5^x-7-20=105
x=
Tìm x, biết:
a) \(\dfrac{3}{4}x\) - \(\dfrac{7}{12}\) = \(\dfrac{5}{6}\) - \(\dfrac{2}{3}\)
b) -\(\dfrac{5}{x}\) = \(\dfrac{20}{28}\)
c) \(2\dfrac{1}{3}\) : x = 7
d) \(\dfrac{-105}{12}\) < x < \(\dfrac{20}{7}\)
\(a,\dfrac{3}{4}x-\dfrac{7}{12}=\dfrac{5}{6}-\dfrac{2}{3}\\ \Rightarrow\dfrac{3}{4}x-\dfrac{7}{12}=\dfrac{1}{6}\\ \Rightarrow\dfrac{3}{4}x=\dfrac{1}{6}+\dfrac{7}{12}\\ \Rightarrow\dfrac{3}{4}x=\dfrac{3}{4}\\ \Rightarrow x=\dfrac{3}{4}:\dfrac{3}{4}\\ \Rightarrow x=1\\ b,\dfrac{-5}{x}=\dfrac{20}{28}\\ \Rightarrow\dfrac{-5}{x}=\dfrac{5}{7}\\ \Rightarrow\dfrac{-5}{x}=\dfrac{-5}{-7}\\ \Rightarrow x=-7\\ c,2\dfrac{1}{3}:x=7\\ \Rightarrow\dfrac{7}{3}:x=7\\ \Rightarrow x=\dfrac{7}{3}:7\\ \Rightarrow x=\dfrac{1}{3}\)
\(d,\dfrac{-105}{12}< x< \dfrac{20}{7}\Rightarrow x\in\left\{-8;-7;...;2\right\}\)
a: \(\Leftrightarrow x\cdot\dfrac{3}{4}=\dfrac{3}{4}\)
hay x=1
b: \(\Leftrightarrow x=\dfrac{-28\cdot5}{20}=-7\)
c: \(\Leftrightarrow x=\dfrac{7}{3}:7=\dfrac{1}{3}\)
d: \(\Leftrightarrow-8< x< 3\)
hay \(x\in\left\{-7;-6;-5;-4;-3;-2;-1;0;1;2\right\}\)
\(a)\dfrac{3}{4}x-\dfrac{7}{12}=\dfrac{1}{6}\\ \dfrac{3}{4}x=\dfrac{1}{6}+\dfrac{7}{12}\\ \dfrac{3}{4}x=\dfrac{2}{3}\\ x=\dfrac{2}{3}:\dfrac{3}{4}\\ x=\dfrac{8}{9}\\ b)-\dfrac{5}{x}=\dfrac{20}{28}\\ -5\cdot28=x\cdot20=-140\\ x=-140:20\\ x=-7\\ c)\dfrac{7}{3}:x=7\\ x=\dfrac{7}{3}:7\\ x=\dfrac{1}{3}\)
tìm x
x+1/3=4/5
x-1/2=2/7
4/7×x=1/3
x:2/5=2/9
20×7:(5×x-3×5)=4
x-270=420:105
x-140:35=270
Tìm x :
x + 1/3 = 4/5
x = 4/5 - 1/3
x = 12/15 - 5/15
x = 7/15
x - 1/2 = 2/7
x = 2/7 + 1/2
x = 4/14 + 7/14
x = 11/14
4/7 × x = 1/3
x = 1/3 : 4/7
x = 1/3 × 7/4
x = 7/12
x : 2/5 = 2/9
x = 2/9 × 2/5
x = 4/45
20 × 7 : ( 5 × x - 3 × 5 ) = 4
140 : 5 × ( x - 3 ) = 4
5 × ( x - 3 ) = 140 : 4
5 × ( x - 3 ) = 35
x - 3 = 35 : 5
x - 3 = 7
x = 7 + 3
x = 10
x - 270 = 420 : 105
x - 270 = 4
x = 4 + 270
x = 274
x - 140 : 35 = 270
x - 4 = 270
x = 270 + 4
x = 274
x + 1/3 = 4/5
x = 4/5 - 1/3
x = 7/15
x - 1/2 = 2/7
x = 2/7 + 1/2
x = 11/14
4/7 * x = 1/3
x = 1/3 : 4/7
x = 7/12
x : 2/5 = 2/9
x = 2/9 * 2/5
x 4 / 45
20 * 7 : ( 5*x - 3 * 5) =4
= 140 :(5*x -3 *5) =4
5*x- 3*5 = 140 : 4
5*x - 3 * 5 = 35
5* x = 35 + 3 * 5
5 * x = 50
x = 50 : 5
x = 10
x - 270 = 402 : 105
x - 270 = 4
x = 270 + 4
x = 274
x- 140 : 35 = 270
x - 4 = 270
x = 270 + 4
x = 274
Tìm x :
a, 60 - 3 ( x -2 ) = 51
b, ( 105 - x ) : 2 mũ 5 = 3 mũ 0 + 1
c, x + 5 = 20 - ( 12 - 7 )
a) \(60-3.\left(x-2\right)=51\)
\(\Rightarrow3.\left(x-2\right)=60-51=9\)
\(\Rightarrow x-2=9:3=3\)
\(\Rightarrow x=3+2=5\)
b) \(\left(105-x\right):2^5=3^{0+1}=3^1=3\)
\(\Rightarrow\left(105-x\right):32=3\)
\(\Rightarrow105-x=3.32=96\)
\(\Rightarrow x=105-96=9\)
c) \(x+5=20-\left(12-7\right)\)
\(\Rightarrow x+5=20-5\)
\(\Rightarrow x+5=15\)
\(\Rightarrow x=15-5=10\)
tính x
a) ( x - 20 )3 = - 64
b) 9 ( x + 1) - 11 ( x + 7 ) = 105 - 1
`#3107`
`a)`
`(x - 20)^3 = -64`
`\Rightarrow (x - 20)^3 = (-4)^3`
`\Rightarrow x - 20 = -4`
`\Rightarrow x = -4 + 20`
`\Rightarrow x = 16`
Vậy, `x = 16.`
`b)`
`9(x + 1) - 11(x + 7) = 105 - 1`
`\Rightarrow 9(x + 1) - 11(x + 7) = 104`
`\Rightarrow 9x + 9 - 11x - 77 = 104`
`\Rightarrow (9 - 11)x + (9 - 77) = 104`
`\Rightarrow -2x - 68 = 104`
`\Rightarrow -2x = 104 + 68`
`\Rightarrow -2x = 172`
`\Rightarrow x = 172 \div (-2)`
`\Rightarrow x = -86`
Vậy,` x = -86.`
a) Ta có ( x - 20 )3 = -64 = ( -4 )3
⇒ x - 20 = -4
⇒ x = 20 + ( -4 ) = 16
b) Ta có 9 ( x + 1 ) - 11 ( x + 7 ) = 105 - 1
⇒ 9x + 9 - 11x - 77 = 104
⇒ ( -2 ) . x - 68 = 104
⇒ ( -2 ) . x = 104 - 68 = 36
⇒ x = 36 : ( -2 ) = -18
a)
\(\left(x-20\right)^3=-64\)
\(\left(x-20\right)^3=-4^3\)
\(\Rightarrow x-20=-4\)
\(\Rightarrow x=-4+20=16\)
b)
\(9\left(x+1\right)-11\left(x+7\right)=105-1\)
\(9\left(x+1\right)-11\left(x+1+6\right)=104\)
\(9\left(x+1\right)-11\left(x+1\right)+66=104\)
\(\left(x+1\right).\left(9-11\right)=104-66\)
\(\left(x+1\right).\left(-2\right)=38\)
\(x+1=38:\left(-2\right)\)
\(x+1=-19\)
\(x=-19-1\)
\(x=-20\)
x -56 : 4= 16
101 +(36 –4x) =105
2(x-51) = 2.23+ 20
10 -(x –3): 2 = 72–110
2x –49 = 5.32
[(8x -12) : 4].33= 36
52x –3–2 . 52= 52. 3
(x3–7) : 4 = 5
a: x-56:4=16
nên x-14=16
hay x=30
b: \(101+\left(36-4x\right)=105\)
\(\Leftrightarrow36-4x=4\)
hay x=8
Vì a: x-56:4=16
=>x-14=16
Hay:x=30
Vì b: 101+(36−4x)=105101+(36−4x)=105
⇔36−4x=4⇔36−4x=4
Hay:x=8
Vậy x={30:8}
Nếu sai thì thui nhá,đừng chửi mình!
Tìm các số nguyên x, biết :
a, -65 - (x+15) + 105 = 0
b, |-6| + (-9) - (x+1) = 7
c, |5-x| + (-25 + 7) = -3 - (-10)
d, 28 - |x+6| + (-2) = 0
e, x - (13 - 15) = 5 + (10 - x) - (-1)
f, -120 - (x - 5) = 125
g, 10 - (-5 + 2) + (-9) = (-20 + 7) - x
Mình cần gấp ngay tối nay ( ghi đầy đủ các bước )
a) \(-65-\left(x+15\right)+105=0\)
\(-65-\left(x+15\right)=-105\)
\(x+15=-65-\left(-105\right)\)
\(x+15=40\)
\(x=25\)
b) |-6| + (-9) - (x+1) = 7
-3- (x+1) =7
x+1 = -10
x = -11
c)\(\left|5-x\right|+\left(-25+7\right)=-3-\left(-10\right)\)
\(\left|5-x\right|+\left(-18\right)=7\)
\(\left|5-x\right|=25\)
\(\Rightarrow\orbr{\begin{cases}5-x=25\\5-x=-25\end{cases}\Rightarrow\orbr{\begin{cases}x=-20\\x=30\end{cases}}}\)
d) \(28-\left|x+6\right|+\left(-2\right)=0\)
\(28-\left|x+6\right|=2\)
\(\left|x+6\right|=26\)
\(\Rightarrow\orbr{\begin{cases}x+6=26\\x+6=-26\end{cases}\Rightarrow\orbr{\begin{cases}x=20\\x=-32\end{cases}}}\)
e) \(x-\left(13-15\right)=5+\left(10-x\right)-\left(-1\right)\)
\(x+2=5+10-x+1\)
\(x+2=16-x\)
\(x+x=16-2\)
\(2x=14\)
\(x=7\)
f) \(-120-\left(x-5\right)=125\)
\(x-5=-120-125\)
\(x-5=-245\)
\(x=-240\)
g) \(10-\left(-5+2\right)+\left(-9\right)=\left(-20+7\right)-x\)
\(-16=-13-x\)
\(x=-13+16\)
\(x=3\)
Giải các phương trình:
a) \(\dfrac{x+2001}{5}+\dfrac{x+1999}{7}+\dfrac{x+1997}{9}+\dfrac{x+1995}{11}=-4;\)
b) \(\dfrac{x-15}{100}+\dfrac{x-10}{105}+\dfrac{x-100}{110}=\dfrac{x-100}{15}+\dfrac{x-105}{10}+\dfrac{x-110}{5}.\)
a: \(\Leftrightarrow\left(\dfrac{x+2001}{5}+1\right)+\left(\dfrac{x+1999}{7}+1\right)+\left(\dfrac{x+1997}{9}+1\right)+\left(\dfrac{x+1995}{11}+1\right)=0\)
=>x+2006=0
=>x=-2006
b: \(\Leftrightarrow\left(\dfrac{x-15}{100}-1\right)+\left(\dfrac{x-10}{105}-1\right)+\left(\dfrac{x-100}{5}-1\right)=\left(\dfrac{x-100}{15}-1\right)+\left(\dfrac{x-105}{10}-1\right)+\left(\dfrac{x-110}{5}-1\right)\)
=>x-105=0
=>x=105
tìm X biết :
a.2/3 : 5/7 : x/9 = 2/7 : 3/5 :10/9
b.3/5 : 7/x : 3/4 = 12/105
c.x : 1/2 = 2/3 x 4/5 x 3/4 x 15/8
a, \(\frac{2}{3}:\frac{5}{7}:\frac{x}{9}=\frac{2}{7}:\frac{3}{5}:\frac{10}{9}\Leftrightarrow\frac{2\times7\times9}{3\times5\times x}=\frac{2\times5\times9}{7\times3\times10}\Leftrightarrow\frac{42}{5\times x}=\frac{3}{7}\Leftrightarrow294=15\times x\Leftrightarrow x=19,6\)
Các phần sau tương tự.
Dùng phương pháp nhân chéo và kiểm tra trình độ tính toán, khả năng rút gọn.
Thay kết quả vào x để kiểm tra lại bài.
a)
160 : (4 x 8)
160 : 4 : 8
Thực hiện các phép tính sau
a)96 : (3 x 8)
96 : 3 : 8
105 : (5 x 7)
105 : 5 : 7
b)
270 : (9 x 6)
420 : (7 x 3)
144 : (2 x 8)
a)
160 : (4 × 8) = 160 : 32 = 5
160 : 4 : 8 = 40 : 8 = 5
Vậy 160 : (4 × 8) = 160 : 4 : 8.
96 : (3 × 8) = 96 : 24 = 4
96 : 3 : 8 = 32 : 8 = 4
Vậy 96 : (3 × 8) = 96 : 3 : 8.
105 : (5 × 7) = 105 : 35 = 3
105 : 5 : 7 = 21 : 7 = 3
Vậy 105 : (5 × 7) = 105 : 5 : 7.
Nhận xét: a : (b × c) = a : b : c
b)
270 : (9 × 6) = 270 : 9 : 6 = 30 : 6 = 5
420 : (7 × 3) = 420 : 7 : 3 = 60 : 3 = 20
144 : (2 × 8) = 144 : 2 : 8 = 72 : 8 = 9