a: Để (d)//y=x-3 thì \(4-m^2=1\)

\(\Leftrightarrow m\in\left\{\sqrt{3};-\sqrt{3}\right\}\)

16) ĐKXĐ: \(x\ge-\dfrac{1}{4}\)

\(\sqrt{4x+1}-\sqrt{3x+4}=1\\ \Leftrightarrow\sqrt{4x+1}=1+\sqrt{3x+4}\\ \Rightarrow4x+1=1+3x+4+2\sqrt{3x+4}\\ \Leftrightarrow x-4=2\sqrt{3x+4}\\ \Leftrightarrow x^2-8x+16=12x+16\\ \Leftrightarrow x^2-20x=0\\ \Leftrightarrow x\left(x-20\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=20\end{matrix}\right.\)

Thử lại \(x=0\) không thỏa mãn \(\Rightarrow x=20\)

\(16,ĐK:x\ge-\dfrac{1}{4}\\ PT\Leftrightarrow\sqrt{4x+1}=\sqrt{3x+4}+1\\ \Leftrightarrow4x+1=3x+4+1+2\sqrt{3x+4}\\ \Leftrightarrow x-4=2\sqrt{3x+4}\\ \Leftrightarrow x^2-8x+16=12x+16\\ \Leftrightarrow x^2-20x=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\left(tm\right)\\x=20\left(tm\right)\end{matrix}\right.\)

\(17,ĐK:x\ge2\\ PT\Leftrightarrow2x+2\sqrt{\left(x+2\sqrt{2x-4}\right)\left(x-2\sqrt{2x-4}\right)}=8\\ \Leftrightarrow4-x=\sqrt{x^2-4\left(2x-4\right)}\\ \Leftrightarrow\sqrt{x^2-8x+16}=4-x\\ \Leftrightarrow\left|x-4\right|=4-x\\ \Leftrightarrow\left[{}\begin{matrix}x-4=4-x\left(x\ge4\right)\\4-x=4-x\left(2\le x< 4\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=4\end{matrix}\right.\)

bạn đăng lại đề được không? Nhìn không rõ

1 do you prefer

2 is having

3 don't like

4 know

5 is singing

6 is - laughing

is watching

1, do-prefer

2,is having

3,don't like

4,know

5,is singing

6,is-laughing, is watching

1. wanting -> want
2. do -> am doing
3. are hating -> hate
4. doesn't -> don't
6. I'm -> I

4C . 2400 nu

5D

6C

Nếu thi thì em ko giúp ạ

4C

5D

6C

A lớn hơn B

A lớn hơn B

A= a+b+c+d + 600 + 50 + 9 + 1341 = 2000

B= a+b+c+d + 1999 = 1999