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mình ghi lộn

\(\Leftrightarrow x=-8\cdot32=-256\)

\(ĐK:x\ge2013\\ PT\Leftrightarrow\sqrt{x-2013}+2\sqrt{x-2013}=3\\ \Leftrightarrow3\sqrt{x-2013}=3\\ \Leftrightarrow\sqrt{x-2013}=1\Leftrightarrow x-2013=1\\ \Leftrightarrow x=2014\left(tm\right)\)

\(\sqrt{x-2013}+\sqrt{4x-8052}=3\)

\(\Leftrightarrow\sqrt{x-2013}+\sqrt{4\left(x-2013\right)}=3\)

\(\Leftrightarrow\sqrt{x-2013}+2\sqrt{x-2013}=3\)

\(\Leftrightarrow3\sqrt{x-2013}=3\)

\(\Leftrightarrow\sqrt{x-2013}=1\)

\(\Leftrightarrow x-2013=1\)

\(\Leftrightarrow x=2014\)

35 : 8 = 4 ( dư 3 )

X = 8

Lời giải:
$\frac{xy+3x-2y-6}{y+3}=3$

$\Rightarrow xy+3x-2y-6=3y+9$

$\Rightarrow xy+3x-5y-15=0$

$\Rightarrow x(y+3)-5(y+3)=0$

$\Rightarrow (y+3)(x-5)=0$

$\Rightarrow y+3=0$ hoặc $x-5=0$

Mà $y$ tự nhiên nên $y+3>0$. Do đó $x-5=0$

$\Rightarrow x=5$

Vậy $x=5$ và $y$ là số tự nhiên tùy ý.

b: Ta có: \(\dfrac{12}{5}:x+\dfrac{4}{3}=3+\dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{12}{5}:x=3-\dfrac{2}{3}=\dfrac{7}{3}\)

hay \(x=\dfrac{12}{5}:\dfrac{7}{3}=\dfrac{36}{35}\)

`a)37/9-y=6/5xx15/16`

`37/9-y=9/8`

`y=37/9-9/8`

`y=296/72-81/72=215/72`

`b)y xx3/15=4/5-2/3`

`y xx3/15=12/15-10/15`

`y xx3/15=2/15`

`y=2/15:3/15`

`y=2/15xx15/3=2/3`

a, 37/9 - Y = 6/5 x 15/16

37/9 - Y = 9/8

Y = 37/9 - 9/8

Y = 296/72 - 81/72

Y = 215/72

b, Y x 3/15 = 4/5 - 2/3

 Y x 3/15 =  2/15

Y = 2/15 : 3/15

Y = 2/15 x 15/3

Y = 2/3

=>3x+3+5x-5=3x^2-3

=>3x^2-3=8x-2

=>3x^2-8x-1=0

=>\(x=\dfrac{4\pm\sqrt{19}}{3}\)

\(a.x+\dfrac{3}{7}=\dfrac{2}{5}:\dfrac{18}{35}\\x+\dfrac{3}{7}=\dfrac{2}{5}\times\dfrac{35}{18} \\ x+\dfrac{3}{7}=\dfrac{7}{9}\\ x=\dfrac{7}{9}-\dfrac{3}{7}\\ x=\dfrac{22}{63}\)

\(b.x\times\dfrac{5}{9}=\dfrac{4}{5}-\dfrac{1}{3}\\x\times\dfrac{5}{9}=\dfrac{7}{15}\\ x=\dfrac{7}{15}:\dfrac{5}{9}\\ x= \dfrac{21}{25}\)

mk đã giải cho bạn rồi nhé! bạn xem lại phần thông báo ạ!

a. x + \(\dfrac{3}{7}\)= \(\dfrac{2}{5}:\dfrac{18}{25}=>x+\dfrac{3}{7}=\dfrac{2}{5}\)x\(\dfrac{35}{18}=>x+\dfrac{3}{7}=\dfrac{7}{9}\)

=> x = \(\dfrac{7}{9}-\dfrac{3}{7}=\dfrac{49}{63}-\dfrac{27}{63}=\dfrac{22}{63}\)

b. \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{4}{5}-\dfrac{1}{3}\)

=> \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{12}{15}-\dfrac{5}{15}=>x\) x \(\dfrac{5}{9}\)= \(\dfrac{7}{15}\)

=> x = \(\dfrac{7}{15}:\dfrac{5}{9}\)

=> x = \(\dfrac{21}{25}\)

a,x + 3/7 = 2/5 : 18/35

   x + 3/7 = 7/9

   x          = 7/9 - 3/7

   x          = 22/63

vậy x = ...

b, X x 5/9 = 4/5 - 1/3

    X x 5/9 = 7/15

            X  = 7/15 : 5/9

            X  = 21/25

vậy X = ...