1\(\dfrac{1}{3}\)x1\(\dfrac{1}{8}\)x1\(\dfrac{1}{15}\)x1\(\dfrac{1}{24}\)x1\(\dfrac{1}{35}\)
\(1\dfrac{1}{2}x1\dfrac{1}{3}x1\dfrac{1}{4}x1\dfrac{1}{5}x1\dfrac{1}{6}x1\dfrac{1}{7}x1\dfrac{1}{8}x1\dfrac{1}{9}\)
làm nhanh giúp mik mik cần gấp
\(1\dfrac{1}{2}x1\dfrac{1}{3}x1\dfrac{1}{4}x1\dfrac{1}{5}x1\dfrac{1}{6}x1\dfrac{1}{7}x1\dfrac{1}{8}x1\dfrac{1}{9}\)
\(=\dfrac{3}{2}x\dfrac{4}{3}x\dfrac{5}{4}x\dfrac{6}{5}x\dfrac{7}{6}x\dfrac{8}{7}x\dfrac{9}{8}x\dfrac{10}{9}\)
\(=x^7.\dfrac{3.4.5.6.7.8.9.10}{2.3.4.5.6.7.8.9}\)
\(=x^7.\dfrac{10}{2}\)
\(=5x^7\)
\(=\dfrac{3}{2}\times\dfrac{4}{3}\times\dfrac{5}{4}\times...\times\dfrac{9}{8}\times\dfrac{10}{9}=\dfrac{10}{2}=5\)
\(1:\left(1\dfrac{1}{2}x1\dfrac{1}{3}x1\dfrac{1}{4}......x1\dfrac{1}{99}\right)\)
`1:(1 1/2 xx 1 1/3 xx 1 1/4 xx ... xx 1 1/99 )`
`= 1 : (3/2 xx 4/3 xx 5/4 xx ... xx 100/99)`
`= 1 : 100/2`
`= 1 xx 2/100`
`= 2/100`
`=1/50`
Tính giá trị biểu thức :
C = \(1\dfrac{1}{2}x1\dfrac{1}{3}x1\dfrac{1}{4}x...x1\dfrac{1}{100}\)
\(=>C=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot\dfrac{5}{4}.....\cdot\dfrac{101}{100}\)
\(C=\dfrac{3\cdot4\cdot5.......\cdot101}{2\cdot3\cdot4.........\cdot100}\)
\(C=\dfrac{101}{2}\)
\(C=1\dfrac{1}{2}\cdot1\dfrac{1}{3}\cdot1\dfrac{1}{4}\cdot...\cdot1\dfrac{1}{100}\)
\(C=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot\dfrac{5}{4}\cdot...\cdot\dfrac{101}{100}\)
\(C=\dfrac{101}{2}\)
Bài 7: (Đề 2) Tính nhanh
\(1\dfrac{1}{2}x1\dfrac{1}{3}x1\dfrac{1}{4}x...x1\dfrac{1}{999}\)
\(...=\dfrac{3}{2}x\dfrac{4}{3}x\dfrac{5}{4}x\dfrac{6}{5}x\dfrac{7}{6}....x\dfrac{1000}{999}\)
\(=\dfrac{1}{2}x\dfrac{1000}{1}=500\)
=3/2x4/3x5/4x....x1000/999
=1/2x1000=500
mình chưa chắc là đúng đâu nhé
Tinh bang cach thuan tien:
a) \(1\dfrac{1}{2}x1\dfrac{1}{3}x1\dfrac{1}{4}\)
b) \(1\dfrac{1}{2}:1\dfrac{1}{3}:1\dfrac{1}{4}\)
a: \(1\dfrac{1}{2}\cdot1\dfrac{1}{3}\cdot1\dfrac{1}{4}\)
\(=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot\dfrac{5}{4}\)
\(=\dfrac{5}{2}\)
b: \(1\dfrac{1}{2}:1\dfrac{1}{3}:1\dfrac{1}{4}\)
\(=\dfrac{3}{2}:\dfrac{4}{3}:\dfrac{5}{4}\)
\(=\dfrac{3}{2}\cdot\dfrac{3}{4}\cdot\dfrac{4}{5}=\dfrac{9}{10}\)
Tính
1\(\dfrac{1}{12}x1\dfrac{1}{13}x1\dfrac{1}{14}\) x ... x \(1\dfrac{1}{2005}\)
1\(\dfrac{1}{12}\) \(\times\) 1\(\dfrac{1}{13}\) \(\times\) 1\(\dfrac{1}{14}\) \(\times\)...\(\times\)1\(\dfrac{1}{2005}\)
A = \(\dfrac{12+1}{12}\) \(\times\) \(\dfrac{13+1}{13}\) \(\times\) \(\dfrac{14+1}{14}\)\(\times\)...\(\times\) \(\dfrac{2006}{2005}\)
A = \(\dfrac{13}{12}\) \(\times\) \(\dfrac{14}{13}\) \(\times\) \(\dfrac{15}{14}\) \(\times\)...\(\times\) \(\dfrac{2006}{2005}\)
A = \(\dfrac{2006}{12}\)
A = \(\dfrac{1003}{6}\)
Cho \(\dfrac{x1-1}{2017}=\dfrac{x2-2}{2016}=\dfrac{x3-3}{2016}=...=\dfrac{x2017-2017}{1}\) và x1+x2+...+x2017=2017.2018
Tìm x1,x2,...,x2017?
cái chỗ x3-3/2016 phải là x3-3/2015, viết lộn
Cho x và y là hai đại lượng tỉ lệ thuận: x1, x2 là hai giá trị khác nhau của x, y1,y2 là hai giá trị tương ứng của y. Tính x1 và y1 biết y1-x1= \(\dfrac{-1}{4}\) ; x2= \(\dfrac{4}{5}\);
y2= \(\dfrac{8}{15}\)
mọi người giúp mình câu: \(\dfrac{8}{10}+\dfrac{3}{5}x1\dfrac{1}{9}:\dfrac{4}{55}\)
\(=\dfrac{4}{5}+\dfrac{2}{3}x.\dfrac{55}{4}=\dfrac{4}{5}+\dfrac{55}{6}x\)