Tìm X:
a) X x 2 = 2 x 10
b) 47 – X = 28 : 4
Những câu hỏi liên quan
Bài 2: Tìm x:a) 156 – (x+ 61) 82 b) (x-35) -120 0c) 124 + (118 – x) 217 d) 7x – 8 713e) x- 36:18 12 f) (x- 36):18 12g) (x-47) -115 0 Bài 3: Tính nhanha) 58.75 + 58.50 – 58.25b) 27.39 + 27.63 – 2.27c) 128.46 + 128.32 + 128.22d) 66.25 + 5.66 + 66.14 + 33.66e) 12.35 + 35.182 – 35.94f) 48.19 + 48.115 + 134.52g) 27.121 – 87.27 + 73.34h) 125.98 – 125.46 – 52.25i) 136....
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Bài 2: Tìm x:
a) 156 – (x+ 61) = 82 b) (x-35) -120 = 0 c) 124 + (118 – x) = 217 d) 7x – 8 = 713 e) x- 36:18 = 12 f) (x- 36):18 = 12 g) (x-47) -115 = 0 |
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Bài 3: Tính nhanh
a) 58.75 + 58.50 – 58.25 b) 27.39 + 27.63 – 2.27 c) 128.46 + 128.32 + 128.22 d) 66.25 + 5.66 + 66.14 + 33.66 e) 12.35 + 35.182 – 35.94 | f) 48.19 + 48.115 + 134.52 g) 27.121 – 87.27 + 73.34 h) 125.98 – 125.46 – 52.25 i) 136.23 + 136.17 – 40.36 j) 17.93 + 116.83 + 17.23 | k) 35.23 + 35.41 + 64.65 l) 29.87 – 29.23 + 64.71 m) 19.27 + 47.81 + 19.20
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Bài 4: Tính giá trị của biểu thức sau:
a) 2763 + 152 b) (-7) + (-14) c) (-35) + (-9) d) (-5) + (-248) e) (-23) + 105 f) 78 + (-123) g) 23 + (-13) h) (-23) + 13 i) 26 + (-6) | j) 80 + (-220) k) (-23) + (-13) l) (-26) + (-6) | m) 12 – 34 n) -23 – 47 o) 31 – (-23) p) -9 – (-5) q) 6 – (8 – 17) r) 19 + (23 – 33) s) (-12 – 44) + (-3) t) 4 – (-15) u) -29 – 23 | v) 99 – [109 + (-9)] w) (-75) + 50 x) (-75) + (-50) y) (-23) + 13 + ( - 17) + 57 z) 14 + 6 + (-9) + (-14)
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a: =>x+61=74
hay x=13
b: =>x-35=120
hay x=155
d: =>7x=721
hay x=103
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Tìm x:a) dfrac{-3}{7}.xdfrac{3}{56}.dfrac{28}{9}b) x-dfrac{3}{16}dfrac{7}{15}:dfrac{3}{5}c) dfrac{2}{5}+dfrac{1}{5}.xdfrac{5}{6}d) dfrac{3}{4}x-dfrac{2}{5}xdfrac{3}{7}.dfrac{1}{6}+dfrac{5}{7}.dfrac{1}{6}*Lưu ý: Trình bày chi tiết kết quả.
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Tìm x:
a) \(\dfrac{-3}{7}\).x=\(\dfrac{3}{56}\).\(\dfrac{28}{9}\)
b) x-\(\dfrac{3}{16}\)=\(\dfrac{7}{15}\):\(\dfrac{3}{5}\)
c) \(\dfrac{2}{5}\)+\(\dfrac{1}{5}\).x=\(\dfrac{5}{6}\)
d) \(\dfrac{3}{4}\)x-\(\dfrac{2}{5}\)x=\(\dfrac{3}{7}\).\(\dfrac{1}{6}\)+\(\dfrac{5}{7}\).\(\dfrac{1}{6}\)
*Lưu ý: Trình bày chi tiết kết quả.
a)\(x=\left(\dfrac{3}{56}\cdot\dfrac{28}{9}\right):\dfrac{-3}{7}=\dfrac{1}{6}:\dfrac{-3}{7}=-\dfrac{7}{18}\)
b)\(x=\left(\dfrac{7}{15}\cdot\dfrac{5}{3}\right)+\dfrac{3}{16}=\dfrac{7}{9}+\dfrac{3}{16}=\dfrac{139}{144}\)
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c)\(x=\left(\dfrac{5}{6}-\dfrac{2}{5}\right).5=\dfrac{13}{6}\)
d)\(=>x\left(\dfrac{3}{4}-\dfrac{2}{5}\right)=\dfrac{1}{6}\cdot\left(\dfrac{3}{7}+\dfrac{5}{7}\right)\)
\(x\cdot\dfrac{7}{20}=\dfrac{4}{21}=>x=\dfrac{4}{21}\cdot\dfrac{20}{7}=\dfrac{80}{147}\)
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tìm x biết
a) (x-2)3-x(x+1)(x-1)+6x(x-3)=10
b) (x+1)3-(x-1)3-6(x-1)2= -10
c) x3+3x2+3x+28=0
d) x3-6x2+12x-7=0
\(a,PT\Leftrightarrow x^3-6x^2+12x-8-x^3+x+6x^2-18x-10=0\)
\(\Leftrightarrow-5x-18=0\)
\(\Leftrightarrow x=-\dfrac{18}{5}\)
Vậy ...
\(b,PT\Leftrightarrow x^3+3x^2+3x+1-x^3+3x^2-3x+1-6x^2+12x-6+10=0\)
\(\Leftrightarrow12x+6=0\)
\(\Leftrightarrow x=-\dfrac{1}{2}\)
Vậy ...
\(c,PT\Leftrightarrow\left(x+1\right)^3+3^3=0\)
\(\Leftrightarrow\left(x+1+3\right)\left(x^2+2x+1-3x-3+9\right)=0\)
\(\Leftrightarrow\left(x+4\right)\left(x^2-x+7\right)=0\)
Thấy : \(x^2-\dfrac{2.x.1}{2}+\dfrac{1}{4}+\dfrac{27}{4}=\left(x-\dfrac{1}{2}\right)^2+\dfrac{27}{4}\ge\dfrac{27}{4}>0\)
\(\Rightarrow x+4=0\)
\(\Leftrightarrow x=-4\)
Vậy ...
\(d,PT\Leftrightarrow\left(x-2\right)^3+1^3=0\)
\(\Leftrightarrow\left(x-2+1\right)\left(x^2-4x+4-x+2+1\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(x^2-5x+7\right)=0\)
Thấy : \(x^2-5x+7=x^2-\dfrac{5.x.2}{2}+\dfrac{25}{4}+\dfrac{3}{4}=\left(x-\dfrac{5}{2}\right)^2+\dfrac{3}{4}\ge\dfrac{3}{4}>0\)
\(\Rightarrow x-1=0\)
\(\Leftrightarrow x=1\)
Vậy ...
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Tìm x:
a) x²+10x=25
b) (x+2)²+4(x+2)+4=0
\(a,\Leftrightarrow x^2+10x-25=0\)
( Không biết có nhầm đề không ;-; )
\(b,\Leftrightarrow\left(\left(x+2\right)+2\right)^2=0\)
\(\Leftrightarrow\left(x+4\right)^2=0\)
\(\Leftrightarrow x+4=0\)
\(\Leftrightarrow x=-4\)
Vậy ...
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\(a,x^2+10x=25< =>x^2+10x-25=0\)
\(< =>x^2+10x+25-50=0\)
\(< =>\left(x+5\right)^2-\left(\sqrt{50}\right)^2=0\)
\(< =>\left(x+5+\sqrt{50}\right)\left(x+5-\sqrt{50}\right)=0\)
\(=>\left[{}\begin{matrix}x=\sqrt{50}-5\\x=-\sqrt{50}-5\end{matrix}\right.\)
b, \(\left(x+2\right)^2+4\left(x+2\right)+4=0\)
\(< =>x^2+4x+4+4x+8+4=0\)
\(< =>x^2+8x+16=0\)
\(< =>\left(x+4\right)^2=0< =>x=-4\)
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- Lớp 8 chưa học căn bậc 2 nên có thể đề câu a sai nha ;-;
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Tìm x:
a)x.(x+7)-(x-2).(x+3)=0
b)(x+2)2-(x2-4)=0
a: \(x\left(x+7\right)-\left(x-2\right)\left(x+3\right)=0\)
\(\Leftrightarrow x^2+7x-x^2-x+6=0\)
hay x=-1
b: Ta có: \(\left(x+2\right)^2-\left(x^2-4\right)=0\)
\(\Leftrightarrow x+2=0\)
hay x=-2
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b. (x + 2)2 - x2 + 4 = 0
<=> (x + 2 - x)(x + 2 + x) + 4 = 0
<=> 2(2 + 2x) + 4 = 0
<=> 4(1 + x) + 4 = 0
<=> 4(1 + x) = -4
<=> 1 + x = -1
<=> x = -1 - 1
<=> x = -2
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\(a,\) \(x\left(x+7\right)-\left(x-2\right)\left(x+3\right)\)
\(\Leftrightarrow x^2+7x-x^2-3x+2x+6\\ \Leftrightarrow6x=0\\ \Leftrightarrow x=0\)
\(Vậy...\)
\(b,\) \(\left(x+2\right)^2-\left(x^2-4\right)=0\)
\(\Leftrightarrow x^2+4x+4-x^2+4=0\\ \Leftrightarrow4x+8=0\\ \Leftrightarrow x=-2\)
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Xem thêm câu trả lời
Tìm x:
a, 4.( x + 41 ) = 7
b, x. ( x-51 ) 2. 2 mũ 3 + 20
a) 4(x+41)=7
x+41=7/4
x=7/4-41
x=157/4
b) có gì đó sai sai-.-
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Tìm x:
a) (x + 5)2 - x(x - 4) = 55
b) x(x - 7) - 3x + 21 = 0
a: \(\Leftrightarrow x^2+10x+25-x^2+4x=55\)
=>14x=30
hay x=15/7
b: \(\Leftrightarrow\left(x-7\right)\left(x-3\right)=0\)
hay \(x\in\left\{7;3\right\}\)
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26 tháng 12 2023 lúc 20:30
B1: Tìm x
a) (x-3)^2+(4-x)(x+4)=10
b) x^2-2x=0
c) (x^2-9)^2-(x-3)^2=0
a) \(\left(x-3\right)^2+\left(4-x\right)\left(x+4\right)=10\)
\(\Leftrightarrow\left(x^2-2\cdot x\cdot3+3^2\right)+\left(4-x\right)\left(4+x\right)=10\)
\(\Leftrightarrow x^2-6x+9+\left(4^2-x^2\right)-10=0\)
\(\Leftrightarrow x^2-6x-1+16-x^2=0\)
\(\Leftrightarrow-6x+15=0\)
\(\Leftrightarrow6x=15\)
\(\Leftrightarrow x=\dfrac{5}{2}\)
b) \(x^2-2x=0\)
\(\Leftrightarrow x\left(x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)
c) \(\left(x^2-9\right)^2-\left(x-3\right)^2=0\)
\(\Leftrightarrow\left(x^2-3^2\right)^2-\left(x-3\right)^2=0\)
\(\Leftrightarrow\left(x-3\right)^2\left(x+3\right)^2-\left(x-3\right)^2=0\)
\(\Leftrightarrow\left(x-3\right)^2\left[\left(x+3\right)^2-1\right]=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(x-3\right)^2=0\\\left(x+3\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-3=0\\\left(x+3\right)^2=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x+3=1\\x+3=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\\x=-4\end{matrix}\right.\)
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Tìm x:
a) (x + 2) (x - 4) - x2 = 36
b) (x - 2)(4x + 1) - 4x(x + 7) = 1
c) x(x - 10) - x + 10 = 0
a: \(\Leftrightarrow x^2-2x-8-x^2=36\)
=>-2x=44
hay x=-22
b: \(\Leftrightarrow4x^2+x-8x-2-4x^2-27x=1\)
=>-34x=3
hay x=-3/34
c: =>(x-10)(x-1)=0
=>x=10 hoặc x=1
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