a) Ta có: 

\(A=-3\cdot7\cdot\left(-2\right)\cdot\left(-13\right)\)

\(A=-21\cdot26\)

\(A=-546\)

\(B=-1\cdot\left(-2\right)\cdot\left(-3\right)\cdot\left(-4\right)\cdot5\)

\(B=2\cdot12\cdot5\)

\(B=2\cdot60\)

\(B=120\)

Mà: \(120>-546\)

\(\Rightarrow B>A\)

a)-2

b)-7

c)12

e)4

c)-15

g)8

a) -2
b) -7
c) 12
e) 4
c) -15
g) 8

a) 6 – 8 = -2

d) 0 – 7; = -7

b) 3 – (-9); = 12

e) 4 – 0; = 4

c) (-5) – 10; = -15

g) (-2) – (-10). = 8

a,5/9+(-3/5)  +( -5/9)

=5/9+(-5/9)+(-3/5)

=0+(-3/5)

=-3/5

b, b,-3/7. 2/11- (-3/7).9/11

=-3/7.(2/11-9/11)

=-3/7.(-7/11)

=3/11

c,,2/3 + 5/6 : 5 - 1/18 . (-3)

=2/3+(1/6-(-1/6))

=2/3+1/3

=3/3

=1

tick nếu đúng nha

Dễ mà, dùng máy tính là xong

a,5/9+(-3/5)  +( -5/9)

=5/9+(-5/9)+(-3/5)

=0+(-3/5)

=-3/5

b, b,-3/7. 2/11- (-3/7).9/11

=-3/7.(2/11-9/11)

=-3/7.(-7/11)

=3/11

c,,2/3 + 5/6 : 5 - 1/18 . (-3)

=2/3+(1/6-(-1/6))

=2/3+1/3

=3/3

=1

a)\(\dfrac{19}{48}-\dfrac{3}{40}=\dfrac{95}{240}-\dfrac{18}{240}=\dfrac{77}{240}\)

b)\(\dfrac{1}{6}+\dfrac{7}{27}+\dfrac{5}{18}=\dfrac{9}{54}+\dfrac{14}{54}+\dfrac{15}{54}=\dfrac{38}{54}=\dfrac{19}{27}\)

a) 19/48 - 3/40= 77/240

b) 1/6 + 7/27 + 5/18= 23/54 + 5/18= 19/27

a)\(\dfrac{19}{48}\) - \(\dfrac{3}{40}\)=\(\dfrac{77}{240}\)

b) \(\dfrac{1}{6}\)+\(\dfrac{7}{27}\)+\(\dfrac{5}{18}\)=\(\dfrac{23}{54}\)+\(\dfrac{5}{18}\)=\(\dfrac{19}{27}\)

a)\(\frac{{ - 2}}{5} + \frac{3}{7} = \frac{{ - 14}}{{35}} + \frac{{15}}{{35}} = \frac{1}{{35}}\)           

b)\(0,123 - 0,234 =  - \left( {0,234 - 0,123} \right) =  - 0,111.\)

a)\(\frac{1}{8}.\frac{3}{5} = \frac{{1.3}}{{8.5}} = \frac{3}{{40}}\)           

b)\(\frac{{ - 6}}{7}:\left( { - \frac{5}{3}} \right) = \frac{{ - 6}}{7}.\frac{{ - 3}}{5} = \frac{{18}}{{35}}\)           

c)\(0,6.\left( { - 0,15} \right) = \frac{6}{{10}}.\frac{{ - 15}}{{100}} = \frac{{ - 90}}{{1000}} = \frac{{ - 9}}{{100}}\).

a) \(6 - 8 = 6 + \left( { - 8} \right) =  - \left( {8 - 6} \right) =  - 2\)

b) \(3 - \left( { - 9} \right) = 3 + 9 = 12\)

c) \(\left( { - 5} \right) - 10 = \left( { - 5} \right) + \left( { - 10} \right)\)\( =  - \left( {5 + 10} \right) =  - 15\)

d) \(0 - 7 = 0 + \left( { - 7} \right) =  - 7\)

e) \(4 - 0 = 4 + 0 = 4\) (vì số đối của 0 là 0)

g) \(\left( { - 2} \right) - \left( { - 10} \right) = \left( { - 2} \right) + 10\)\( = 10 - 2 = 8\).

a) \(\left( { - 5} \right).4 =  - \left( {5.4} \right) =  - 20\)

b) \(6.\left( { - 7} \right) =  - \left( {6.7} \right) =  - 42\)

c) \(\left( { - 14} \right).20 =  - \left( {14.20} \right) =  - 280\)

d) \(51.\left( { - 24} \right) =  - \left( {51.24} \right) =  - 1224\)

a: =0+5=5

b: =10/1=10

a) Mẫu số chung = BCNN(11, 7) = 77

Thừa số phụ: 77: 11= 7; 77:7 = 11.

Ta có:

\(\begin{array}{l}\frac{7}{{11}} + \frac{5}{7} = \frac{{7.7}}{{11.7}} + \frac{{5.11}}{{7.11}}\\ = \frac{{49}}{{77}} + \frac{{55}}{{77}} = \frac{{104}}{{77}}\end{array}\).

b) Mẫu số chung = BCNN(20, 15)= 60 

Thừa số phụ: 60:20 = 3; 60:15 = 4

Ta có:

\(\begin{array}{l}\frac{7}{{20}} - \frac{2}{{15}} = \frac{{7.3}}{{20.3}} - \frac{{2.4}}{{15.4}}\\ = \frac{{21}}{{60}} - \frac{8}{{60}} = \frac{{13}}{{60}}\end{array}\).