

4,5 - 2\(x\) = \(\dfrac{11}{14}\) : ( - \(\dfrac{11}{7}\))

4,5 - 2\(x\) = \(\dfrac{11}{14}\) \(\times\) (- \(\dfrac{7}{11}\))

4,5 - 2\(x\) = - \(\dfrac{1}{2}\) 

4,5 - 2\(x\) = -0,5

2\(x\) = 4,5 + 0,5

2\(x\) = 5

\(x\) = 5: 2

\(x\) = 2,5 

=>4,5-2x=11/14:11/7=1/2

=>2x=4

hay x=2

\(\left(4,5-2x\right)\cdot1\dfrac{4}{7}=\dfrac{11}{14}\)

\(\left(\dfrac{9}{2}-2x\right)\cdot\dfrac{11}{7}=\dfrac{11}{14}\)

\(\dfrac{9}{2}-2x=\dfrac{11}{14}:\dfrac{11}{7}\)

\(\dfrac{9}{2}-2x=\dfrac{1}{2}\)

\(2x=\dfrac{9}{2}-\dfrac{1}{2}\)

\(2x=\dfrac{8}{2}\)

\(x=\dfrac{8}{2}:2\)

`x=2`

`a)(4,5-2x)*1 4/7=11/14`

`=>(4,5-2x)*11/7=11/14`

`=>4,5-2x=1/2`

`=>2x=4,5-0,5=4`

`=>x=2`

Vậy `x=2`

`b)(2,8x-32):2/3=-90`

`=>2,8x-32=-90*2/3=-60`

`=>2,8x=-28`

`=>x=-10`

Vậy `x=-10`

a, \(\left(2,8x-32\right):\dfrac{2}{3}=-90\)

\(\Rightarrow2,8x-32=-60\)

\(\Rightarrow2,8x=-28\)

\(\Rightarrow x=-10\)

Vậy x = -10

b, \(\left(4,5-2x\right):1\dfrac{4}{7}=\dfrac{11}{14}\)

\(\Rightarrow\left(4,5-2x\right):\dfrac{11}{7}=\dfrac{11}{14}\)

\(\Rightarrow4,5-2x=\dfrac{121}{98}\)

\(\Rightarrow2x=\dfrac{160}{49}\)

\(\Rightarrow x=\dfrac{80}{49}\)

Vậy \(x=\dfrac{80}{49}\)

\(a,\left(2,8x-32\right):\dfrac{2}{3}=-90\)

\(2,8x-32=-90.\dfrac{2}{3}\)

\(2,8x-32=-60\)

\(2,8x=-60+32\)

\(2,8x=-28\)

\(x=-28:2,8\)

\(x=-10\)

Vậy \(x=-10\)

\(b,\left(4,5-2x\right):1\dfrac{4}{7}=\dfrac{11}{14}\)

\(\left(4,5-2x\right):\dfrac{11}{7}=\dfrac{11}{14}\)

\(4,5-2x=\dfrac{11}{14}.\dfrac{11}{7}\)

\(4,5-2x=\dfrac{121}{98}\)

\(2x=4,5-\dfrac{121}{98}\)

\(2x=\dfrac{160}{49}\)

\(x=\dfrac{160}{49}:2\)

\(x=\dfrac{80}{49}\)

Vậy \(x=\dfrac{80}{49}\)

\(a,\left(2,8x-32\right):\dfrac{2}{3}=-90\)

\(2,8x-32\) \(=-90.\dfrac{2}{3}\)

\(2,8x-32\)

`a)4/5+5 1/2 xx (4,5-2)+7/10`

`=4/5+11/2*2,5+7/10`

`=0,8+2,2+0,7`

`=3+0,7=3,7`

`b)125%xx 17/4:(1 5/16-0,5)+2008`

`=1,25xx4,25:13/16+2008`

`=85/13+2008`

`=2014 7/13`

`c)5/11+(16/11+1)`

`=5/11+1+5/11+1`

`=2+10/11=32/11`

`d)3/17+11/4+5/8+14/17+3/8`

`=3/17+14/17+5/8+3/8+11/4`

`=1+1+11/4`

`=19/4`

a) 

\(\dfrac{4}{5}+5\dfrac{1}{2}x\left(4,5-2\right)=\dfrac{7}{10}\)

<=> \(\dfrac{11}{2}x\times2,5=\dfrac{7}{10}-\dfrac{4}{5}=\dfrac{-1}{10}\)

<=> \(\dfrac{55}{4}x=\dfrac{-1}{10}< =>x=\dfrac{-2}{275}\)

b) \(125\%\times\dfrac{17}{4}:\left(1\dfrac{5}{16}-0,5\right)+2008\)

= \(\dfrac{85}{16}:\left(\dfrac{21}{16}-\dfrac{1}{2}\right)+2008=\dfrac{85}{16}:\dfrac{13}{16}+2008=\dfrac{26189}{13}\)

c) \(\dfrac{5}{11}+\left(\dfrac{16}{11}+1\right)\)

= \(\dfrac{21}{11}+1=\dfrac{32}{11}\)

d) \(\left(\dfrac{3}{17}+\dfrac{14}{17}\right)+\left(\dfrac{5}{8}+\dfrac{3}{8}\right)+\dfrac{11}{4}\)

= 1 + 1 + \(\dfrac{11}{4}\) = \(\dfrac{19}{4}\)

Tìm x biết:

\(\left(4,5-2x\right).1\dfrac{4}{7}=\dfrac{11}{4}\)

\(\Leftrightarrow\left(4,5-2x\right)=\dfrac{11}{4}:1\dfrac{4}{7}\)

\(\Leftrightarrow4,5-2x=\dfrac{7}{4}\)

\(\Leftrightarrow2x=4,5-\dfrac{7}{4}\)

\(\Leftrightarrow2x=\dfrac{11}{4}\)

Vậy \(x=\dfrac{11}{8}\)

Tìm số nguyên x biết:

Theo đề bài, ta có:

\(4\dfrac{1}{3}\left(\dfrac{1}{6}-\dfrac{1}{2}\right)\le x\le\dfrac{2}{3}\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\)

\(\Leftrightarrow-\dfrac{13}{9}\le x\le-\dfrac{11}{18}\) hay \(-\dfrac{26}{18}\le x\le-\dfrac{11}{18}\)

\(\Leftrightarrow-1,\left(4\right)\le x\le-0,6\left(1\right)\)

Mà \(x\in Z\) nên x=-1

Vậy x = -1

1 ) \(\left(4,5-2x\right).1\dfrac{4}{7}=\dfrac{11}{4}\)

\(\Leftrightarrow\left(4,5-2x\right).\dfrac{11}{7}=\dfrac{11}{4}\)

\(\Leftrightarrow4,5-2x=\dfrac{11}{4}:\dfrac{11}{7}=\dfrac{11}{4}.\dfrac{7}{11}=\dfrac{7}{4}\)

\(\Leftrightarrow2x=2,75\)

\(\Leftrightarrow x=1,375\)

2 ) Đáp án x = 0 nhé !!

Cậu chỉ cần lấy số nguyên giữa 2 số thập phân .

a, \(\dfrac{1}{3}+\dfrac{2}{3}:x=-7\)                          b, \(\left(\dfrac{9}{2}-2x\right).\dfrac{11}{7}=\dfrac{11}{14}\)
            \(\dfrac{2}{3}:x=\left(-7\right)-\dfrac{1}{3}\)                      \(\dfrac{9}{2}-2x\)           \(=\dfrac{11}{14}:\dfrac{11}{7}\)
            \(\dfrac{2}{3}:x=-\dfrac{22}{3}\)                             \(\dfrac{9}{2}-2x\)            \(=\dfrac{1}{2}\)
                  \(x=\dfrac{2}{3}.\left(-\dfrac{22}{3}\right)\)                           \(2x\)            \(=\dfrac{9}{2}-\dfrac{1}{2}\)
                  \(x=-\dfrac{1}{11}\)                                      \(2x\)            \(=4\) 
                                                                         \(x\)            \(=4:2\)
                                                                         \(x\)            \(=2\)

\(a,\dfrac{1}{3}+\dfrac{2}{3}:x=-7\\ \Rightarrow\dfrac{2}{3}:x=\dfrac{-22}{3}\\ \Rightarrow x=\dfrac{-1}{11}\\ b,\left(\dfrac{9}{2}-2x\right).\dfrac{11}{7}=\dfrac{11}{14}\\ \Rightarrow\dfrac{9}{2}-2x=\dfrac{1}{2}\\ \Rightarrow2x=4\\ \Rightarrow x=2\)

1/3+2/3:x=-7

       2/3:x=-7-1/3

       2/3:x=-22/3

             x=2/3:-22/3

             x=-1/11

(9/2-2x)x11/7=11/14

 (9/2-2x)        =11/14:11/7

(9/2-2x)          =1/2

       2x           =9/2-1/2

       2x=4

         x=4:2

        x=2

\(a.-8:\left(4\dfrac{1}{5}x+\dfrac{3}{10}\right)=4\dfrac{4}{9}\)

\(4\dfrac{1}{5}x+\dfrac{3}{10}=\left(-8\right):4\dfrac{4}{9}\)

\(4\dfrac{1}{5}x+\dfrac{3}{10}=\dfrac{-9}{5}\)

\(4\dfrac{1}{5}x=\dfrac{-9}{5}-\dfrac{3}{10}\)

\(4\dfrac{1}{5}x=\dfrac{-21}{10}\)

\(x=\dfrac{-21}{10}:\dfrac{21}{5}\)

\(x=\dfrac{-1}{2}\)

Vay \(x=\dfrac{-1}{2}\).

\(b.4\dfrac{2}{3}-\left(\dfrac{3}{5}:x\right)=-20\%\)

\(\dfrac{14}{3}-\left(\dfrac{3}{5}:x\right)=\dfrac{-1}{5}\)

\(\dfrac{3}{5}:x=\dfrac{14}{3}-\dfrac{-1}{5}\)

\(\dfrac{3}{5}:x=\dfrac{73}{15}\)

\(x=\dfrac{3}{5}:\dfrac{73}{15}\)

\(x=\dfrac{9}{73}\)

Vay \(x=\dfrac{9}{73}\).

Câu c; d; e tương tự nhé.