3.x+12=4.(x-7)
tìm x
a) X x 3/4 = 1/5 b) 3/7 x X = 2/5 c) 1/3 + 2/9 = 2/12 x X
d) 4/15 x X - 2/3 = 1/5 e) x : 1/7 = 2/3 f) 1/9 : x = 7/3 j) 1/4 + 5/12 = 8/3 : x
h) 7/4 : X - 1/2 = 1/5
a: x*3/4=1/5
=>x=1/5:3/4=1/5*4/3=4/15
b: x*3/7=2/5
=>x=2/5:3/7=2/5*7/3=14/15
c: 1/3+2/9=2/12x
=>1/6x=3/9+2/9=5/9
=>x=5/9*6=30/9=10/3
d: 4/15*x-2/3=1/5
=>4/15*x=2/3+1/5=10/15+3/15=13/15
=>4x=13
=>x=13/4
e: x:1/7=2/3
=>x=2/3*1/7=2/21
f: 1/9:x=7/3
=>x=1/9:7/3=1/9*3/7=3/63=1/21
j: 1/4+5/12=8/3:x
=>8/3:x=3/12+5/12=8/12=2/3
=>x=4
h: =>7/4:x=1/5+1/2=7/10
=>x=7/4:7/10=10/4=5/2
4 x 25 - 12 x 5 + 170 : 10
( 7 + 3 mũ 3 : 3 mũ 2 ) x 4 - 3
12 : {400 :[ 500 - ( 125 + 25 x 7 )]}
168 + { [ 2 x (2 mũ 4 + 3 mũ 2 ) - 256 mũ 0 ] : 7 mũ 2
a) 4.25-12.5+170:10
=100-60+17
=40+17
=57
b) (7+33:32).4-3
=(7+3).4-3
=10.4-3
=40-3
=37
c) 12:{400:[500-(125+25.7)]}
=12:{400:[500-(125+175)]}
=12:{400:[500-300]}
=12:{400:200}
=12:2
=6
d) 168+{[2.(24+32)-2560]:72}
=168+{[2.(16+9)-1]:49}
=168+{[2.25-1]:49}
=168+{[50-1]:49}
=168+{49:49}
=168+1
=169
Giá trị X trong biểu thức 4/7 x X = 1/3 A 7/12 B 4/21 C 12/7 D 3/21
Tính:
7/12 x 3/7 + 7/12 x 4/7
\(=\dfrac{7}{12}\times\left(\dfrac{3}{7}+\dfrac{4}{7}\right)=\dfrac{7}{12}\times\dfrac{7}{7}=\dfrac{7}{12}\)
`7/12xx3/7+7/12xx4/7=7/12xx(3/7+4/7)=7/12xx7/7=7/12`
\(\dfrac{7}{12}.\dfrac{3}{7}+\dfrac{7}{12}.\dfrac{4}{7}=\dfrac{7}{12}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)=\dfrac{7}{12}\)
a)-5.(-x+7)-3.(-x-5)=-4.(12-x)+48
b) (-x-7)-5.(-x-3)=12.(3-x)
c)-2.(15-3x)-4.(7x+8)=-5-9.(-2x+1)
d) (-3x-7) - 4.(-2x-11)=7.(4x+10)+9
\(a,-5.\left(-x+7\right)-3.\left(-x-5\right)=-4.\left(12-x\right)+48\)
\(5x-35-3x+15=-48+4x+48\)
\(2x-10=4x\)
\(2x-4x=10\)
\(-2x=10\)
\(x=-5\)
\(b,\left(-x-7\right)-5.\left(-x-3\right)=12.\left(3-x\right)\)
\(-x-7+5x+15=36-12x\)
\(4x+8=36-12x\)
\(4x+12x=36-8\)
\(16x=28\)
\(x=1,75\)
các câu còn lại tương tự nha
Tìm x:
\(\dfrac{3}{5}\) : x = \(\dfrac{1}{3}+\dfrac{1}{2}\) x : \(\dfrac{7}{12}\) = 2 x - \(\dfrac{3}{2}\) = \(\dfrac{11}{4}-\dfrac{5}{4}\) x + \(\dfrac{5}{4}\) = \(\dfrac{3}{2}+\dfrac{7}{12}\)
`3/5 : x =1/3 +1/2`
` 3/5 : x= 2/6 +3/6`
` 3/5 : x= 5/6`
` x= 3/5 : 5/6`
` x= 3/5 xx 6/5`
` x= 18/25`
__
`x: 7/15 =2`
` x= 2xx 7/15`
` x= 14/15`
__
`x-3/2=11/4-5/4`
`x-3/2= 6/4`
`x= 3/2 +3/2`
`x= 6/2`
`x=3`
__
`x+5/4 = 3/2+7/12`
`x+5/4 = 18/12+7/12`
`x+5/4 = 25/12`
`x= 25/12-5/4`
`x= 25/12- 15/12`
`x= 10/12`
`x= 5/6`
1) so sánh phân số
a) -8/12 và -3/-4 b)-56 /24 và 7/3 c) -4/25 và 15/-13
2) tính
a) 3/5 x 20/ -9
b)4/15 + -3/2 +8/-5
c) 19/35 x -38/7
d) -7/12 x 13/14 +1/14 x (-7) /12
Bài 1:
a: -8/12<0<-3/-4
b: -56/24<0<7/3
c: 4/25<1<15/13
=>-4/25>-15/13
Bài 2:
a: =-60/45=-4/3
b: =4/15-3/2-8/5=8/30-45/30-48/30=-85/30=-17/6
Tìm x
a,-5×(-x+7)-3×(-x-5)=-4×(12-x)+48
b,-2×(15-3x)-4×(-7x+8)=,-5-9×(-2x+1)
c,7×(-x-7)-5×(-x-3)=12×(3-x)
d,5×(-3x-7)-4×(-2x-11)=7×(4x+10)+9
a ) \(-5\times\left(-x+7\right)-3\times\left(-x-5\right)=-4\times\left(12-x\right)+48\)
\(\Leftrightarrow5x-35+3x+15=-48+4x+48\)
\(\Leftrightarrow5x-3x+4x=35-15-48+48\)
\(\Leftrightarrow2x=20\)
\(\Leftrightarrow x=10\)
b ) \(-2\times\left(15-3x\right)-4\times\left(-7x+8\right)=-5-9\times\left(-2x+1\right)\)
\(\Leftrightarrow-30+6x-28x-32=-5+18x-9\)
\(\Leftrightarrow6x-28x-18x=30+32-5-9\)
\(\Leftrightarrow-40x=48\)
\(\Leftrightarrow x=-1.2\)
c, 7 . ( - x - 7 ) - 5 . ( - x - 3 ) = 12 . ( 3 - x)
<=> - 7x - 49 + 5x + 15 = 36 - 12x
<=> - 2x + 12x = 36 - 15 + 49
<=> 10 x = 70
<=> x = 7
Vẫy x = 7
d, 5 . ( - 3x - 7 ) - 4 . ( - 2x - 11 ) = 7 . ( 4x + 10) + 9
<=> - 15x + 8x + 44 = 28x + 70 + 9
<=> - 7x + 44 = 28x + 79
<=> - 7x - 28x = 79 - 44
<=> - 35x = 35
<=> x = - 1
Vậy x = - 1
Hc tốt
\(\dfrac{1}{(x-3)(x-4)}\)\(+\dfrac{3}{(x-4)(x-7)}+\dfrac{5}{(x-7)(x-12)}=\dfrac{1}{4}\)
ĐKXĐ:\(x\ne3,4,7,12\)
\(\dfrac{1}{\left(x-3\right)\left(x-4\right)}+\dfrac{3}{\left(x-4\right)\left(x-7\right)}+\dfrac{5}{\left(x-7\right)\left(x-12\right)}=\dfrac{1}{4}\\ \Leftrightarrow\dfrac{1}{x-3}-\dfrac{1}{x-4}+\dfrac{1}{x-4}-\dfrac{1}{x-7}+\dfrac{1}{x-7}-\dfrac{1}{x-12}=\dfrac{1}{4}\\ \Leftrightarrow\dfrac{1}{x-3}-\dfrac{1}{x-12}=\dfrac{1}{4}\\ \Leftrightarrow\dfrac{x-12-x+3}{\left(x-3\right)\left(x-12\right)}=\dfrac{1}{4}\\ \Leftrightarrow\dfrac{-9}{x^2-15x+36}=\dfrac{1}{4}\\ \Leftrightarrow x^2-15x+36=-36\\ \Leftrightarrow x^2-15x+72=0\)
\(\Leftrightarrow x^2-2.\dfrac{15}{2}x+\dfrac{225}{4}+\dfrac{63}{4}=0\\ \Leftrightarrow\left(x-\dfrac{15}{2}\right)^2+\dfrac{63}{4}=0\left(vô.lí\right)\)
\(\Leftrightarrow\dfrac{1}{x-3}-\dfrac{1}{x-4}+\dfrac{1}{x-4}-\dfrac{1}{x-7}+\dfrac{1}{x-7}-\dfrac{1}{x-12}=\dfrac{1}{4}\)
\(\Leftrightarrow\dfrac{1}{x-3}-\dfrac{1}{x-12}=\dfrac{1}{4}\)
\(\Leftrightarrow\dfrac{x-12-x+3}{\left(x-3\right)\left(x-12\right)}=\dfrac{1}{4}\)
\(\Leftrightarrow\left(x-3\right)\left(x-12\right)=-36\)
=>x(x-15)=0
=>x=0 hoặc x=15
Tìm x
1; 3. ( x - 4) - ( 8 - x) = 12
2; 5. ( x - 6 ) - 2 ( x + 3) = 12
3; 5 - | x + 7| = 4
4; 6. | x - 7 | = 18 : (-3)
1) 3(x - 4) - (8 - x) = 12
3x - 12 - 8 + x = 12
4x - 20 = 12
4x = 12 + 20
4x = 32
x = 8
2) 5(x - 6) - 2(x + 3) = 12
5x - 30 - 2x - 6 = 12
3x - 36 = 12
3x = 12 + 36
3x = 48
x = 16
3) 5 - | x + 7| = 4
|x + 7| = 4 - 5
|x + 7| = -1 x + 7 = 1; -1 x + 7 = 1 hoặc x + 7 = -1 x = 1 - 7 x = -1 - 7 x = -6 x = -8 => x = -6 hoặc x = -8 4) 6|x - 7| = 18 : (-3) 6|x - 7| = -6 6|x - 7| = -6 : 6 |x - 7| = -1 x - 7 = 1; -1 x - 7 = 1 hoặc x - 7 = -1 x = 1 + 7 x = -1 + 7 x = 8 x = 6 => x = 8 hoặc x = 61, \(3.\left(x-4\right)-\left(8-x\right)=12\)
\(\Leftrightarrow3x-12-8+x=12\)
\(\Leftrightarrow3x+x=12+12+8\)
\(\Leftrightarrow4x=32\)
\(\Leftrightarrow x=8\)
Vậy : \(x=8\)
2, \(5.\left(x-6\right)-2.\left(x+3\right)=12\)
\(\Leftrightarrow5x-30-2x-6=12\)
\(\Leftrightarrow5x-2x=12+30+6\)
\(\Leftrightarrow3x=48\)
\(\Leftrightarrow x=\frac{48}{3}=16\)
Vậy : \(x=16\)
3, \(5-\left|x+7\right|=4\)
\(\Leftrightarrow\left|x+7\right|=5-4=1\)
\(\Leftrightarrow\left[{}\begin{matrix}x+7=1\\x+7=-1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-8\end{matrix}\right.\)
Vậy : \(x\in\left\{6,-8\right\}\)
4, \(6.\left|x-7\right|=18:\left(-3\right)\)
\(\Leftrightarrow6.\left|x-7\right|=-6\)
\(\Leftrightarrow\left|x-7\right|=-1\)
Ta thấy : \(\left|x-7\right|\ge0\forall x\) mà \(-1< 0\)
\(\Rightarrow x\in\varnothing\)
Vậy : không có \(x\) thỏa mãn đề.