a) \(K_2O+H_2O->2KOH\)

b) \(2Fe+3Cl_2->2FeCl_3\)

c) \(2Al\left(OH\right)_3+3H_2SO_4->Al_2\left(SO_4\right)_3+6H_2O\)

d) \(4FeS_2+11O_2->2Fe_2O_3+8SO_2\)

e)\(2Al+6HCl->2AlCl_3+3H_2\)

f) \(2KClO_3->KCl+3O_2\)

g) \(4P+5O_2->2P_2O_5\)

h) \(3Fe+2O_2->Fe_3O_4\)

i) \(2Al+3CuSO_4->Al_2\left(SO_4\right)_3+3Cu\)

j) \(2K+2H_2O->2KOH+H_2\)

a) 2Al+ 3H2SO4-> Al2(SO4)3+3H2

b) 2Fe(OH)3+ 3H2SO4-> Fe2(SO4)3+ 6H2O

a) 2 \(\rightarrow\)

b) 2 \(\rightarrow\)

$\rm u)S + 2HNO_3 \rightarrow H_2SO_4 + 2NO \uparrow$

$\rm v)3Ba(NO_3)_2 + Al_2(SO_4)_3 \rightarrow 3BaSO_4 \downarrow + 2Al(NO_3)_3$
$\rm w)3Ba(OH)_2 + P_2O_5 \rightarrow Ba_3(PO_4)_3 \downarrow + 3H_2O$
$\rm x)2Fe_2O_3 + 3C \xrightarrow{t^o} 4Fe + 3CO_2 \uparrow$

`Fe + 2HCl -> FeCl_2 + H_2`

`2Na + 2HCl -> 2NaCl + H_2`

`2Al + 6HCl -> 2AlCl_3 + 3H_2`

`2Al(OH)_3 + 3H_2SO_4 -> Al_2(SO_4)_3 + 6H_2O`

Fe + 2HCl → FeCl₂ + H₂
2Na + 2HCl → 2NaCl + H₂
2Al + 6HCl → 2AlCl₃ + 3H₂
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O

\(Fe+2HCl\rightarrow FeCl_2+H_2\)

\(2Na+2HCl\rightarrow2NaCl+H_2\)

\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)

a. 6NH3 + 5O3 --> 6NO + 9H2O

b. 2S + HNO3 -to-> 2NO + H2SO4

c. 4NO2 + O2 + 2H2O --> 4HNO3

d. FeCl3 + 3AgNO3 --> Fe(NO3)3 + 3AgCl

e. 3NO2 + H2O -to-> 2HNO3 + NO

f. 3Ba(NO3)2 + Al2(SO4)3 --> 3BaSO4 + 2Al(NO3)3

a. 6NH₃ + 5O₃ \(\rightarrow\) 6NO + 9H₂O

b. 2S + HNO₃ \(\underrightarrow{to}\) 2NO + H₂SO₄

c. 4NO₂ + O₂ + 2H₂O \(\rightarrow\) 4HNO₃

d. FeCl₃ + 3AgNO₃ \(\rightarrow\) Fe(NO₃)₃ + 3AgCl

e. 3NO₂ + H₂O \(\underrightarrow{to}\) 2HNO₃ + NO

f. 3Ba(NO₃)₂ + Al₂(SO₄)₃ \(\rightarrow\) 3BaSO₄ + 2Al(NO₃)₃

a) Al(OH)3: oxit bazơ: nhôm oxit

H2SO4: Axit: axit sunfuric

Al2(SO4)3: muối: nhôm sunfat

H2O: nước

a) Các chất trong phản ứng:

Al(OH)3 : oxit bazo: Nhôm hidroxit

H2SO4: axit : axit sunfuric

Al2(SO4)3: Muối: Nhôm sunfat

H2O: Nước

b) \(n_{Al\left(OH\right)3}=\dfrac{7,8}{78}=0,1\left(mol\right)\)

\(n_{H2SO4}=\dfrac{19,6}{98}=0,2\left(mol\right)\)

PTHH:

2Al(OH)3 + 3H2SO4 -> Al2(SO4)3 + H2O

B.đầu: 0,1________0,2_________0________0

P.ứng: 0,1_________0,15_______0,05______0,05

S.P.ứng: 0,1_________0,05________0,05_____0,05 (mol)

+) m_H2SO4(dư) = 0,05. 98 = 4,9 (gam)

+) m_Al2(SO4)3 = 0,05. 342 = 17,1 (gam)

+) m_H2O = 0,05.18 = 0,9 (gam)

lưu huỳnh oxi đồng

canxi sắt

mặt trời đồng

1+1=3

hok tốt

hello Duy

hello Duy

hello Duy

Chất thứ 2 trong sơ đồ phải là Al₂O₃ bạn nhé!

\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)

\(2Al_2O_3\underrightarrow{đpnc}4Al+3O_2\)

\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)

\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_{4\downarrow}\)

Bạn tham khảo nhé!