-36-|3x - 3| = -27

=> |3x - 3 | = -36 - 27

=> | 3x - 3| = -63 ( vô lý)

=> x ko có giá trị

-36-|3x-3|=-27

|3x-3|=-36+27

|3x-3|=-9

=> 3x-3=-9 hoặc 3x-3=9

TH1: 3x-3=-9

3x =-9+3

3x =-6

x=-6:3

x=-2

TH2: 3x-3=9

3x =9+3

3x =12

x=12:3

x=4

Vậy x∈{-2;4}

Ta có: -36-|3x-3|=-27

⇔|3x-3|=-36-(-27)=-36+27=-9

Vì |3x-3|≥0 nên với |3x-3|=-9 thì x không có giá trị

Vậy: x∈∅

a) (3x-1)³ = 27 = 3³

=> 3x - 1 = 3

3x = 4

x = 4/3

b) 3^2x-1 = 27 = 3³

=> 2x - 1 = 3

2x = 4

x = 2

c) 6^8-2x = 36 = 6²

=> 8 -2x = 2

=> 2x = 6

x = 3

d) (3x-2)¹⁰ = (3x-2)⁷

=> (3x-2)¹⁰ - (3x-2)⁷ = 0

(3x-2)⁷. [(3x-2)³ - 1] = 0

=> (3x-2)⁷ = 0 => 3x-2 = 0 => 3x = 2 => x = 2/3

(3x-2)³ - 1 = 0 => (3x-2)³ =  1 => 3x - 2 = 1 => 3x = 3 => x = 1

KL:...

\(\left(3x-1\right)^3=3^3\)

\(3x-1=3=>3x=4\)

\(=>x=\frac{4}{3}\)

3x = 27-36

3x= -9

x = -9: 3

x = -3

=> 3x =27-36

 3x=-9

x=-9:3

x=-3

-3

x= -3 

\(27-3x=36\)

        \(3x=27-36\)

        \(3x=-9\)

          \(x=\left(-9\right):3\)

          \(x=-3\)

x = - 3

a) \(\left(x+\frac{1}{2}\right)^2=\frac{1}{16}\)

\(\Rightarrow x+\frac{1}{2}=\pm\frac{1}{4}\)

\(\Rightarrow\left[{}\begin{matrix}x+\frac{1}{2}=\frac{1}{4}\\x+\frac{1}{2}=-\frac{1}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{1}{4}-\frac{1}{2}\\x=\left(-\frac{1}{4}\right)-\frac{1}{2}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\frac{1}{4}\\x=-\frac{3}{4}\end{matrix}\right.\)

Vậy \(x\in\left\{-\frac{1}{4};-\frac{3}{4}\right\}.\)

b) \(\left(3x+1\right)^3=-27\)

\(\Rightarrow\left(3x+1\right)^3=\left(-3\right)^3\)

\(\Rightarrow3x+1=-3\)

\(\Rightarrow3x=\left(-3\right)-1\)

\(\Rightarrow3x=-4\)

\(\Rightarrow x=\left(-4\right):3\)

\(\Rightarrow x=-\frac{4}{3}\)

Vậy \(x=-\frac{4}{3}.\)

Mấy câu sau làm tương tự nhé.

Chúc bạn học tốt!

c)\(\left(3x-2\right)^2=36\\ \Leftrightarrow\left(3x-2\right)^2=\left(\pm6\right)^2\\ \Rightarrow\left\{{}\begin{matrix}3x-2=6\\3x-2=-6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\frac{8}{3}\\x=-\frac{4}{3}\end{matrix}\right.\)

d)\(\left(\frac{2}{5}-3x\right)^2=\frac{9}{25}\\ \Leftrightarrow\left(\frac{2}{5}-3x\right)^2=\left(\pm\frac{3}{5}\right)^2\\ \Rightarrow\left\{{}\begin{matrix}\frac{2}{5}-3x=\frac{3}{5}\\\frac{2}{5}-3x=-\frac{3}{5}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-\frac{1}{15}\\x=\frac{1}{3}\end{matrix}\right.\)

a: =>3x=10+14=24

=>x=8

b: =>25-30-x=-19

=>-5-x=-19

=>x+5=19

=>x=14

c: =>15-x=12+14=26

=>x=-11

d: =>4x+11-x-34=67

=>3x-23=67

=>3x=90

=>x=30

e: =>-x-14=289-36-289=-36

=>x+14=36

=>x=22

a) 3x=24
     x=8
b) 25-30-x=-19
    25-30+19=x
     14=x
c) 15-x=26
         x=-11
d) 4x+11-x-34=67
    3x=90
      x=30
e) -14-x= -36
          x=-14 -36
          x= 22
      
 

\(36+3x=195\)

\(\Rightarrow3x=195-36=159\)

\(\Rightarrow x=159:3\)

\(\Rightarrow x=53\)

Vậy x = 53

\(27.3^x=3^6\)

\(\Rightarrow3^x=3^6:3^3\)

\(\Rightarrow3^x=3^3\)

Vậy x = 3

a) 42 - x = 5

x = 42 - 5

x = 37

b) 15.(x + 4) = 75

x + 4 = 75 : 15

x + 4 = 5

x = 5 - 4

x = 1

d) x + 18 = 12

x = 12 - 18

x = -6

e) 2x - 15 = -19

2x = (-19) + 15

2x = -4

x = -4 : 2

x = -2

f) 36 : (x^3 - 12) = -3

x^3 - 12 = 36 : (-3)

x^3 - 12 = -12

x^3 = 0

=> x = 0

g)x + 15 = 35

x = 35 - 15

x = 20

h) 2x - 13 = 3^2

2x - 13 = 9

2x = 9 + 13

2x = 22

x = 22 : 2

x = 11

a) 42-x=5

         x=42-5

         x= 37

b)15*(x+4)=75

        x+4=75:15

        x+4=5

        x    =5-4

       x     = 1

a) 42 - x = 5

x = 42 - 5

x = 37

b) 15.(x + 4) = 75

x + 4 = 75 : 15

x + 4 = 5

x = 5 - 4

x = 1

d) x + 18 = 12

x = 12 - 18

x = -6

e) 2x - 15 = -19

2x = (-19) + 15

2x = -4

x = -4 : 2

x = -2

f) 36 : (x^3 - 12) = -3

x^3 - 12 = 36 : (-3)

x^3 - 12 = -12

x^3 = 0

=> x = 0

g)x + 15 = 35

x = 35 - 15

x = 20

h) 2x - 13 = 3^2

2x - 13 = 9

2x = 9 + 13

2x = 22

x = 22 : 2

x = 11